Biot-Savart law gives the magnetic field produced at a point in space by a steady current. It was established from careful experiments by Jean-Baptiste Biot and Félix Savart and provides the relation between a current element and the magnetic field it produces at a point.

Experimentally the following dependences were observed for the magnetic field produced by a small current element:
These observations lead to the differential (scalar) form of the law:


Here μ0 is the permeability of free space.

Unit of magnetic field B: tesla (T) or weber per square metre (Wb m-2).
Writing the scalar dependence of the magnitude of the contribution from a small current element gives

The vector form (differential form) of the Biot-Savart law is

In words: the infinitesimal magnetic field dB at a point due to a current element I dℓ is
To obtain the total magnetic field B produced by an arbitrary steady current distribution, integrate the differential form over the entire current path:
B = (μ0 / 4π) ∫ (I dℓ × r̂) / r^2
For commonly used configurations the Biot-Savart law leads to familiar results after evaluation of the line integral, for example the field due to an infinitely long straight wire and the field on the axis of a circular coil.
We use superposition: magnetic fields produced by each coil add vectorially at the midpoint. Each coil is a circular coil of radius R and number of turns N carrying current I. The centres of the two coils are separated by 2R, therefore the midpoint is at a distance R from the centre of each coil.

Solve the problem by using the expression for the magnetic field on the axis of a circular coil of N turns and radius R, at a distance x from its centre:
B(x) = (μ0 N I R2) / (2 (R2 + x2)3/2)
Evaluate this expression at x = R, which is the distance from each coil to the midpoint.
Solution
The magnetic field at the midpoint due to one coil, B1, is
B1 = (μ0 N I R2) / (2 (R2 + R2)3/2)
Simplify the denominator:
R2 + R2 = 2 R2
(2 R2)3/2 = 23/2 R3
Therefore
B1 = (μ0 N I R2) / (2 × 23/2 R3)
Cancel R2 with R3:
B1 = (μ0 N I) / (2 × 23/2 R)
Simplify the powers of 2:
2 × 23/2 = 25/2
Thus
B1 = (μ0 N I) / (25/2 R)

Both coils are identical and carry current in the same direction, so their fields at the midpoint have the same magnitude and the same direction along the common axis. The net field is the sum of the two contributions:
Bnet = 2 B1
Substitute B1:
Bnet = 2 × (μ0 N I) / (25/2 R)
Simplify the numerical factor:
2 / 25/2 = 1 / 23/2
Therefore
Bnet = (μ0 N I) / (23/2 R)

Recognising 23/2 = 2√2, the result can also be written as
Bnet = (μ0 N I) / (2 √2 R)

Direction: The direction of B at the midpoint is along the common axis of the coils. Use the right-hand rule: curl the fingers in the direction of the current in each coil; the thumb gives the direction of the magnetic field on the axis. Since currents are in the same direction, the fields produced by the two coils at the midpoint reinforce each other and point along the same sense of the axis (from the coil side indicated by the right-hand rule towards the other).
Summary
The Biot-Savart law relates a current element to the magnetic field it produces: dB = (μ0 / 4π) (I dℓ × r̂) / r2. For a circular coil the axial field at distance x is B(x) = (μ0 N I R2)/(2 (R2 + x2)3/2). For the two identical coaxial coils separated by 2R and carrying equal currents in the same direction, the field at the midpoint is Bnet = (μ0 N I)/(23/2 R) directed along the common axis as given by the right-hand rule.
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