CBSE Class 8  >  Class 8 Notes  >  Mathematics (Maths)   >  Important Formulas: Linear Equations in One Variable

Important Formulas: Linear Equations in One Variable

Algebraic Equation

An algebraic equation is an equality that contains one or more variables. It states that the value of the expression on the left of the equality sign is equal to the value of the expression on the right for some value(s) of the variable(s).

  • Expressions: \(5x\), \(2x - 3\), \(x^2 + 1\), \(y + y^2\), etc.
  • Equations: \(5x = 25\), \(2x - 3 = 9\), \(6z + 10 = -2\), etc.
Algebraic Equation

What is a Linear Equation in One Variable

  • A linear equation in one variable is an equation in which the highest power of the variable is 1.
  • Such an equation usually has the variable appearing only to the first power and not multiplied by itself or another variable.
  • Typical examples of linear expressions: \(2x\), \(3y - 7\), \(12 - 5z\).

Non-linear expressions

  • Expressions in which the variable has powers greater than 1 or where variables are multiplied together are not linear. Examples: \(x^2 + 1\), \(y^3 + y\).
Non-linear expressions

Important points to Note

  • Every equation contains the equality sign (=).
  • The expression on the left of the equality sign is called the Left Hand Side (LHS).
  • The expression on the right of the equality sign is called the Right Hand Side (RHS).
  • The values of the variable that make the LHS and RHS equal are called the solutions of the equation.
  • When solving an equation we perform the same mathematical operations on both sides so the equality remains true (we keep the two sides balanced).
  • A linear equation in one variable usually has exactly one solution, but special cases may occur:
    • If both sides reduce to the same identity (for example \(0 = 0\)), there are infinitely many solutions.
    • If both sides reduce to a contradiction (for example \(0 = 5\)), there is no solution.

How to solve Linear Equations in One Variable

General strategies used while solving linear equations are: collect like terms, transpose terms from one side to the other (change side), and divide or multiply to isolate the variable. The sign of a term changes when it is transposed across the equality sign. The following methods cover common cases.

Solving equations with linear expressions on one side and numbers on the other

  • Transpose numbers so that all variable terms appear on one side and numerical terms on the other side.
  • Perform addition or subtraction on both sides to combine like terms.
  • Divide or multiply on both sides to get the variable alone and thus find its value.

Example: Solve \(2x - 3 = 7\)

Sol.\(2x - 3 = 7\)
\(2x = 7 + 3\)
\(2x = 10\)
\(x = \dfrac{10}{2}\)
\(x = 5\)

Solving equations having the variable on both sides

  • Transpose variable terms so that variable terms are on one side and constants on the other side.
  • Add or subtract to combine like terms.
  • Divide or multiply to isolate the variable and obtain its value.

Example: Solve \(3x - 4 = 2x + 6\)

Sol. \(3x - 4 = 2x + 6\)
\(3x - 2x = 6 + 4\)
\(x = 10\)

Solving equations with variables in denominators (remove denominators first)

  • Find the LCM of denominators present on both sides.
  • Multiply both sides of the equation by this LCM to remove denominators and obtain an equation without fractions.
  • Solve the resulting linear equation by the methods above.

Example: Solve \(\dfrac{4x + 5}{2} + 2 = \dfrac{x - 2}{4}\)

Sol. \(\dfrac{4x + 5}{2} + 2 = \dfrac{x - 2}{4}\)
LCM of denominators \(2\) and \(4\) is \(4\).
Multiply both sides by \(4\):
\(4\cdot\dfrac{4x + 5}{2} + 4\cdot 2 = 4\cdot\dfrac{x - 2}{4}\)
\(2(4x + 5) + 8 = x - 2\)
\(8x + 10 + 8 = x - 2\)
\(8x + 18 = x - 2\)
\(8x - x = -2 - 18\)
\(7x = -20\)
\(x = \dfrac{-20}{7}\)

MULTIPLE CHOICE QUESTION

Try yourself: What is a linear equation in one variable?

A

An equation that 2 involves variables and numbers.

B

An equation that involves only one variable and a constant term.

C

An equation that contains multiple variables and no constant terms.

D

An equation that involves variables and exponents.

Equations reducible to linear form

  • Equations in which both sides are rational expressions whose numerators are linear expressions and denominators are constants can be reduced to a linear equation by cross-multiplying.
  • After cross-multiplication, expand and collect like terms to get a linear equation of the form \((x + a)d = c(x + b)\) and solve as above.

Example: Solve \(\dfrac{2x - 4}{7} = \dfrac{x + 6}{4}\)

Sol. \(\dfrac{2x - 4}{7} = \dfrac{x + 6}{4}\)
Cross-multiply:
\(4(2x - 4) = 7(x + 6)\)
\(8x - 16 = 7x + 42\)
\(8x - 7x = 42 + 16\)
\(x = 58\)

Short summary

A linear equation in one variable is an equality where the variable has power one. To solve such equations: collect like terms, transpose terms while keeping the balance (perform same operation on both sides), remove denominators if any by multiplying with the LCM, and finally divide or multiply to isolate the variable. Check special cases where an equation may have no solution or infinitely many solutions.

The document Important Formulas: Linear Equations in One Variable is a part of the Class 8 Course Mathematics (Maths) Class 8.
All you need of Class 8 at this link: Class 8

FAQs on Important Formulas: Linear Equations in One Variable

1. What are the basic formulas I need to know for solving linear equations in one variable for Class 8 CBSE?
Ans. Linear equations in one variable follow the principle that whatever operation is performed on one side must be done on the other. The fundamental formula is: if ax + b = c, then x = (c - b)/a. Essential operations include transposition (moving terms across the equals sign while changing signs), balancing both sides, and isolating the variable. Students should master combining like terms and applying inverse operations systematically to find the solution.
2. How do I know which formula to use when solving linear equations with fractions and decimals?
Ans. When fractions appear in linear equations, multiply the entire equation by the least common multiple (LCM) of all denominators to eliminate fractional coefficients. For decimals, multiply by 10, 100, or 1000 depending on decimal places. After clearing fractions or decimals, apply standard transposition formulas and inverse operations. This method simplifies the equation into whole numbers, making calculation easier and reducing arithmetic errors significantly.
3. What's the difference between solving linear equations using transposition versus balancing method?
Ans. Both methods reach identical solutions but differ in approach. The transposition method shifts terms across the equals sign while reversing their signs-faster for experienced learners. The balancing method performs identical operations on both sides simultaneously, maintaining equation equilibrium. Balancing reinforces the principle that equations represent equal quantities, while transposition is more efficient for quick problem-solving. Class 8 students typically learn both but increasingly rely on transposition as confidence builds.
4. Why do my answers sometimes not satisfy the original linear equation even though I followed the formula correctly?
Ans. Verification is essential-substitute your solution back into the original equation to confirm both sides equal. Common errors include sign mistakes during transposition, miscalculating when clearing fractions, or arithmetic errors while combining like terms. These mistakes produce incorrect solutions that seem "correct" until verified. Always check by replacing the variable with your answer; if both sides don't equal, retrace your steps through each formula application and arithmetic operation.
5. What formulas do I need to remember for solving word problems that involve linear equations in one variable?
Ans. Word problems require translating language into algebraic expressions using the same fundamental formulas as numerical equations. Identify the unknown (assign variable), form the equation from given conditions, then solve using transposition or balancing methods. Key formulas remain identical: ax + b = c format and inverse operations. The additional skill is careful reading and accurate equation formation, not new mathematical formulas-the solving process itself follows standard Class 8 linear equation principles.
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