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Class 6 Maths Chapter 9 Practice Question Answers - Mensuration

Q1: Area of square = (a)_______ × (b)______squareunits.
Ans: 
We know that area of a square is = side × side
Therefore,
(a) Side
(b) Side


Q2: Area of rectangle = (a)_______ × (b)______squareunits.
Ans: 
We know that area of rectangle = length × breadth
Therefore,
(a) Length
(b) Breadth

Q3: Circumference of a circle, C = ________?
Ans: 
We know that circumference is the total length of the boundary of a figure.
So, C = 2πr.

Q4: Perimeter of square = ___?
Ans: 
We know that perimeter is the length of the boundaries of a figure.
Square has four sides.
Therefore, Perimeter of square = 4 × side.

Q5: Length of boundary of a plane figure is called_____.
Ans: 
Perimeter

Q6: Find the diameter of a circle whose circumference is 88cm.
Ans: 
Given: Circumference of a circle = 88cm
We need to find the diameter of the circle.
We know that circumference = πd.
Class 6 Maths Chapter 9 Practice Question Answers - Mensuration

Q7: Find circumference of a circle of radius 13cm.
Ans: 
Given: Radius = 13cm
We need to find the circumference of the circle.
We know, Circumference = 2πr
Class 6 Maths Chapter 9 Practice Question Answers - Mensuration

Q8: Find the perimeter of a square whose has sides measuring 6.4cm
Ans: Given: 
Side of square = 6.4cm
We need to find the perimeter of the square.
We know that the perimeter of the square = 4 × side
So, Perimeter of square will be
P = 4 × 6.4 = 25.6cm.

Q9: Find the cost of fencing a square field of 175m at Rs.60 per metre.
Ans: 
Given: Perimeter of square field = 175m
We need to find the cost of fencing the field.
Perimeter = 175m
Cost of fencing per metre = Rs.60
So, total cost of fencing will be
= 175 × 60 = Rs. 10,500

Q10: Length and breadth of a rectangle are 12.3cm and 9.6cm respectively. Find its perimeter.
Ans: 
Given: Length = 12.3cm
Breadth = 9.6cm
We know perimeter = 2(l + b)
= 2(12.3 + 9.6) = 31.5cm.

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