Generally, we can calculate the square of a number by the formula (a2 + b2 + 2ab). This formula applies by splitting a number into a and b. For eg. (49)2 can be calculated using this formula by splitting into 40 and 9. But calculating with this method always is a lengthy process and not recommended to follow in the exam.
The base method of calculating squares is an easy method to square 2 and 3 digits numbers easily. The major thing is to find the Base here. The base is referred to as n x 10x where n is 1, 2, 3, and so on. You have to take the value of base i.e, 10x which is nearer to the number.
Let us see the steps to find the square of a number using the Base Method.
Step 1: Find Base i.e, n x10x.
Step 2:
Make sure the number of digits in this part = number of zeroes in the base, add zeroes if it is of fewer digits, or carry forward extra digits in case of more than the required digits.
Step 3:
Step 4: Merge results of Steps 2 and 3. Keep Step 2 result on the right side.
Suppose you have to find the square of 104.
In this way, you have to calculate the square using the base method. Let us take more examples to have a clear understanding.
Find the square of 99.
Find the square of 119.
Find the square of 198
Find the square of 482
Find the square of 1012
In the exam, you have don't have to write the individual steps. Just start calculating mentally and write the final value. After practicing, you will be able to solve this quickly.
Calculate the following squares using the base method and answer in the comment section.
(A) (93)2
(B) (216)2
(C) (1001)2
(D) (3014)2
The base method is useful when numbers are nearer to the base as it will become more calculating when the difference between numbers and base becomes larger. To overcome such calculation, we are introducing one more method i.e., the Duplex Method.
To understand this method, at first, you must know how to calculate the duplex of the numbers.
Dup (a) = a2
Dup (ab) = 2 x a x b
Dup (abc) = 2 x a x c + b2
Dup (abcd) = 2 x a x d + 2 x b x c
Now let`s start calculating squares using this method.
(A) Method of calculating the square of a number ab.
It will be Dup a | Dup ab | Dup b
Calculate the square of 42
Dup 4 | Dup 42 | Dup 2
42 |2 x 4 x 2| 22
16 | 1 6 | 4 (Keep only one digit in each part except the first one)
1764
(B) Method of calculating the square of a number abc.
Dup a | Dup ab | Dup abc | Dup bc | Dup c
Find the square of 145
(C) Method of calculating the square of a number abcd.
Dup a | Dup ab | Dup abc | Dup abcd | Dup bcd | Dup cd | Dup d
Find the square of 1234
This is the way to solve squares using the duplex method. But in exams, don`t write steps. Just start calculating the duplex from the right-hand side and write the final answer. Practice solving squares using this method without steps. You can calculate any number of digits from this method. The only need for this method is to know how to calculate the duplex of the numbers.
Calculate the following squares using the duplex method and answer in the comment section.
(A) (87)2
(B) (529)2
(C) (1991)2
(D) (5018)2
Let us see some more tricks of solving squares of the numbers ending with digits 1, 5, 6, and 9.
In the same way, you can calculate the square of other numbers ending with digit 5. You just need to strengthen your multiplication skills.
Suppose you have to find the square of 76.
Step : (Number - 1)2 + Number + (Number - 1)
(76)2 = (75)2 + 75 + 76 = 5625 + 151 = 5776 (Calculate square of number ending with digit 5 using the above method.)
(146)2 = (145)2 + 145 + 146 = 21025 + 291 = 21316
(1006)2 = (1005)2 + 1005 + 1006 = 1010025+ 2011= 1012036
To calculate squares of numbers ending with digit 6, you must know how to calculate squares of numbers ending with digit 5 and fast multiplication skills as it is the foremost requirement.
Suppose you have to find the square of 64.
Step : (Number + 1)2 - Number - (Number + 1)
(64)2 = (65)2 - 65 - 64 = 4225 - 129 = 4096(Calculate square of number ending with digit 5 using the above method.)
(294)2 = (295)2 - 295 - 294 = 87025 - 589= 86436
(3004)2 = (3005)2 - 3005 - 3004 = 9030025 - 6009 = 9024016
Again, you must know how to calculate squares of numbers ending with digit 5 with strong multiplication skills to calculate squares of numbers ending with digit 4.
Suppose you have to calculate the square of 91.
Step : (Number - 1)2 + Number + (Number + 1)
(91)2 = (90)2 + 90 + 91 = 8100 + 181 = 8281
(161)2 = (160)2 + 160 + 161 = 25600 + 321 = 25921
(921)2 = (920)2 + 920 + 921 = 846400 + 1841 = 848241 (Calculate 922 mntally using base method)
(1201)2 = (1200)2 + 1200 + 1201 = 1440000 + 2401 = 1442401
In the same way, you can calculate the square of other numbers ending with digit 1. For this, you must remember squares up to 20 and strong addition calculation mentally.
Suppose you have to calculate the square of 79.
Step : (Number + 1)2 - Number - (Number + 1)
(79)2 = (80)2 - 80 - 79 = 6400 - 159 = 6241
(159)2 = (160)2 - 160 - 1659 = 25600 - 319 = 25281
(579)2 = (580)2 - 580 - 579 = 336400 - 1159 = 335241 (Calculate 922 mntally using base method)
(1239)2 = (1240)2 - 1240 - 12039 = 1537600 - 2479 = 1535121 (Calculate 1242 using duplex method)
For this also, you must possess strong multiplication skills.
Step : [25 + (Number - 50) | (Number - 50)2]
(51)2 = 25 + 1 | 01 = 2601
(57)2 = 25 + 7 | 49 = 3249
(66)2 = 25 + 16 | 256 = 41 | 2 56 = 43 | 56 = 4356 (Keep only 2 digit on right side)
(69)2 = 25 + 19 | 361 = 44 | 3 61 = 47 | 61 = 4761 (Keep only 2 digit on right side)
Step : [25 - (50 - Number) | (50 - Number)2]
(49)2 = 25 - 1 | 01 = 2401
(43)2 = 25 - 7 | 49 = 1849
(37)2 = 25 - 13 | 169 = 12 | 1 69 = 13 | 69 = 1369 (Keep only 2 digit on right side)
(31)2 = 25 - 19 | 361 = 6 | 3 61 = 9 | 61 = 961 (Keep only 2 digit on right side)
(88)2 : it is 100 - 12 or a = 100 and b = 12
So, (88)2 = (88 + 12) (88 - 12) + 122 = 76 x 100 + 144 = 7744
(104)2 = (104 + 4) (104 - 4) + 42 = 108 x 100 + 146 = 10816
(438)2 = (438 + 38) (438- 38) + 382 = 476 x 400 + 1444 = 191844
Calculate the following squares using any of the above mentioned method:
(A) (59)2
(B) (876)2
(C) (1441)2
(D) (995)2
(E) (1441)2
(F) (78)2
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