Class 4 Exam  >  Class 4 Notes  >  Mathematics for Class 4  >  Word Problem: Division - 2

Word Problem: Division - 2 | Mathematics for Class 4 PDF Download

Q1: A truck was carrying 340 chairs, staked in sets of 5 chairs each. How many stacks of chairs were there on the truck? 

Ans: Total number of chairs = 340
Chairs per stack = 5
The number of Stacks is given by,Word Problem: Division - 2 | Mathematics for Class 4

Word Problem: Division - 2 | Mathematics for Class 4

Q2: How many hours are there in 1200 minutes?  

Ans: To convert minutes to hours, you can use the fact that there are 60 minutes in an hour.

Number of hours = Word Problem: Division - 2 | Mathematics for Class 4

Number of hours=Number of minutes number of hoursNumber of hours = (1200 / 60)
Word Problem: Division - 2 | Mathematics for Class 4Therefore, there are 20 hours in 1200 minutes.

Q3: The total train fare for 20 persons is 7540 rupees. What is the fare for 1 person?

Ans: The total train fare = 7540 rupees
Number of persons = 20
Train fare for 1 person = 7540 ÷ 20
Word Problem: Division - 2 | Mathematics for Class 4

Q4: In your classes, you counted 120 hands. How many students were in the class? 

Ans: Total number of hands = 120
Number of hands each person has = 2
To find how many students were in the class, we divide the total number of hands by 2.
We get, 120 ÷ 2 = 60
Therefore, there were 60 students in the class.
Word Problem: Division - 2 | Mathematics for Class 4

Q5: A team of 7 construction workers worked together to build 3 sheds in 10 days.How much of a shed did each of them build?

Ans: To find how much of a shed each construction worker built, we can use the concept of "worker-days."
Since 7 workers worked for 10 days to build 3 sheds, the total worker-days can be calculated as:
Total worker-days = Number of workers * Number of days = 7 workers * 10 days = 70 worker-days

Now, since they built 3 sheds in total, each shed required:
Worker-days per shed = Total worker-days / Number of sheds = 70 worker-days / 3 sheds ≈ 23.33 worker-days per shed
Word Problem: Division - 2 | Mathematics for Class 4

This means that, on average, each shed required approximately 23.33 worker-days to be built.
Now, to find out how much of a shed each construction worker built, we divide this value by the number of workers:
Shed built by each worker = Worker-days per shed / Number of workers ≈ 23.33 worker-days per shed / 7 workers ≈ 3.33 worker-days per worker

Therefore, on average, each construction worker built about 3.33 worker-days' worth of a shed during the 10-day construction period.

Word Problem: Division - 2 | Mathematics for Class 4Therefore, each worker built approximately 3 sheds.

Q6: 126 pieces of cookies were equally distributed by Bella among 24 children. How many pieces of cookies did Bella distribute among children if she left with 6 pieces of cookies at the end? 

Ans: Total number of cookies = 126
Number of cookies left at the end = 6
Number of cookies consumed = 126 - 6 = 120
Hence number of cookies received by each child = 120 / 24
Word Problem: Division - 2 | Mathematics for Class 4

Q7: 1360 parcel were delivered in 20 days by a courier company. If the company delivered an equal number of packages on all days, how many packages were delivered each day? 

Ans: Total number of packages delivered = 1360
Number of days = 20
Packages delivered per day = 1360/20
Word Problem: Division - 2 | Mathematics for Class 4

Q8: A factory produced 9,864 widgets in a day. If they need to pack the widgets into boxes, and each box can hold 48 widgets, how many boxes will be filled completely, and how many widgets will be left over? 

Ans:  Total number of widgets produced in 1 day = 9864
Number of boxes = 48
Number of widgets in each box = 9864 / 48

Word Problem: Division - 2 | Mathematics for Class 4Therefore, 205 boxes will be filled completely and 24 widgets will be left remaining.

Q9: Sam is building a fence around his rectangular garden. If the perimeter of the garden is 1,398 meters, and one side is 132 meters long, what is the length of the other side? 

Ans: We know, the perimeter of a rectangle = 2 x (length + breadth)
Length of one side of the park = 132
Let the length of the other side be y
Therefore, 1398 = 2 x (132 + y)
Word Problem: Division - 2 | Mathematics for Class 4=> 1398 = 264 + 2y

Word Problem: Division - 2 | Mathematics for Class 4=> 1134 = 2y
Hence y = 1134/2
=>  1398 = 264 x y
=>  y = 1398 / 264
Word Problem: Division - 2 | Mathematics for Class 4

Q10: A computer server has 8,497 gigabytes of data that needs to be transferred to external hard drives. If each external hard drive can hold 365 gigabytes, how many hard drives will be filled completely, and how much data will be left to transfer? 

Ans: Total amount of data = 8497
Amount of data one drive can hold = 365
Word Problem: Division - 2 | Mathematics for Class 4The server will completely fill 23 external hard drives with 365 gigabytes each, and there will be 102 gigabytes of data left over that can't completely fill another hard drive. 

The document Word Problem: Division - 2 | Mathematics for Class 4 is a part of the Class 4 Course Mathematics for Class 4.
All you need of Class 4 at this link: Class 4
33 videos|167 docs|30 tests

FAQs on Word Problem: Division - 2 - Mathematics for Class 4

1. What is the basic concept of division in mathematics?
Ans. Division is a mathematical operation that involves splitting a number (the dividend) into equal parts. It answers the question of how many times one number (the divisor) can fit into another number. For example, in the division problem 20 ÷ 4, 20 is the dividend, 4 is the divisor, and the answer is 5, meaning 4 can fit into 20 five times.
2. How do you solve a division problem step by step?
Ans. To solve a division problem, follow these steps: 1. Identify the dividend and the divisor. 2. Determine how many times the divisor can fit into the dividend. 3. Write down the result (the quotient). 4. If there is a remainder, note it down. For example, in 23 ÷ 5, the divisor 5 fits into 23 four times (4), leaving a remainder of 3, so the answer is 4 R3.
3. What are some real-life applications of division?
Ans. Division has many real-life applications, such as sharing food among friends, calculating the cost per item when shopping, splitting a bill at a restaurant, or determining how many groups can be formed from a larger collection. For instance, if you have 12 cookies and want to share them equally among 4 friends, you would divide 12 by 4, resulting in 3 cookies per friend.
4. What is the difference between division with remainders and without remainders?
Ans. Division with remainders occurs when the dividend cannot be evenly divided by the divisor, leaving a leftover amount (remainder). For example, 10 ÷ 3 equals 3 R1, meaning 3 fits into 10 three times with 1 remaining. Division without remainders means the dividend is evenly divisible by the divisor, such as 12 ÷ 4 = 3, with no leftover.
5. How can I practice division to improve my skills?
Ans. To practice division, you can use worksheets, online quizzes, or math apps that focus on division problems. Start with simple problems and gradually increase the difficulty. You can also practice division through word problems and real-life scenarios to enhance your understanding and application of the concept. Regular practice will help improve your speed and accuracy in division.
Related Searches

Word Problem: Division - 2 | Mathematics for Class 4

,

Viva Questions

,

mock tests for examination

,

Exam

,

pdf

,

study material

,

shortcuts and tricks

,

Sample Paper

,

Extra Questions

,

Semester Notes

,

Word Problem: Division - 2 | Mathematics for Class 4

,

video lectures

,

Free

,

Summary

,

MCQs

,

Previous Year Questions with Solutions

,

past year papers

,

Objective type Questions

,

ppt

,

practice quizzes

,

Important questions

,

Word Problem: Division - 2 | Mathematics for Class 4

;