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Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula

Q1: How much paper of each shade is needed to make a kite given in the figure, in which ABCD is a square with diagonal 60 cm?
Class 9 Maths Chapter 10 HOTS Questions - Heron’s FormulaSol:

Since diagonals of a square are of equal length and bisect each other at right angles, therefore,
Area of ∆AOD = 1/2 × 30 × 30 = 450 cm2
Area of ∆AOD = Area of ∆DOC = Area of ∆BOC
= Area of ∆AOB = 450 cm2
[∵ ∆AOD = ∆AOB ≅ ∆BOC ≅ ∆COD, ∵ they have equal area]
Now, area of ACEF (by Heron’s formula)
Here a = 20 cm, b = 20 cm and c = 30 cm
Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Area of ∆CEF = Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Now, area of orange shaded paper in kite
= Area of ∆AOD + Area of ∆CEF
= 450 cm2 + 198.4 cm2
= 648.4 cm2
Area of blue shaded paper in kite
= Area of ∆AOB + Area of ∆COD
= 450 cm2 + 450 cm2 = 900 cm2
Area of black shaded paper in kite = Area of ∆BOC = 450 cm2.

Q2: OPQR is a rhombus, whose three vertices P, Q and R lie on the circle with centre 0. If the radius of the circle is 12 cm, find the area of the rhombus.
Sol:

Since diagonals bisect each other at 90°.
∴ In right ∆QLR, (LR)2 + (LQ)2 = (QR)2
Class 9 Maths Chapter 10 HOTS Questions - Heron’s FormulaClass 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Area of rhombus OPQR = 1/2 x products of diagonals
= Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
= Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula

Q3: In an exhibition, an umbrella is made by stiching 10 triangular pieces of cloth with same message written on two triangular pieces. If each piece of cloth measures 60 cm, 60 cm and 20 cm, find how much cloth is required for each message.
Why we should respect women, educate women, save women and empower women ?
Class 9 Maths Chapter 10 HOTS Questions - Heron’s FormulaSol:

Here, each triangular piece is an isosceles triangle with sides 60 cm, 60 cm and 20 cm.Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Area of each triangular Piece = Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
Now, there are 2 triangular pieces with same message.
∴ Total area of cloth for each message = 2 × 591.61 = 1183.22 cm2
We should respect women, educate women, save women and empower women to serve humanity and give them equal opportunity so far they deprived

Q4: Sister Nivedita has trapezium shaped plot which she divided into three triangular portion for different purposes. I – for providing free education for orphan children, II – for providing dispensary for the needy villagers and III – for the library for villagers. Find the area of trapezium plot given in the figure. Which qualities of sister Nivedita are being depicted in question ?
Class 9 Maths Chapter 10 HOTS Questions - Heron’s FormulaSol:

Here, ABCD is the trapezium with AB || DC.
Through C, Draw CF ⊥ AB
For – I: For area of ∆EBC
Class 9 Maths Chapter 10 HOTS Questions - Heron’s FormulaClass 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
= Class 9 Maths Chapter 10 HOTS Questions - Heron’s Formula
= 336m2
But, we know, Area of ∆EBC = 1/2(base × height)
⇒ 1/21 × 30 × CF = 336
15 × CF = 336
⇒ CF = 336 / 15 = 22.4 m
Now, area of trapezium shaped plot = 1/2 (20 + 50)(22.4)
= 35 x 22.4 = 784 m2
Caring, kind, social, generous and visionary lady.

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