Averages Questions for CAT with Answers PDF

Required average = (3 + 5 + 7 + 11 + 13 + 17 + 19
+ 23 + 29 + 31)/10 = 158/10 = 15.8.

D’s weight = 4 x 70 – 3 x 74 = 280 – 222 = 58.
E’s weight = 58 + 3 = 61.
Now, we know that A + B + C + D = 4 x 70 = 280
and B + C + D + E = 75 x 4 = 300. Hence, A’s
weight is 20 kg less than E ’s weight. A = 61 - 20
= 41 kg.

Required average = (0 + 1 + 2 + … + 9)/10 = 45/10
= 4.5

The sum of the first n odd numbers = n². In this case n = 10 → Sum = 10² = 100.
Required average = 100/10 = 10.

Required average = (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18)/10 = 112/10 = 11.2.

P = 14 x 10 – 13 x 8 = 140 –104 = 36

Monday + Tuesday + Wednesday = 3 x 35 = 105;
Tuesday + Wednesday + Thursday = 3 x 30 = 90.
Thus, Monday – Thursday = 15 and
Thursday = Monday/2 → Monday = 30 and Thursday = 15

4x + 40 = 5(x + 4) → x = 20 (average after 4 innings).

Hence, new average = 20 + 4 = 24.

1/5 + 1/8 + C = 3 x 1/10 → C = –1/40.

Average income over 9 months = [3 x (2250 + 500) + 3 x (2150 + 500) + 3 x (5750+500)]/9 = 3883.33

If the average age of 5 persons has gone up by 10 years it means the total age has gone up by 50 years.

Thus the total age of the two women would be: 30 + 40 + 50 = 120. Hence, their average age = 60 years.

Total present age of A, B and C = 25 x 3 + 15 = 75 + 15 = 90.

Total present age of B and C = 20 x 2 + 20 = 60.

A ’s age = 90 – 60 = 30.

(5+10+15+20+25+30)/6 = 105/6 = 17.5

His total score is 90 + 70 + 150 = 310 out of 450.

This works out to a percentage score of = 68.88%

Total age (at present) = 5 ¥ 20 = 100 years. Total age of the family excluding the youngest member (for the remaining 5 people) = 100 –5 = 95. Average age
of the other 4 people in the family = 95/4 years.

5 years ago their average age = 95/4 – 5 = 75/4 = 18.75 years.

W + T + F = 60; T + F + S = 63 → S – W = 3.

Hence temperature on Wednesday = 22 – 3 = 19.

Teacher’s weight = 21 x 20 – 20 x 19 = 420– 380 = 40.

The weight of the new man would be 29 x 5 kgs more than the weight of the man he replaces. New man’s weight = 120 + 29 x 5 = 265 kgs.

The average would be given by the average of the first and last numbers (since the series 1, 2, 3, 4…100 is an Arithmetic Progression).

Hence, the average = (1 + 100)/2 = 50.50