Introduction
Probability defines the likelihood of occurrence of an event. There are many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur. Probability generally has great applications in games, in business to make probability-based predictions, and also probability has extensive applications in this new area of artificial intelligence. The probability of an event can be calculated by probability formula by simply dividing the favorable number of outcomes by the total number of possible outcomes. The value of the probability of an event to happen can lie between 0 and 1 because the favorable number of outcomes can never cross the total number of outcomes. Also, the favorable number of outcomes cannot be negative.
What is Probability?
Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favorable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.
Probability(Event) = Favorable Outcomes/Total Outcomes = x/n
Simple application of probability to understand it better. Suppose we have to predict about the happening of rain or not. The answer to this question is either "Yes" or "No". There is a likelihood to rain or not rain. Here we can apply probability. Probability is used to predict the outcomes for the tossing of coins, rolling of dice, or drawing a card from a pack of playing cards.
The probability is classified into theoretical probability and experimental probability.
Terminology of Probability Theory
The following terms in probability help in a better understanding of the concepts of probability.
- Experiment: A trial or an operation conducted to produce an outcome is called an experiment.
- Sample Space: All the possible outcomes of an experiment together constitute a sample space. For example, the sample space of tossing a coin is head and tail.
- Favorable Outcome: An event that has produced the desired result or expected event is called a favorable outcome. For example, when we roll two dice, the possible/favorable outcomes of getting the sum of numbers on the two dice as 4 are (1,3), (2,2), and (3,1).
- Trial: A trial denotes doing a random experiment.
- Random Experiment: An experiment that has a well-defined set of outcomes is called a random experiment. For example, when we toss a coin, we know that we would get ahead or tail, but we are not sure which one will appear.
- Event: The total number of outcomes of a random experiment is called an event.
- Equally Likely Events: Events that have the same chances or probability of occurring are called equally likely events. The outcome of one event is independent of the other. For example, when we toss a coin, there are equal chances of getting a head or a tail.
- Exhaustive Events: When the set of all outcomes of an experiment is equal to the sample space, we call it an exhaustive event.
- Mutually Exclusive Events: Events that cannot happen simultaneously are called mutually exclusive events. For example, the climate can be either hot or cold. We cannot experience the same weather simultaneously.
Probability Formula
The probability formula defines the likelihood of the happening of an event. It is the ratio of favorable outcomes to the total favorable outcomes. The probability formula can be expressed as,
where,
- P(B) is the probability of an event 'B'.
- n(B) is the number of favorable outcomes of an event 'B'.
- n(S) is the total number of events occurring in a sample space.
Different Probability Formulas
- Probability formula with addition rule: Whenever an event is the union of two other events, say A and B, then
P(A or B) = P(A) + P(B) - P(A∩B)
P(A ∪ B) = P(A) + P(B) - P(A∩B) - Probability formula with the complementary rule: Whenever an event is the complement of another event, specifically, if A is an event, then P(not A) = 1 - P(A) or P(A') = 1 - P(A).
P(A) + P(A′) = 1. - Probability formula with the conditional rule: When event A is already known to have occurred and the probability of event B is desired, then P(B, given A) = P(A and B), P(A, given B). It can be vice versa in the case of event B.
P(B∣A) = P(A∩B)/P(A) - Probability formula with multiplication rule: Whenever an event is the intersection of two other events, that is, events A and B need to occur simultaneously. Then P(A and B) = P(A)⋅P(B).
P(A∩B) = P(A)⋅P(B∣A)
Example: Find the probability of getting a number less than 5 when a dice is rolled by using the probability formula.
Solution: To find:
Probability of getting a number less than 5
Given: Sample space = {1,2,3,4,5,6}
Getting a number less than 5 = {1,2,3,4}
Therefore, n(S) = 6
n(A) = 4
Using Probability Formula,
P(A) = (n(A))/(n(s))
p(A) = 4/6
m = 2/3
Question for Probability
Try yourself:A fair six-sided dice is rolled. What is the probability of rolling an even number?
Explanation
Given: Sample space = {1, 2, 3, 4, 5, 6}
Let event A be rolling an even number. Event A = {2, 4, 6}
Number of outcomes in event A, n(A) = 3
Total number of outcomes in the sample space, n(S) = 6
Using the probability formula, P(A) = n(A) / n(S) = 3/6 = 1/2
Correct answer: b) 1/2
Report a problem
Probability Tree Diagram
A tree diagram in probability is a visual representation that helps in finding the possible outcomes or the probability of any event occurring or not occurring. The tree diagram for the toss of a coin given below helps in understanding the possible outcomes when a coin is tossed and thus in finding the probability of getting a head or tail when a coin is tossed.
Types of Probability
There can be different perspectives or types of probabilities based on the nature of the outcome or the approach followed while finding the probability of an event happening. The four types of probabilities are,
- Classical Probability:
- Classical probability, often referred to as the "priori" or "theoretical probability", states that in an experiment where there are B equally likely outcomes, and event X has exactly A of these outcomes, then the probability of X is A/B, or P(X) = A/B.
For example, when a fair die is rolled, there are six possible outcomes that are equally likely. That means, there is a 1/6 probability of rolling each number on the die.
- Empirical Probability:
- The empirical probability or the experimental perspective evaluates probability through thought experiments. For example, if a weighted die is rolled, such that we don't know which side has the weight, then we can get an idea for the probability of each outcome by rolling the die number of times and calculating the proportion of times the die gives that outcome and thus find the probability of that outcome.
- Subjective Probability:
- Subjective probability considers an individual's own belief of an event occurring. For example, the probability of a particular team winning a football match on a fan's opinion is more dependent upon their own belief and feeling and not on a formal mathematical calculation.
- Axiomatic Probability:
- In axiomatic probability, a set of rules or axioms by Kolmogorov are applied to all the types. The chances of occurrence or non-occurrence of any event can be quantified by the applications of these axioms, given as,
- The smallest possible probability is zero, and the largest is one.
- An event that is certain has a probability equal to one.
- Any two mutually exclusive events cannot occur simultaneously, while the union of events says only one of them can occur.
Finding the Probability of an Event
In an experiment, the probability of an event is the possibility of that event occurring. The probability of any event is a value between (and including) "0" and "1".
Events in Probability
In probability theory, an event is a set of outcomes of an experiment or a subset of the sample space.
If P(E) represents the probability of an event E, then, we have,
- P(E) = 0 if and only if E is an impossible event.
- P(E) = 1 if and only if E is a certain event.
- 0 ≤ P(E) ≤ 1.
Suppose, we are given two events, "A" and "B", then the probability of event A, P(A) > P(B) if and only if event "A" is more likely to occur than the event "B". Sample space(S) is the set of all of the possible outcomes of an experiment and n(S) represents the number of outcomes in the sample space.
P(E) = n(E)/n(S)
P(E’) = (n(S) - n(E))/n(S) = 1 - (n(E)/n(S))
E’ represents that the event will not occur.
Therefore, now we can also conclude that, P(E) + P(E’) = 1
Coin Toss Probability
The probability of tossing a coin. Quite often in games like cricket, for making a decision as to who would bowl or bat first, we sometimes use the tossing of a coin and decide based on the outcome of the toss. Let us check as to how we can use the concept of probability in the tossing of a single coin. Further, we shall also look into the tossing of two and three coming respectively.
Tossing a Coin
A single coin on tossing has two outcomes, a head, and a tail. The concept of probability which is the ratio of favorable outcomes to the total number of outcomes can be used to find the probability of getting the head and the probability of getting a tail.
Total number of possible outcomes = 2; Sample Space = {H, T}; H: Head, T: Tail
- P(H) = Number of heads/Total outcomes = 1/2
- P(T)= Number of Tails/ Total outcomes = 1/2
Tossing Two Coins
In the process of tossing two coins, we have a total of four outcomes. The probability formula can be used to find the probability of two heads, one head, no head, and a similar probability can be calculated for the number of tails. The probability calculations for the two heads are as follows.
Total number of outcomes = 4; Sample Space = {(H, H), (H, T), (T, H), (T, T)}
- P(2H) = P(0 T) = Number of outcome with two heads/Total Outcomes = 1/4
- P(1H) = P(1T) = Number of outcomes with only one head/Total Outcomes = 2/4 = 1/2
- P(0H) = (2T) = Number of outcome with two heads/Total Outcomes = 1/4
Tossing Three Coins
The number of total outcomes on tossing three coins simultaneously is equal to 2^{3} = 8. For these outcomes, we can find the probability of getting one head, two heads, three heads, and no head. A similar probability can also be calculated for the number of tails.
Total number of outcomes = 2^{3} = 8 Sample Space = {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (T, T, H), (T, H, T), (H, T, T), (T, T, T)}
- P(0H) = P(3T) = Number of outcomes with no heads/Total Outcomes = 1/8
- P(1H) = P(2T) = Number of Outcomes with one head/Total Outcomes = 3/8
- P(2H) = P(1T) = Number of outcomes with two heads /Total Outcomes = 3/8
- P(3H) = P(0T) = Number of outcomes with three heads/Total Outcomes = 1/8
Question for Probability
Try yourself:You are tossing three fair coins simultaneously. What is the probability of getting exactly two tails?
Explanation
To find the probability of getting exactly two tails when tossing three coins, we need to identify the outcomes that fulfill this condition and then calculate the probability.
Total number of outcomes when tossing three coins simultaneously = 2^3 = 8
Sample Space = {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (T, T, H), (T, H, T), (H, T, T), (T, T, T)}
Outcomes with exactly two tails = {(H, T, T), (T, T, H), (T, H, T)}
Number of outcomes with exactly two tails = 3
Probability of getting exactly two tails = Number of outcomes with exactly two tails / Total outcomes
Probability = 3/8
Therefore, the correct answer is:
B) 3/8
Report a problem
Dice Roll Probability
Many games use dice to decide the moves of players across the games. A dice has six possible outcomes and the outcomes of a dice is a game of chance and can be obtained by using the concepts of probability. Some games also use two dice, and there are numerous probabilities that can be calculated for outcomes using two dice. Let us now check the outcomes, their probabilities for one dice and two dice respectively.
Rolling One Dice
The total number of outcomes on rolling a die is 6, and the sample space is {1, 2, 3, 4, 5, 6}. Here we shall compute the following few probabilities to help in better understanding the concept of probability on rolling one dice.
- P(Even Number) = Number of even number outcomes/Total Outcomes = 3/6 = 1/2
- P(Odd Number) = Number of odd number outcomes/Total Outcomes = 3/6 = 1/2
- P(Prime Number) = Number of prime number outcomes/Total Outcomes = 3/6 = 1/2
Rolling Two Dice
The total number of outcomes on rolling two dice is 6^{2} = 36. The following image shows the sample space of 36 outcomes on rolling two dice.
Sample Space for Tossing Two Coins
Let us check a few probabilities of the outcomes from two dice. The probabilities are as follows.
- Probability of getting a doublet(Same number) = 6/36 = 1/6
- Probability of getting a number 3 on at least one dice = 11/36
- Probability of getting a sum of 7 = 6/36 = 1/6
As we see, when we roll a single die, there are 6 possibilities. When we roll two dice, there are 36 possibilities. When we roll 3 dice we get 216 possibilities. So a general formula to represent the number of outcomes on rolling 'n' dice is 6^{n}.
Probability of Drawing Cards
A deck containing 52 cards is grouped into four suits of clubs, diamonds, hearts, and spades. Each of the clubs, diamonds, hearts, and spades have 13 cards each, which sum up to 52. Now let us discuss the probability of drawing cards from a pack. The symbols on the cards are shown below. Spades and clubs are black cards. Hearts and diamonds are red cards.
Sample Space of Playing Cards
The 13 cards in each suit are ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king. In these, the jack, the queen, and the king are called face cards. We can understand the card probability from the following examples.
- The probability of drawing a black card is P(Black card) = 26/52 = 1/2
- The probability of drawing a hearts card is P(Hearts) = 13/52 = 1/4
- The probability of drawing a face card is P(Face card) = 12/52 = 3/13
- The probability of drawing a card numbered 4 is P(4) = 4/52 = 1/13
- The probability of drawing a red card numbered 4 is P(4 Red) = 2/52 = 1/26
Probability Theorems
The following theorems of probability are helpful to understand the applications of probability and also perform the numerous calculations involving probability.
- Theorem 1: The sum of the probability of happening of an event and not happening of an event is equal to 1. P(A)+P(¯A)=1P(A)+P(A¯)=1
- Theorem 2: The probability of an impossible event or the probability of an event not happening is always equal to 0. P(ϕ)=0P(ϕ)=0
- Theorem 3: The probability of a sure event is always equal to 1. P(A) = 1
- Theorem 4: The probability of happening of any event always lies between 0 and 1. 0 < P(A) < 1
- Theorem 5: If there are two events A and B, we can apply the formula of the union of two sets and we can derive the formula for the probability of happening of event A or event B as follows.
P(A∪B)=P(A)+P(B)−P(A∩B)P
Also for two mutually exclusive events A and B, we have P( A U B) = P(A) + P(B)
Bayes' Theorem on Conditional Probability
- Bayes' theorem describes the probability of an event based on the condition of occurrence of other events. It is also called conditional probability. It helps in calculating the probability of happening of one event based on the condition of happening of another event.
- For example, let us assume that there are three bags with each bag containing some blue, green, and yellow balls. What is the probability of picking a yellow ball from the third bag? Since there are blue and green colored balls also, we can arrive at the probability based on these conditions also. Such a probability is called conditional probability.
The formula for Bayes' theorem is - where, P(A|B) denotes how often event A happens on a condition that B happens.
- where, P (B|A) denotes how often event B happens on a condition that A happens.
- P(A) the likelihood of occurrence of event A.
- P(B) the likelihood of occurrence of event B.
Solved Example on Probability
Example: In a bag, there are 6 blue balls and 8 yellow balls. One ball is selected randomly from the bag. Find the probability of getting a blue ball.
Solution: Let us assume the probability of drawing a blue ball to be P(B)
Number of favorable outcomes to get a blue ball = 6
Total number of balls in the bag = 14
P(B) = Number of favorable outcomes/Total number of outcomes = 6/14 = 3/7