Arithmetic and quantitative reasoning problems frequently rely on a compact set of standard formulas and clear definitions. The following document collects those formulas, explains their meaning, gives short examples where useful, and offers practical tips for applying them in logical-reasoning and data-interpretation tasks. Retain this page as a quick reference while practising problem solving.
Definition: The arithmetic mean of n numbers x1, x2, ..., xn is the sum of the numbers divided by n.
Formula: (x1 + x2 + ... + xn) ÷ n
Example with worked solution:
Find the average of 4, 7 and 11.
Sum of the numbers = 4 + 7 + 11 = 22
Number of observations = 3
Average = 22 ÷ 3 = 22/3 = 7.333...
Formula: (w1·x1 + w2·x2 + ... + wn·xn) ÷ (w1 + w2 + ... + wn)
Use weighted average when different observations contribute unequally to the overall mean (for example, averages of batches of different sizes).
Ratio: a : b expresses the relative sizes of two quantities.
Proportion: a ÷ b = c ÷ d or a : b = c : d
When solving proportion problems, cross-multiply: a·d = b·c.
When speeds are given for different segments, use total distance ÷ total time to compute overall average speed. For harmonic averages of equal distances, use the harmonic mean formula for speeds.
Formula: I = P × R × T ÷ 100
Here I is the interest, P the principal, R the annual rate (percentage), and T the time in years.
Example with worked solution:
Find simple interest on ₹5,000 at 6% per annum for 2 years.
I = 5000 × 6 × 2 ÷ 100
I = 5000 × 12 ÷ 100
I = 600
Formula (amount): A = P(1 + r/n)(n·t)
Here A is the amount after time t years, P the principal, r the annual decimal rate, and n the number of compounding periods per year. For annual compounding (n = 1) use A = P(1 + r)t.
Notes: For interest rates given in percentages, convert r% to decimal by dividing by 100.
Example with worked solution:
Find the amount for P = ₹10,000 at 5% compounded annually for 2 years.
Convert rate to decimal: r = 5 ÷ 100 = 0.05
A = 10000 × (1 + 0.05)2
A = 10000 × 1.1025 = 11025
Use prime factorisation to compute LCM and GCD quickly: LCM uses the highest powers of primes; GCD uses the lowest powers common to all numbers.
Permutations (ordered selections): nP r = n! ÷ (n - r)!
Combinations (unordered selections): nC r = n! ÷ [r! (n - r)!]
Basic probability: For equally likely outcomes, Probability(Event) = (Number of favourable outcomes) ÷ (Total number of outcomes)
Permutations and combinations are widely used in counting arguments for logical-reasoning questions.
For grouped data, use class mid-points to approximate mean and variance. Quick estimations and table reading are frequently required in data-interpretation questions.
A price rises from ₹200 to ₹260. Compute the percentage increase.
Absolute increase = 260 - 200
Absolute increase = 60
Percentage increase = (60 ÷ 200) × 100
Percentage increase = 0.3 × 100 = 30%
From a set of 5 distinct objects, two are chosen at random. What is the probability that a particular object A is chosen?
Total number of ways to choose 2 from 5 = 5C2 = 10
Number of choices that include A: choose the other object from the remaining 4, so 4 ways
Probability = 4 ÷ 10 = 2 ÷ 5 = 0.4
Use this page as a checklist when solving quantitative reasoning and data-interpretation problems. Memorise the core formulas, practise their application in varied contexts and always check units and reasonableness of answers for faster, more accurate problem solving.
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| 4. Are there any specific strategies to solve arithmetic reasoning questions quickly in the CAT exam? | ![]() |
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