Worksheet Solutions: Fields And Fences - 2 | Mathematics for Class 4: NCERT PDF Download

Q1: Choose the correct answer.

(ii) Area of a rectangle is 36 sq cm and length is 9 cm. Find its breadth?
(a) 9 cm
(b) 6 cm
(c) 4 cm
Ans: (c)

(iii) The length of the boundary of a closed figure is called ______
(a) Volume
(b) Area
(c) Perimeter
Ans: (c)

(iv) Area of a rectangle 5 cm long and 3 cm wide is ______ sq cm.
(a) 8
(b) 10
(c) 15
Ans: (c)

(v) Area of a square with side 3m is ______
(a) 12
(b) 9
(c) 6
Ans: (b)

Q2: Fill in the blanks.

(i) The perimeter of a triangle of sides 4m, 3m and 2m is ______.
(ii) The amount of surface enclosed within a closed figure is called ______.
(iii) Unit of area is ______.
(iv) The perimeter of a square of sides 5 cm is ______.
(v) A square has a boundary of 12 cm. What will be the length of each side?
Ans:
(i) 9m
(ii) Area
(iii) Square cm/m/km
(iv) 20 cm
(v) 3 cm

Q3: Answer the following Questions.

(i) A square wall has a perimeter of 100 m. What is the side of the wall? Find its area?
Ans:
Perimeter of a square = 100m
Length of side of the wall = 100/4 = 25m
Area = Side X Side = 25 x 25 = 625 sq m

(ii) A rectangular garden is 150m long and 50m wide. Find its Perimeter?
Ans:
Length = 150m
Breadth = 50m
Perimeter = 150 + 50 + 150 + 50 = 400m

(iii) A square carom board has a perimeter of 420 cm. Find the length of each side?
Ans:
Perimeter of a square = 420 cm
Length of each side = 420/4 = 105 cm

(iv) Find the perimeter of a rectangle whose length and breadth are respectively 12 cm and 9 cm.
Ans:
Length = 12 cm
Breadth = 9 cm
Perimeter = 12 + 9 + 12 + 9 = 42 cm

(v) A rectangular field is 48 m long and 20m broad. Find the cost of fencing the field at the rate of Rs 50 per metre?
Ans:
Length = 48m
Breadth = 20m
Perimeter = 48 + 20 + 48 + 20 = 136m
Cost of fencing = 136 x 50 = 6800 rupees