Classification (often seen as "odd one out") is a reasoning task that asks you to group items by a shared property and then identify the item that does not share that property. In such questions you are given a set of words, numbers, letter groups, pairs or images; all but one share a clear relationship or category. Your objective is to detect that relationship quickly and select the item that breaks the pattern.
These questions test observation, vocabulary, general knowledge, pattern recognition, logical analysis and elimination skills. They are common in logical reasoning (LR) sections of government and banking exam papers where speed with accuracy is important.
Classification questions appear in a variety of forms. The common types are listed below with a short explanation of each.
Use the following practical steps and strategies when you practise or face classification questions in an exam.
Example 1: Choose the pair of words which are different from others in the group.
(a) Length : Extend
(b) Duration : Period
(c) Time : Span
(d) Expanse : Stretch
Ans: (d)
Solution:
(a) Length : Extension → related but not exact synonyms (extension is the act/result of extending length)
(b) Duration : Period → clear synonyms
(c) Time : Span → clear synonyms
(d) Expanse : Stretch → close synonyms (both refer to a wide/extended area)
Options (b), (c), and (d) show direct synonym relationships. Option (a) shows a derivative/related concept, not a true synonym.
Example 2: In the following question, find the odd one from the given alternatives.
(a) Linen
(b) Cotton
(c) Iron
(d) Silk
Ans: (c)
Solution:
Linen, Cotton and Silk are materials used for making clothes (textile fibres). Iron is a metal and not a textile material. Therefore Iron is the odd one out.
Example 3: In the following question, find the odd one from the given alternatives.
(a) Netherlands
(b) Brunei
(d) Croatia
(e) Serbia
Ans: (b)
Solution:
The Netherlands, Croatia and Serbia are countries in Europe. Brunei is in Southeast Asia. Therefore Brunei is the odd one out.
Example 4: In the following question, find the odd one from the given alternatives.
(a) Electrician
(b) Paediatrician
(c) Oncologist
(d) Cardiologist
Ans: (a)
Solution:
Paediatrician, Oncologist and Cardiologist are medical doctors (specialists). Electrician is a technical trade profession, not a medical specialty. Hence Electrician is the odd one out.
Example 5: Select the odd number pair from the given alternatives.
(a) 13, 169
(b) 17, 269
(c) 14, 196
(d) 16, 256
Ans: (b)
Solution:
Examine whether the second number is the square of the first number in each pair.
13, 169 →
\(13^2 = 169\)
17, 269 →
\(17^2 = 289\)
269 ≠ 289
14, 196 →
\(14^2 = 196\)
16, 256 →
\(16^2 = 256\)
Therefore (b) is the odd pair because its second number is not the square of the first.
Example 6: Choose the word which is least like the other words in the group.
(a) Tiger
(b) Lion
(c) Leopard
(d) Cow
Ans: (d)
Solution: Tiger, Lion and Leopard are carnivorous predators (big cats). Cow is herbivorous. Hence Cow is the odd one out.
Example 7: Choose the odd pair.
(a) Volume : Liter
(b) Time : Second
(c) Length : Meter
(d) Pressure : Barometer
Ans: (d)
Solution: In (a), (b) and (c) the second term is a unit of measurement for the first term (liter measures volume; second measures time; meter measures length). A barometer is an instrument used to measure pressure, not a unit. Therefore (d) is different.
Example 8: Choose the number which is different from others in the group.
(a) 13
(b) 17
(c) 23
(d) 27
Ans: (d)
Solution: 13, 17 and 23 are prime numbers. 27 is composite (27 = 3 × 3 × 3). Therefore 27 is the odd number.
Example 9: Choose the number pair which is different from others in the group
(a) 14 - 7
(b) 24 - 3
(c) 37 - 5
(d) 42 - 2
Ans: (c)
Solution:
Check if the first number is a multiple of the second number in each pair.
14 is a multiple of 7.
24 is a multiple of 3.
37 is not a multiple of 5.
42 is a multiple of 2.
Therefore (c) is the odd pair.
Example 10: Choose the letter pair which is different from others in the group.
(a) BD
(b) IK
(c) PN
(d) SU
Ans: (c)
Solution:
Observe the alphabetic gaps.
BD → B to D is +2 (B → C → D) so these are alternate letters in forward order.
IK → I to K is +2, forward order.
SU → S to U is +2, forward order.
PN → P to N is -2 (P → O → N), i.e., reverse order.
All pairs are two letters separated by one letter but PN is in reverse order. Hence PN is the odd pair.
Classification questions require pattern recognition across meaning, grammar, numbers and letters. Apply a short checklist (semantic → grammatical → numeric → alphabetical → pairwise), eliminate quickly, and practise frequently to build speed and accuracy. When a numeric relation is involved, check squares, primes, multiples and digit-sum properties. For words, test synonyms, antonyms and category membership. With systematic practice these questions become fast and reliable scoring opportunities.
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