CBSE Class 8  >  Class 8 Notes  >  Mathematics (Maths)   >  Important Formulas: Exponents & Powers

Important Formulas: Exponents & Powers

Base is the number (or algebraic expression) that is multiplied repeatedly. Exponent (or power) is the small number written above and to the right of the base which shows how many times the base is used as a factor.

If a is a non-zero number and n is a positive integer then an means a multiplied by itself n times.

Examples:

  • 23 = 2 × 2 × 2 = 8
  • 51 = 5
  • a4 = a × a × a × a

Laws of Exponents

  • \(a^{m} \times a^{n} = a^{m+n}\)

    When multiplying two powers with the same base, add the exponents. Valid for any integers \(m,n\) and for any base \(a\).

  • \(\dfrac{a^{m}}{a^{n}} = a^{m-n}\)

    When dividing powers with the same base, subtract the exponents. Valid for \( a \neq 0 \).

  • \((a^{m})^{n} = a^{mn}\)

    When a power is raised to another power, multiply the exponents.

  • \((ab)^{m} = a^{m} b^{m}\)

    The power of a product equals the product of the powers. Valid for any integers \(m\).

  • \(\left(\dfrac{a}{b}\right)^{m} = \dfrac{a^{m}}{b^{m}}\)

    The power of a quotient equals the quotient of the powers. Valid for \( b \neq 0 \).

  • \(a^{-m} = \dfrac{1}{a^{m}}\)

    A negative exponent denotes reciprocal of the positive exponent. Valid for \( a \neq 0 \).

  • \(a^{0} = 1\)

    Any non-zero number raised to the zero power equals 1.

  • \(\left(\dfrac{a}{b}\right)^{-m} = \left(\dfrac{b}{a}\right)^{m}\)

    Negative exponent on a fraction swaps numerator and denominator, then applies the positive exponent. Valid for \( a \neq 0 \) and \( b \neq 0 \).

  • \(1^{n} = 1\)

    One raised to any integer power is 1.

  • \((-1)^{p} = 1\)

    When \(p\) is an even integer, \((-1)^{p} = 1\). When \(p\) is an odd integer, \((-1)^{p} = -1\).

Laws of Exponents

Additional Remarks 

  • Zero base: For positive integer \(n\), 0n = 0.
  • Undefined form:00 is indeterminate/undefined in elementary arithmetic and should be avoided.
  • Negative exponents require non-zero base: Expressions like 0-1 are not defined.
  • Fractional exponents: These represent roots (for example, \(a^{1/2}=\sqrt{a}\)). This extends the laws but is treated under rational exponents (covered in higher classes).

Reasoning and Short Proofs

Product rule:

\(a^{m} = \underbrace{a \times a \times \cdots \times a}_{m\ \text{times}}\)

\(a^{n} = \underbrace{a \times a \times \cdots \times a}_{n\ \text{times}}\)

Multiplying these gives \(a^{m} \times a^{n} = \underbrace{a \times \cdots \times a}_{m+n\ \text{times}} = a^{m+n}\).

Quotient rule:

\(a^{m} = \underbrace{a \times \cdots \times a}_{m\ \text{times}}\)

\(a^{n} = \underbrace{a \times \cdots \times a}_{n\ \text{times}}\)

Dividing \(a^{m}\) by \(a^{n}\) cancels common factors and leaves \(a^{m-n}\) when \(m \ge n\).

Power of a power:

\((a^{m})^{n} = \underbrace{a^{m} \times a^{m} \times \cdots \times a^{m}}_{n\ \text{times}}\)

Each \(a^{m}\) contributes \(m\) factors of \(a\); total factors \(= mn\). Thus \((a^{m})^{n}=a^{mn}.\)

Negative exponent:

\(a^{m} \times a^{-m} = a^{m-m} = a^{0} = 1\)

Hence \(a^{-m} = 1/a^{m}\) for \( a \neq 0 \).

Zero exponent:

From the quotient rule with \(m=n\): \(\dfrac{a^{m}}{a^{m}} = a^{m-m} = a^{0}\).

But \(\dfrac{a^{m}}{a^{m}} = 1\) when \( a \neq 0 \). Thus \(a^{0} = 1\) for \( a \neq 0 \) and  \( m = 0 \).

Solved Examples

Example 1. Simplify \(a^{3} \times a^{4}\).

Sol: Use the product rule.

\(a^{3} \times a^{4} = a^{3+4}\)

\(= a^{7}\)

Example 2. Simplify \(2^{3} \times 2^{-5}\).

Sol: Apply the product rule (add exponents).

\(2^{3} \times 2^{-5} = 2^{3+(-5)}\)

\(= 2^{-2}\)

\(= \dfrac{1}{2^{2}}\)

\(= \dfrac{1}{4}\)

Example 3. Simplify \((3^{2})^{4}\).

Sol: Use power of a power (multiply exponents).

\((3^{2})^{4} = 3^{2\times 4}\)

\(= 3^{8}\)

Example 4. Simplify \((2\times 3)^{2}\).

Sol: Use power of a product.

\((2\times 3)^{2} = 2^{2} \times 3^{2}\)

\(= 4 \times 9\)

\(= 36\)

Example 5. Simplify \(\left(\dfrac{5}{2}\right)^{-3}\).

Sol: Apply the negative exponent rule to the fraction.

\(\left(\dfrac{5}{2}\right)^{-3} = \left(\dfrac{2}{5}\right)^{3}\)

\(= \dfrac{2^{3}}{5^{3}}\)

\(= \dfrac{8}{125}\)

Practice Questions

  • Simplify \(x^{5} \times x^{-2}\).
  • Simplify \(\dfrac{7^{4}}{7^{2}}\).
  • Simplify \((xy)^{3}\).
  • Simplify \(\left(\dfrac{4}{3}\right)^{2} \times \left(\dfrac{3}{4}\right)^{-1}\).
  • Evaluate \((-1)^{6}\) and \((-1)^{7}\).
The document Important Formulas: Exponents & Powers is a part of the Class 8 Course Mathematics (Maths) Class 8.
All you need of Class 8 at this link: Class 8

FAQs on Important Formulas: Exponents & Powers

1. What's the difference between a base and an exponent in powers?
Ans. The base is the number being multiplied, while the exponent (or power) tells you how many times to multiply it. For example, in 2³, 2 is the base and 3 is the exponent, meaning 2 × 2 × 2. Understanding this distinction is fundamental to mastering exponent rules and solving problems efficiently in Class 8 mathematics.
2. How do I simplify expressions using the product rule for exponents?
Ans. When multiplying powers with the same base, add the exponents together. The formula is: aᵐ × aⁿ = aᵐ⁺ⁿ. For instance, x² × x⁵ = x⁷. This product rule is one of the most essential exponent laws tested in CBSE Class 8 and makes calculations faster than expanding everything manually.
3. Why does any number to the power zero always equal 1?
Ans. Any non-zero number raised to the power zero equals 1 because of how exponent division works. Using the quotient rule, aᵐ ÷ aᵐ = aᵐ⁻ᵐ = a⁰, which must equal 1 since any number divided by itself is 1. This principle applies universally and appears frequently in Class 8 exponent problems.
4. What's the correct way to handle negative exponents in calculations?
Ans. Negative exponents represent reciprocals: a⁻ⁿ = 1/aⁿ. So 2⁻³ equals 1/2³ or 1/8. Instead of dealing with negatives directly, convert to fractions using this rule. This concept often confuses students but mastering negative exponents is crucial for CBSE mathematics and higher-level problems involving powers.
5. How do quotient and power rules differ when solving exponent problems?
Ans. The quotient rule divides powers with identical bases by subtracting exponents: aᵐ ÷ aⁿ = aᵐ⁻ⁿ. The power rule raises an exponent to another exponent by multiplying: (aᵐ)ⁿ = aᵐˣⁿ. Both are distinct exponent formulas essential for Class 8, and confusing them leads to calculation errors during exam preparation.
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