Average (A) is the ratio between sum (S) of the quantities and the number (N) of quantities. ∴ A = S/N ⇒ S = A × N
Formula
Average
The average of n-consecutive even integers or n-consecutive odd integers is equal to the middle number if n is odd.
The average of n-consecutive even integers or n-consecutive odd integers is equal to the Average of middle two numbers if n is even. Note: In the above case if the average is x the middle two numbers will be (x - 1) and (x + 1) respectively.
The average of a group of n-quantities is A. If one more quantity whose value is x is added to the group such that the average increases by 'i' then x = A + i × (n + 1) Note: In the above case if there is a reduction in the average then take 'i' as negative.
The average of a group of n-quantities is A. If a quantity whose value is y is replaced by another quantity whose value is x such that the average increases by 'i'. Then x = y +i×n Note 1: If there is a reduction in average take 'i' as negative. Note 2: The original average 'A' has no effect on the equation.
The average weight of a group of n-quantities is A but while taking the values one quantity 'p' is erroneously read as 'q'. Then the actual average =
The average of first n-positive integers
The average of first n-positive even integers = n + 1
The average of first n-positive odd integers = n
The average of squares of first n-numbers
Percentage
If any number is divided by 100 then it is called a percentage. It is denoted by radical sign%. ⇒ x% = x/100 ∴ To get the fractional or decimal equivalent to a percentage divide the given number with 100.
If a number is increased by x% then the value after increase is given by New Value (N.V) = (100 + x)% × Original Value (O.V)
If a number is successfully increased by x%, y% and z% respectively, then the final value is given by Final Value (F.V) = (100 + x) % × (100 + y) % × (100 + z) % × Initial Value (I.V)
If a number is decreased or reduced by x% the value after reduction is given by New Value (N.V) = (100 - x) % × Original Value (O.V)
If a number is successively decreased by x%, y% and z% respectively then the final value (F.V) is given by Final Value (F.V) = (100 - x) % × (100 - y) % × (100 - z) % × Initial Value (I.V)
If there are two different values (one is greater and the other is smaller) then the greater value is more than the smaller one in terms of percentage is given by
In the above case the smaller one less than the greater one in terms of the percentage is given by
Tips
To quickly calculate average of a list of items try to guess where the average is likely to lie. For e.g. for the list 34, 45, 67, 43, 78 the average is likely to be around 50. It does not matter what number you choose as long as it is easy to calculate the difference of the numbers with the given number.
Then calculate the sum of the differentials around this assumed average.
In this case the differentials are 34-50, 45-50, 67-50, 43-50, 78-50 i.e. -16, -5, 17, -7, 28. Thus the sum of the differentials= 17. The point here is that the different differentials cancel each other out and we get a sum close to zero.
Then divide the sum of differentials by n and add it to the assumed average to get the real average.
Hence, real average = 50 + 17/5 = 50 + 3.4 = 53.4.
So if we have to calculate the average of 103, 102, 96, 99, 120 we can quickly calculate it as 100 + 20/5 = 104.
Solved Example
MULTIPLE CHOICE QUESTION
Try yourself: The average weight of 39 Students in a class is 23. Among them Sita is the heaviest while Tina is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Sita to Tina is 15:8.Then what is the weight of the Tina?
A
15
B
16
C
18
D
19
E
Cannot be determined
Correct Answer: B
Total weight of the 39 students = 39 × 23 = 897.
If Sita (weight S) and Tina (weight T) are removed, the remaining 37 students still average 23, so their total weight = 37 × 23 = 851.
Therefore S + T = 897 – 851 = 46.
We’re also given S : T = 15 : 8. Write S = 15k and T = 8k. Then S + T = 15k + 8k = 23k = 46 ⇒ k = 2.
Hence Tina’s weight T = 8k = 8×2 = 16.
Report a problem
MULTIPLE CHOICE QUESTION
Try yourself: The ages of Four members of a family are in the year 2010 are ‘X’,’X+12’,’X+24’ and ‘X+36’. After some years Oldest among them was dead then average reduced by 3. After how many years from his death, the average age will same as in 2010?
A
2 Years
B
3 Years
C
4 years
D
6 Years
E
Cannot be determined
Correct Answer: B
Average Age in 2010:
The ages are X, X + 12, X + 24, X + 36.
Sum = 4X + 72.
Average = (4X + 72) / 4 = X + 18.
Oldest Member’s Death:
The oldest member (X + 36) dies k years from 2010.
At the time of death (year 2010 + k), the remaining members’ ages are: (X + k), (X + 12 + k), (X + 24 + k).
Sum = 3X + 3k + 36.
Average = (3X + 3k + 36) / 3 = X + k + 12.
This average is reduced by 3 compared to 2010: (X + k + 12) = (X + 18) - 3 X + k + 12 = X + 15 k = 3
The oldest member dies in 2013.
Time to Restore Original Average:
Let m be the years after 2013. The remaining members’ ages in 2013 + m are: (X + 3 + m), (X + 15 + m), (X + 27 + m).
Sum = 3X + 45 + 3m.
Average = (3X + 45 + 3m) / 3 = X + 15 + m.
Set this equal to the original average (X + 18): X + 15 + m = X + 18 m = 3
Conclusion: The average age returns to the 2010 level 3 years after the death
Report a problem
MULTIPLE CHOICE QUESTION
Try yourself: The average of Four numbers is 24.5. of the four numbers, the first is 1.5 times the second, the second is 1/3 rd of the third, and the third is 2 times the fourth number. Then what is smallest of all those numbers?
A
12
B
13
C
14
D
15
E
16
Correct Answer: C
Answer – 3. 14 Explanation: First = 1.5x Second = x Third = 3x Fourth = 1.5x average = 24.5 = (1.5x+x+3x+1.5x)/4 x = 14
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