Triangles Class 10 Notes Maths Chapter 6

Introduction

Similar Figures

• Two geometrical figures are said to be similar figures if they have the same shape but not necessarily the same size.
  Or
  A shape is said to be similar to other if the ratio of their corresponding sides is equal and the corresponding angles are equal.
• Two polygons having the same number of sides are similar, if:
  (i) all the corresponding angles are equal and
  (ii) all the corresponding sides are in the same ratio or proportion.
  If only one condition from (i) and (ii) is true for two polygons, then they cannot be similar.

Similarity of Triangles

Two triangles are said to be similar triangles if:

• Their corresponding angles are equal and 
• their corresponding sides are proportional (i.e., the ratios between the lengths of corresponding sides are equal).  

For example:
If in ∆ABC and ∆PQR
∠A = ∠P, ∠B = ∠Q, ∠C = ∠R and,
AB/PQ = BC/QR = AC/PR
Then, △ABC∼△PQR
where the symbol ∼ is read as ‘is similar to’.
Conversely
If △ABC is similar to △PQR, then
∠A = ∠P, ∠B = ∠Q, ∠C = ∠R and,
AB/PQ = BC/QR = AC/PR

Note: The ratio of any two corresponding sides in two equiangular triangles is always the same.

Theorem 1 ( Thales theorem)

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then other two sides are divided in the same ratio.
This theorem is known as the Basic Proportionality Theorem (BPT) or Thales theorem.

Given: 

To Proof:

Proof:

Now, 

Now,

Theorem 2 ( Converse of Thales theorem)

If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.

Given: In ΔABC, DE is a straight line such that

To prove DE || BC.

Construction: If DE is not parallel to BC, draw DF meeting AC at F.

Proof: In ΔABC, let DF || BC

[∴ A line drawn parallel to one side of a Δ divides the other two sides in the same ratio.]

⇒ FC = EC.

It is possible only when E and F coincide

Hence, DE || BC.

Example 1:  If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, 

prove that

Solution: 

 If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.

Criteria For Similarity of Triangles

1. AAA Similarity

Theorem 3 : If in two triangles, if corresponding angles are equal, then their corresponding sides are in the same ratio i.e., they are proportional, and hence the two triangles are similar.

This criterion is referred to as the AAA (Angle–Angle–Angle) criterion of similarity of two triangles.

2. AA Similarity

If ∠A=∠C and ∠B=∠D then △ABC∼△DEF

Example: In theΔABC length of the sides are given as AP = 5 cm , PB = 10 cm and BC = 20 cm. Also PQ||BC. Find PQ.

Solution: In ΔABC and ΔAPQ, ∠PAQ is common and ∠APQ = ∠ABC (corresponding angles)

⇒ ΔABC ~ ΔAPQ (AA criterion for similar triangles)

⇒ AP/AB = PQ/BC

⇒ 5/15 = PQ/20

⇒ PQ = 20/3 cm

3.  SSS similarity

If in two triangles, sides of one triangle are proportional to (i.e., in the same ratio of ) the sides of the other triangle, then their corresponding angles are equal and hence the two triangles are similiar

This criterion is referred to as the SSS (Side–Side–Side) similarity criterion for two triangles.

Using Theorem: if a line divides two sides of a triangle in the same ratio, then the line is parallel to the third side. This theorem is often referred to as the Basic Proportionality Theorem or Thales' Theorem.

Example: Two triangles ABC and DEF are similar such that AB = 8cm, BC = 10cm, CA =y cm, DE = 6 cm, EF = x cm and FD = 9 cm . Find the Values of x and y?

Solution:  As △ABC∼△DEF  then  AB/DE=AC/DF=BC/EF

So now putting values 8/6=y/9=10/x

8/6=y/9   and 8/6=10/x

4/3=y/9 and 4/3=10/x

4*9=y*3 and 4*x=10*3 (Cross multiplying)

so y comes out to be =12

and x=7.5

4.    SAS Similarity

This criterion is referred to as the SAS (Side–Angle–Side) similarity criterion for two triangles.

If AB/ED=BC/EF and ∠B=∠E Then △ABC∼△DEF

Example: Determine if the following triangles are similar. If so, write the similarity criteria

Solution:

We can see that ∠B≅∠F∠B=∠F and these are both included angles. We just have to check that the sides around the angles are proportional.

ABDFBCFE=128=32=2416=32BC/FE=24/16=3/2  and AB/DF=12/8=3/2

Since the ratios are the same ΔABC∼ΔDFEΔABC∼ΔDFE by the SAS Similarity Theorem.

• Similar Figures: Figures with the same shape, regardless of size, are termed similar figures.
• Congruence vs. Similarity: While all congruent figures are similar, the reverse is not necessarily true.
• Conditions for Similar Polygons: Two polygons with the same number of sides are similar if their corresponding angles are equal, and their corresponding sides are in proportion.
• Parallel Lines and Triangle Side Division: Drawing a line parallel to one side of a triangle divides the other two sides in the same ratio.
• Converse of Triangle Side Division: If a line divides any two sides of a triangle in the same ratio, it is parallel to the third side.
• AAA Similarity Criterion: If corresponding angles in two triangles are equal, their corresponding sides are in the same ratio, and the triangles are similar.
• AA Similarity Criterion: If two angles in one triangle are respectively equal to two angles in another triangle, the triangles are similar.
• SSS Similarity Criterion: If corresponding sides in two triangles are in the same ratio, their corresponding angles are equal, leading to similarity.
• SAS Similarity Criterion: If one angle of a triangle is equal to one angle of another triangle, and the sides including these angles are in proportion, the triangles are similar.