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Practice Questions with Solutions: Perimeter and Area

Q1: Length of a rectangular park is 3 times its breadth. If the length of the park is 90 metres, then find the area of the park.
Ans: Length of rectangular park = 90 m.
So, breadth = 90 m ÷ 3 = 30 m.
Area of the rectangle = length × breadth
= 90 m × 30 m = 2700 m2.

Q2: Find the area of a rectangular piece of cardboard measuring 1 m long and 25 cm broad.
Ans: Length is in metres, but the breadth is in cm. So, we change the length to cm.
1 m = 100 cm, so length = 100 cm.
Area = length × breadth
= 100 cm × 25 cm = 2500 cm2.

Q3: Find the area of a square with a side of 7 cm.
Ans: Area of a square = side × side
= 7 cm × 7 cm = 49 cm2.

Q4: Find the Perimeter (P) and the Area (A) of the Given Figures. Assume Each Side of the Unit Square is 2 Cm

Practice Questions with Solutions: Perimeter and Area

Ans: Each small square has a side = 2 cm.
Perimeter is the length of the continuous outer boundary of the figure.

Practice Questions with Solutions: Perimeter and Area

Perimeter of the given figure is found by adding the lengths of all outer edges.
As shown in the figure, the outer edges add up to (2 + 2 + 2 + 2) + (2 + 2 + 2) + 2 + 2 + (2 + 2) + 2 + 2 + 2 = 28 cm.
∴ Perimeter of the given figure = 28 cm.
Now for area;
Area of one small square = side × side = 2 cm × 2 cm = 4 cm2.

Practice Questions with Solutions: Perimeter and Area

There are 8 such small squares in the figure.
Area of the figure = area of one square × number of squares = 4 cm2 × 8 = 32 cm2.

Q5: Find the Perimeter of and the area of the figure below:
Side = 30Practice Questions with Solutions: Perimeter and AreaAns:
A square has all four sides equal. Here, each side = 30 cm.
Perimeter of square = 30 + 30 + 30 + 30 = 120 cm.
Area of square = side × side = 30 cm × 30 cm = 900 cm2.

Q6: Find the Perimeter and Area of the rectangle below 
Length = 4m 20cm and Breadth = 2m and 50cm
Ans:
First convert length and breadth to the same unit (use cm).
1 m = 100 cm.
Length = 4 m 20 cm = (4 × 100) cm + 20 cm = 400 cm + 20 cm = 420 cm.
Breadth = 2 m 50 cm = (2 × 100) cm + 50 cm = 200 cm + 50 cm = 250 cm.
Perimeter of rectangle = 2 × (length + breadth)
= 2 × (420 cm + 250 cm) = 2 × 670 cm = 1340 cm.
Area of rectangle = length × breadth = 420 cm × 250 cm = 105000 cm2.

Q7: Neha and Rekha Draw a Circle of the Same Size in Their Books
If the length and breadth of Neha՚s Book is 60 cm and 40 cm, and the length and Breadth of Rekha՚s Book is 70 Cm and 30 Cm, Find Whose Book Have More Circle?
Ans:
Area of Neha's book = 60 cm × 40 cm = 2400 cm2(length × breadth)
Area of Rekha's book = 70 cm × 30 cm = 2100 cm2(length × breadth)
Since 2400 cm2 > 2100 cm2, Neha's book has the larger area. If both draw circles of the same size, Neha's book can fit more such circles than Rekha's book.

Q8: An Open Cinema Ground is 240 Meter Long and 190 meters in Breadth
Find the area of land acquired by Open Cinema.
Ans:
Length of an open cinema ground is 240 meters and breadth is 190 meters.
Means it's a rectangular shape.
Now for the perimeter of the rectangle;
Area of open cinema ground = length × breadth
∴ Area of open cinema ground = 240 × 190
∴ Area of open cinema ground = 45600 m2
Therefore, the area of the Open cinema ground is 45600 m2.

Q9: Answer the Following Questions. (Every Room is a Square or a Rectangle)

Practice Questions with Solutions: Perimeter and Area

(i) Look at the house design and find the area of the bathroom.
Ans:
The bathroom is a rectangle with length 11 and breadth 3 (units as given).
Area = length × breadth = 11 × 3 = 33 (units)2.

(ii)  Look at the house design and find the area of the kitchen.
Ans: The kitchen is a rectangle with length 24 and breadth 4 (units as given).
Area = length × breadth = 24 × 4 = 96 (units)2.

Q10: Find the length of the rectangular school playground of 4800 square meters and 60 m in breadth.
Ans:
Area = length × breadth.
4800 m2 = length × 60 m.
Length = 4800 m2 ÷ 60 m = 80 m.
Therefore, the length of the playground is 80 m.

The document Practice Questions with Solutions: Perimeter and Area is a part of the Class 4 Course Mathematics for Class 4.
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FAQs on Practice Questions with Solutions: Perimeter and Area

1. What is the formula for calculating the perimeter of a rectangle?
Ans. The formula for calculating the perimeter of a rectangle is P = 2 × (length + width), where P represents the perimeter, length is one side of the rectangle, and width is the adjacent side.
2. How can we find the area of a square?
Ans. The area of a square can be found using the formula A = side × side, or A = side², where A represents the area and 'side' is the length of one side of the square.
3. What is the difference between perimeter and area?
Ans. The perimeter is the total distance around the outside of a shape, while the area measures the amount of space inside that shape. Perimeter is expressed in linear units, whereas area is expressed in square units.
4. How do you calculate the area of a triangle?
Ans. The area of a triangle can be calculated using the formula A = ½ × base × height, where A represents the area, 'base' is the length of the triangle's base, and 'height' is the perpendicular height from the base to the opposite vertex.
5. Why is it important to understand perimeter and area in real life?
Ans. Understanding perimeter and area is important in real life for various reasons, such as determining the amount of material needed for fencing a yard (perimeter) or calculating the space required for flooring in a room (area). This knowledge helps in planning and making informed decisions in everyday situations.
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