Grade 10 Exam  >  Grade 10 Notes  >  Mathematics  >  Speed Time & Distance Time Graphs

Speed Time & Distance Time Graphs

Speed Time Graphs 

In a speed-time graph speed is always plotted on the vertical axis and time is always plotted on the horizontal. This represents the motion of a particle accelerating from a speed at time 0 , u , to a speed v at time t.
Speed Time Graphs The gradient of the line of the speed-time graph is the acceleration of the particle (for straight lines acceleration is constant).
Speed Time Graphs 
Speed Time Graphs 
The area under the speed-time graph is the distance the particle travels.
Speed Time Graphs 
 = 8.

Distance Time Graphs

Distance-time graphs and Acceleration-time graphs can also be drawn for the motion of a particle, where time is always plotted on the horizontal axis.
A straight line on a distance-time graph represents that a particle has constant speed. Curvature suggests that a particle is accelerating or decelerating.

Worked Example: Speed-time graphs and acceleration-time graphs

Example: A car drives along a straight road. The car accelerates uniformly from rest to a speed of 10 ms-1 in 2T seconds. It then travels at a constant speed for 1 minute. The car then decelerates uniformly to rest in a further 8T seconds. Sketch a speed-time graph to illustrate the motion of the car. If the total distance travelled by the car is 800 m , find the value of T and sketch and acceleration-time graph to illustrate the motion of the car.

We sketch the following speed-time graph.
Worked Example: Speed-time graphs and acceleration-time graphsThe area of a trapezium is
Worked Example: Speed-time graphs and acceleration-time graphs
Where a represents the shorter of the two parallel sides of the trapezium and b represents the other. We are given that s = 800 m , so we equate this to the above expression and solve for T.
5(10T + 120) = 800,
10T + 120 = 160,
10T = 40,
T = 4.
The acceleration in the first 2T = 8 seconds is given by
a = 10/8 ,
= 1.25 ms-2.
Here, for the first 8 seconds the v -coordinate increases by 10 as the t -coordinate increases by 8, this gives a positive answer. The acceleration in the last 8T = 32 seconds is given by
a = -10/32
= -0.3125 ms-2.

Here, in the last 32 seconds the v-coordinate decreases by 10 as the t-coordinate increases by 32. This gives a negative answer.
Worked Example: Speed-time graphs and acceleration-time graphs

The document Speed Time & Distance Time Graphs is a part of the Grade 10 Course Mathematics for Grade 10.
All you need of Grade 10 at this link: Grade 10
Explore Courses for Grade 10 exam
Get EduRev Notes directly in your Google search
Related Searches
Viva Questions, shortcuts and tricks, Summary, study material, Previous Year Questions with Solutions, Important questions, video lectures, pdf , mock tests for examination, Speed Time & Distance Time Graphs, Exam, ppt, Extra Questions, Objective type Questions, MCQs, Speed Time & Distance Time Graphs, Semester Notes, Free, Sample Paper, practice quizzes, Speed Time & Distance Time Graphs, past year papers;