CBSE Class 7  >  Class 7 Notes  >  Mathematics (Maths) (Old NCERT)  >  Short Question Answer: Algebraic Expressions

Short Question Answer: Algebraic Expressions

Q1.  Add x + y - 5, y - x + 5,  x - y + 5
Ans:
Adding the coefficients of the similar terms will give the sum of three terms that is,

Short Question Answer: Algebraic Expressions

Q2. Add 3a2b2 - 4ab + 5, 8a2b2 + 12ab - 9, 15 - 6ab - 5a2b2.
Ans:
Adding the coefficients of the similar terms will give the sum of three terms that is,

Short Question Answer: Algebraic Expressions

Q3. Subtract -x+ 6xy  from 8x- 4xy + 12.
Ans: 
Subtracting the coefficients of the similar terms will give the difference of two terms that is,

Short Question Answer: Algebraic Expressions

Q4. Subtract a2 - 4b2 + 3ab - 20 from 2a2 + 6b2 + 7ab + 12.
Ans:
Subtracting the coefficients of the similar terms will give the difference of two terms that is,

Short Question Answer: Algebraic Expressions

Q5. Find the value of the given equation 4x- 3x + 12, if x = -3
Ans: 
We are given the quadratic equation of x as,
4x- 3x + 12
Substituting the value x = -3,
= 4(-3)2 - 3(-3) + 12
=4 × 9 + 9 + 12
=36 + 9 + 12
=57

Q6. Simplify 3(2x + 1) + 4x + 15 when x = -1.
Ans:
We are given the quadratic equation of x  as,
3(2x + 1) + 4x + 15
Substituting x = -1,
= 3[2(-1) + 1] + 4(-1) + 15
= 3(-2 + 1)-4 + 15
= -3-4 + 15
= -7 + 15
= 8

Q7. Identify monomials and binomials in the following: 4xy, -a + 8, p2, xy + 4x.
Ans:
 
Monomials: the expressions that have only one variable. From the given set of expressions the monomials are 4xy, p2
Binomials: the expressions that have two variables. From the given set of expressions the binomials are  xy + 4x, -a + 8.


Q8. Define
(a) Like Terms
(b) Unlike Terms
Ans:
 
(a) Terms having the same algebraic factors are called like terms.
Example: 3pq  and 7pq
(b) Terms having different algebraic factors are called unlike terms.
Example: 2xy and -3x

Q9. Find the value of equation 3x2 - 4x + 8, when x = 8.
Ans:
We are given the quadratic equation of x as,
3x2 - 4x + 8
Substituting x = 8,
=3(8)2 - 4(8) + 8
=3(64) - 32 + 8
=192 - 32 + 8
=168

Q10. What should be taken away from 3x2 + 2y2 - 5xy - 25 to get -x2 - y2 + 2xy + 10.
Ans: 
Let the term required be p.
Short Question Answer: Algebraic Expressions
Hence, the required number is 4x+ 3y- 7xy - 35.

Q11.  From the sum of 7p + 3q + 11 and 4p - 2q - 5, subtract 3p - q + 11.
Ans: By adding coefficients of similar terms of the first two expressions we get,

Short Question Answer: Algebraic Expressions
By subtracting coefficients of similar terms of the above expression and third expression we get,

Short Question Answer: Algebraic Expressions

Q12. From the sum of 8a - 5b + 3 and 6a + 3b + 5, subtract the difference of 2a - 3b + 8 and a + 2b + 6.
Ans: 
By adding coefficients of similar terms of the first two expressions we get
Short Question Answer: Algebraic Expressions

By subtracting coefficients of similar terms of the above expression and third expression we get,

Short Question Answer: Algebraic Expressions

By subtracting,

Short Question Answer: Algebraic Expressions

Q13. Find the value of
(a) 3p2 + 4q2 - 5, when p = 3 and q = -2
(b) x3 - 3x2y + 2xy2 + 8xy + 9, when x = -3 and y = 1
Ans:
(a) 3p2 + 4q2 - 5

Substituting p = 3,q = -2,
= 3(3)2 + 4(-2)2 - 5
= 27 + 16 - 5
= 38

(b) x3 - 3x2y + 2xy+ 8xy + 9
Ans: Substituting x = -3,y = 1,
= (-3)3 - 3(-3)2(1) + 2(-3)(1)2 + 8(-3)(1) + 9
= -27 - 27 - 6 - 34 + 9
= -54 - 30 + 9
= - 75

Q14. What should be the value of 'p', 3m2 + m + p = 12 when m = 0.
Ans:
We are given the quadratic equation of m as,
3m2 + m+ p = 12
Substituting m=0,
3(0)2 + (0) + p = 12
p = 12 

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