Mixed Graphs Questions for CAT with Answers PDF

In 1995 - 96 = 25/100 = 1/4
In 1996 - 97 = 25/75 = 1/3
In 1998 - 99 = 25/100 = 1/4
In 1999 - 2000 = 50/150 = 1/3
From the results, the advertising expenditure of S as a percentage of advertising expenditure of P and R together was least in 1995 - 96 and 1998 - 99.

Sale of the products P, Q, R and S in 2000 - 01 are Rs. 200, Rs. 500, Rs. 100 and Rs. 200 crores, respectively.
Profit of Q = 500 - 50 = Rs. 450 crores
Profit of S = 200 - 25 = Rs. 175 crores
∴ Required percentage

= 4 × (5.55)%
= 38.89%

Total number of articles sold by stores P and Q from August to October = 250 + 350 + 350 + 240 + 275 + 380 = 1845
Total number of articles sold by store R from August to October = 280 + 270 + 350 = 900
Required percent = (945 × 100)/900 = 105%

Profit of all three stores in the month of September = 270 × 350 + 240 × 278 + 270 × 328
= 94,500 + 66,720 + 88,560 = Rs. 2,49,780
Profit of stores Q and R in October = 278 × 380 + 350 × 328
= 1,05,640 + 1,14,800 = Rs. 2,20,440
Difference = 2,49,780 - 2,20,440 = Rs. 29,340

e-Votes received by BJP in Lucknow

e- Votes received by BJP in Noida 

Required ratio = 175 : 100 = 7 : 4

e-Votes cast to BJP in Kanpur and Varanasi

e-Votes cast to SP in Kanpur and Varanasi

Required ratio = 17 : 14

Total number illiterate people in AP and MP = ((7/9) × 27% + (4/5) × 21%) × 32,76,000 = (21 + 16.8) × 32,760 = 12,38,328

Ingredient P used in 500 g of type A and 600 g of type B food products = (500 × 5/20) g + (600 × 3/20) g = (125 + 90) g = 215 g
Ingredient Q used in 500 g of type A and 600 g of type B food products = (500 × 4/20) g + (600 × 4/20) g = 220 g
Ingredient R used in 500 g of type A and 600 g of type B food products = (500 × 6/20) g + (600 × 8/20) g = 390 g
Ingredient S used in 500 g of type A and 600 g of type B food products = (500 × 5/20) g + (600 × 5/20) g = 275 g
Total cost = Rs. (30 + 215 × 8 + 220 × 5 + 390 × 4 + 275 × 7) = Rs. 6335

Ingredient P used in 600 g food products of type B and 1200 g food of type C = (3 × 600/20 + 5 × 1200/30) g = 290 g
Ingredient Q used in 600 g food products of type B and 1200 g food of type C = (4 × 600/20 + 9 × 1200/30) g = 480 g
Ingredient R used in 600 g food products of type B and 1200 g food of type C = (8 × 600/20 + 7 × 1200/30) g = 520 g
Ingredient S used in 600 g food products of type B and 1200 g food of type C = (5 × 600/20 + 9 × 1200/30) g = 510 g
Total cost = Rs. (290 × 8 + 480 × 5 + 520 × 4 + 510 × 7) = Rs. 10370
Thus, answer option 2 is correct.