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Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry PDF Download

Q.1. Derive an expression for the rate constant for a first order reaction.

Rate constant of a first order reaction: The reaction in which, the overall rate of the reaction is proportional to the first power of concentration of one of the reactants only are called first order reaction.
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
where k1 is the rate constant of the first order reaction.

At the beginning of the reaction, time f = 0, let the concentration of A be 'a' mole lit-1. After the reaction has proceeded for some time't', let the concentration of A that has reacted be x mole lit-1. The concentration of unreacted A remaining at time't' will be (a - x) mole lit-1. The rate of the reaction will be dx/dt. For a first order reaction,
rate = dx/dt = k1 (a - x ) ..... (i)
Integrating (1), both sides
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Which is -In (a - x) = k1t + c .....(2)
C = integration constant,
at time, t = 0, x = 0
In equation (2)
-ln (a -0 ) = k1 x 0 + c
or
c = ln a
Substituting c value in equation (2)
-ln (a -x ) = k1t- In a
rearranging,
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry 
Unit of k1 is sec -1
This equation is known as the first order rate constant equation.


Q.2. The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

Decay constant k= Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry

The rate of counts is proportional to the number of C-14 atoms in the sample.

N0 =100, N=80
The age of the sample t = Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry


Q.3. The unit of rate constant for zero order reaction is:
(a) s−1
(b) mol L−1 s−1
(c) L mol−1 s−1
(d) L2 mol−2s−1

Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry


Q.4. The rate for the decomposition of NH3 on platinum surface is zero order. What are the rate of production of N2 and H2 if K= 2.5 x 10-4 mol litre-1s-1.

2NH3 →N2 +3H2
Rate of reaction = Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
For a zero order reaction
Rate = k = 2.5 x 10-4 M/s
Rate of production of N=Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Rate of production of H=Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry


Q.5. Show that in a first order reaction, time required for completion of 99.9% is 10 times of half-life (t1/2) of the reaction.

For first order reaction,
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Given that:
x = 99.9 a for t99.9%
x = 0.5 a for t50%
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
⇒ t99.9% = 10 × t50%
Hence proved.


Q.6. The rate constant of the reaction A→B is 0.6×10−3  moleL−1 s−1 . If the concentration of A is 5 M, then concentration of B after 20 minutes is:
(a) 0.36 M
(b) 0.72M
(c) 1.08M
(d) 3.60M

Correct option is Option (b)

The rate constant has unit mole per second which indicates zero order reaction.

x = kt

The concentration of B after 20 minutes is 20 x 60 x 0.6 x 10-3 = 0.72M


Q.7. For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

For a first order reaction, we have
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry

Let a M be the initial concentration.
When reaction is 99% complete,
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
When reaction is 90% complete,
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry

Divide equation (1) by (2), we get
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry


Q.8. A first order reaction takes 40 min for 30% decomposition. Calculate t1/2.

Let a M be the initial concentration. After 40 minutes, the concentration is a
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry

The half life period,Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry


Q.9. The rate constant for a first order reaction is 60 s−1 . How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?

Given that the rate constant for a first order reaction is 60 s −1 .
Let a M be the initial concentration.
Final concentration will beSolved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Rate constant, k=60/s
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
t=4.6 × 10 −2  seconds


Q.10. A first order reaction has a rate constant 1.15×10 −3 s −1 . How long will 5 g of this reactant take to reduce to 3 g?
(a) 444 s
(b) 400 s
(c) 528 s
(d) 669 s

Correct Answer is option (a)
Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry
= 2.00 × 103 log(1.667)

= 2 × 103 × 0.2219 = 444 s.

The document Solved Numericals on Zero, First, Second and Third Order reactions | Physical Chemistry is a part of the Chemistry Course Physical Chemistry.
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FAQs on Solved Numericals on Zero, First, Second and Third Order reactions - Physical Chemistry

1. What is a zero order reaction?
Ans. A zero order reaction is a chemical reaction where the rate of reaction is independent of the concentration of the reactants. In other words, the rate of reaction remains constant throughout the reaction, regardless of the changes in reactant concentration.
2. How can the rate constant of a first order reaction be determined?
Ans. The rate constant of a first order reaction can be determined by plotting a graph of the natural logarithm of reactant concentration against time. The slope of this graph will give the rate constant, which can then be used to calculate the rate of reaction at any given time.
3. What are the characteristics of a second order reaction?
Ans. A second order reaction is a chemical reaction where the rate of reaction is directly proportional to the product of the concentrations of two reactants or the square of the concentration of a single reactant. The rate constant of a second order reaction has units of M^-1s^-1.
4. How does the rate of a third order reaction change with respect to reactant concentration?
Ans. In a third order reaction, the rate of reaction is directly proportional to the product of the concentrations of three reactants or the cube of the concentration of a single reactant. As the concentration of reactants increases, the rate of reaction increases exponentially.
5. Can a reaction have a fractional order?
Ans. Yes, a reaction can have a fractional order. Fractional order reactions occur when the rate of reaction is not an integer or a whole number. The rate equation for such reactions involves fractional powers of the reactant concentrations. Fractional order reactions are relatively rare and are often observed in complex chemical systems.
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