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Algebraic Expressions and Identities Chapter Notes - (Maths) Class 8 PDF

What are Algebraic Expressions?

Any mathematical expression that consists of numbers, variables and operations is called an algebraic expression. Examples: \(3x + 4\), \(5ab - 2b + 7\).

Components of an Algebraic Expression

Components of an Algebraic Expression
  • Constants: Fixed numerical values. Example: in \(3x + 4\), 4 is a constant.
  • Variables: Symbols that represent unknown or varying quantities. Example: \(x\) in \(3x + 4\) is a variable.
  • Coefficients: Numbers multiplied by variables. Example: in \(3x\), 3 is the coefficient of \(x\).
  • Operators: Symbols that indicate operations: \(+\), \(-\), \(\times\), \(\div\).

Types of Algebraic Expressions

Types of Algebraic Expressions

Polynomials are algebraic expressions made up of one or more terms. Terms separated by \(+\) or \(-\) are called unlike terms if their variable parts differ. Common types:

  • Monomial: An algebraic expression having only one term, e.g., \(7x^2\), \(-3ab\).
  • Binomial: An algebraic expression having two terms, e.g., \(x + 5\), \(3a - 2b\).
  • Trinomial: An algebraic expression having three terms., \(x^2 + 2x + 1\).
  • Polynomial: Expression with one or more terms where each term is a product of a constant and variables raised to whole-number powers.

Addition and Subtraction of Algebraic Expressions

Method

  • Arrange the expressions so that like terms appear in the same column.
  • Add or subtract the coefficients of like terms as you would combine like numerical terms.
  • If a term is not present in one expression, treat its coefficient as zero and bring the other term unchanged into the result.

Example 1: Add \(15p^{2} - 4p + 5\) and \(9p - 11\).

Solution: Write the expressions one below the other aligning like terms.

\(15p^{2} - 4p + 5\) \( \; \; \; \; \; \; \; \; + \; \; 9p - 11\)

Combine like terms.

\(15p^{2} + (-4p + 9p) + (5 - 11)\) \(= 15p^{2} + 5p - 6\)
Example 2: Subtract \(5a^{2} - 4b^{2} + 6b - 3\) from \(7a^{2} - 4ab + 8b^{2} + 5a - 3b\).
Solution: 
Change the signs of all terms of the expression to be subtracted, then add.
Expression to subtract: \(5a^{2} - 4b^{2} + 6b - 3\) Negated: \(-5a^{2} + 4b^{2} - 6b + 3\)

Now add to the first expression.

\(7a^{2} - 4ab + 8b^{2} + 5a - 3b\) \(+ \; (-5a^{2} + 4b^{2} - 6b + 3)\)

Combine like terms.

\((7a^{2} - 5a^{2}) - 4ab + (8b^{2} + 4b^{2}) + 5a + (-3b - 6b) + 3\) \(= 2a^{2} - 4ab + 12b^{2} + 5a - 9b + 3\)

Multiplication of Algebraic Expressions

When multiplying algebraic terms watch how coefficients combine and how exponents add for the same base. Use the distributive law to multiply monomials with polynomials and polynomials with polynomials.

Multiplication of Like Terms

The coefficients multiply and powers of the same variable add.

Example 3: Product of \(4x\) and \(3x\).

Solution: Multiply the coefficients. \(4 \times 3 = 12\)

Add the exponents of \(x\). \(x^{1} \times x^{1} = x^{1+1} = x^{2}\)
Therefore, \( (4x) \times (3x) = 12x^{2}\).
Example 4:
Product of \(5x\), \(3x\) and \(4x\).

Solution: Multiply coefficients: \(5 \times 3 \times 4 = 60\)

Add exponents of \(x\): \(x^{1} \times x^{1} \times x^{1} = x^{1+1+1} = x^{3}\)
So, \( (5x) \times (3x) \times (4x) = 60x^{3}\).

Multiplication of Unlike Terms

  • Multiply the coefficients.
  • If the variables are different, each variable is included unchanged in the product.
  • If some variables are the same, add the exponents of those variables.

Example 5: Product of \(2p\) and \(3q\).

Solution: Multiply coefficients: \(2 \times 3 = 6\)

Combine variables: \(p \times q = pq\)
So, \( (2p) \times (3q) = 6pq\).

Example 6: Product of \(2x^{2}y\), \(3x\) and \(9\).

Solution: Multiply coefficients: \(2 \times 3 \times 9 = 54\)

Combine powers of \(x\): \(x^{2} \times x^{1} = x^{2+1} = x^{3}\)
Combine \(y\): \(y\) remains as \(y\)
Hence, \( (2x^{2}y) \times (3x) \times 9 = 54x^{3}y\).

Multiplying a Monomial by a Monomial

Multiplying Two Monomials

General rule:

  • Coefficient of product = coefficient of first monomial × coefficient of second monomial.
  • Variable part = product of variable parts; add exponents for like bases.

Example 7: \( (3x^{2}) \times (4x^{3}) \)

Solution: Multiply coefficients: \(3 \times 4 = 12\)

Add exponents of \(x\): \(x^{2} \times x^{3} = x^{2+3} = x^{5}\)
So, \( (3x^{2}) \times (4x^{3}) = 12x^{5}\).

Example 8: \( (2a^{3}b) \times (5ab^{2}) \)

Solution: Multiply coefficients: \(2 \times 5 = 10\)

For \(a\): \(a^{3} \times a^{1} = a^{3+1} = a^{4}\)
For \(b\): \(b^{1} \times b^{2} = b^{1+2} = b^{3}\)
Thus, the product is \(10a^{4}b^{3}\).

Multiplying Three or More Monomials

The same rules extend: multiply all coefficients and add exponents for each variable across all monomials.

Example 9: \(4xy \times 5x^{2}y^{2} \times 6x^{3}y^{3}\)

Solution: Multiply coefficients: \(4 \times 5 \times 6 = 120\)

Combine powers of \(x\): \(x^{1} \times x^{2} \times x^{3} = x^{1+2+3} = x^{6}\)
Combine powers of \(y\): \(y^{1} \times y^{2} \times y^{3} = y^{1+2+3} = y^{6}\)
Therefore, the product is \(120x^{6}y^{6}\).

Example 10: Find the volume of each rectangular box with given length, breadth, and height.

LengthBreadthHeight
\(2ax\)\(3by\)\(5cz\)
\(m^{2}n\)\(n^{2}p\)\(p^{2}m\)
\(2q\)\(4q^{2}\)\(8q^{3}\)

Volume = length × breadth × height

Solution (i): Multiply coefficients: \(2 \times 3 \times 5 = 30\)

Multiply variables: \((ax) \times (by) \times (cz) = abcxyz\)
Volume = \(30abcxyz\)

Solution (ii): Multiply like bases: \(m^{2}n \times n^{2}p \times p^{2}m\)

Group same bases and add exponents: \(m^{2+1} n^{1+2} p^{1+2} = m^{3} n^{3} p^{3}\)
Volume = \(m^{3} n^{3} p^{3}\)

Solution (iii): Multiply coefficients: \(2 \times 4 \times 8 = 64\)

Multiply powers of \(q\): \(q^{1} \times q^{2} \times q^{3} = q^{1+2+3} = q^{6}\)
Volume = \(64q^{6}\)

Multiplying a Monomial by a Polynomial

Multiplying a Monomial by a Binomial

Multiply the monomial with each term of the binomial and then add the results (distributive law).

Example 11: Simplify \(2x \times (3x + 5xy)\).

Solution: Multiply \(2x\) by the first term: \(2x \times 3x\)

\(2x \times 3x = 6x^{2}\)
Multiply \(2x\) by the second term: \(2x \times 5xy\)
\(2x \times 5xy = 10x^{2}y\)
Sum: \(6x^{2} + 10x^{2}y\)

Example 12: Simplify \(a^{2} \times (2ab - 5c)\).

Solution: Multiply \(a^{2}\) by \(2ab\): \(a^{2} \times 2ab\)
\(= 2a^{3}b\)

Multiply \(a^{2}\) by \(-5c\): \(a^{2} \times (-5c)\)
\(= -5a^{2}c\)
Result: \(2a^{3}b - 5a^{2}c\)

Multiplying a Monomial by a Trinomial

Multiply the monomial with each term of the trinomial and add the products.

Example: \(4q \times (5q^{2} + 6q + 8)\)

Solution: \(4q \times 5q^{2} = 20q^{3}\)

\(4q \times 6q = 24q^{2}\)
\(4q \times 8 = 32q\)
Sum: \(20q^{3} + 24q^{2} + 32q\)

Example 13: Simplify and evaluate as directed:

(i) \(x(x - 4) + 3\) for \(x = 2\)

(ii) \(5z(3z - 9) - 4(z - 2) - 45\) for \(z = -1\)

Solution:

(i) Expand: \(x(x - 4) + 3\)

\(= x^{2} - 4x + 3\)
For \(x = 2\): evaluate \(x^{2} - 4x + 3\)
\(= 2^{2} - 4(2) + 3\)
\(= 4 - 8 + 3 = -1\)

(ii) Expand: \(5z(3z - 9) - 4(z - 2) - 45\)

\(= 15z^{2} - 45z - 4z + 8 - 45\)
Combine like terms: \(= 15z^{2} - 49z - 37\)
For \(z = -1\): evaluate \(15z^{2} - 49z - 37\)
\(= 15(-1)^{2} - 49(-1) - 37\)
\(= 15 + 49 - 37 = 27\)

MULTIPLE CHOICE QUESTION

Try yourself: What is the result of multiplying 5a and 2a2?

A

10a3

B

7a3

C

10a2

D

7a2

Multiplying a Polynomial by a Polynomial

Multiplying a Binomial by a Binomial

Use the distributive law (each term of the first multiplies every term of the second). Combine like terms at the end.

Example 14: Simplify \((3a + 4b) \times (2a + 3b)\).

Solution: Apply distributive law: \(3a \times (2a + 3b) + 4b \times (2a + 3b)\)

\(= (3a \times 2a) + (3a \times 3b) + (4b \times 2a) + (4b \times 3b)\)
Compute each product:
\(3a \times 2a = 6a^{2}\)
\(3a \times 3b = 9ab\)
\(4b \times 2a = 8ab\)
\(4b \times 3b = 12b^{2}\)
Combine like terms: \(6a^{2} + (9ab + 8ab) + 12b^{2} = 6a^{2} + 17ab + 12b^{2}\)

Multiplying a Binomial by a Trinomial

Multiply each term of the binomial by each term of the trinomial, then combine like terms.

Example 15: Simplify \((p + q) (2p - 3q + r) - (2p - 3q) r\).

Solution: First expand \((p + q)(2p - 3q + r)\):

\(= p(2p - 3q + r) + q(2p - 3q + r)\)
\(= 2p^{2} - 3pq + pr + 2pq - 3q^{2} + qr\)
Combine like terms in this part: \(2p^{2} - pq - 3q^{2} + pr + qr\)
Now expand \((2p - 3q)r\):
\(= 2pr - 3qr\)
Subtract: \((p + q)(2p - 3q + r) - (2p - 3q)r\)
\(= (2p^{2} - pq - 3q^{2} + pr + qr) - (2pr - 3qr)\)
Distribute the minus sign: \(= 2p^{2} - pq - 3q^{2} + pr + qr - 2pr + 3qr\)
Combine like terms for \(pr\) and \(qr\): \(pr - 2pr = -pr\) and \(qr + 3qr = 4qr\)
Final result: \(2p^{2} - 3q^{2} - pq + 4qr - pr\)

What is an Identity?

An identity is an equality that holds true for every permissible value of the variables. An equation is true only for certain values (solutions) and so is not an identity unless it holds for all values of the variable(s).

Example: \(x^{2} = 1\) is an equation true only for \(x = 1\) and \(x = -1\); it is not an identity.

What is an Identity?

Standard Identities

These identities are widely used to expand squares and products quickly and to simplify algebraic calculations.

  • \((a + b)^{2} = a^{2} + 2ab + b^{2}\)
  • \((a - b)^{2} = a^{2} - 2ab + b^{2}\)
  • \(a^{2} - b^{2} = (a + b)(a - b)\)
  • \((x + a)(x + b) = x^{2} + (a + b)x + ab\)
  • \((a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2ab + 2bc + 2ca\)

These identities provide alternative and faster methods to compute expansions, factorisations and products of expressions.

Using Identities: Solved Examples

Use identities to expand or factor expressions without full multiplication.

Example: Expand \((x + 3)^{2}\).

Solution: Use \((a + b)^{2} = a^{2} + 2ab + b^{2}\) with \(a = x\), \(b = 3\)

\(= x^{2} + 2 \cdot x \cdot 3 + 3^{2}\)
\(= x^{2} + 6x + 9\)
Example: Factor \(a^{2} - b^{2}\).

Solution: Use \(a^{2} - b^{2} = (a + b)(a - b)\)

So, \(a^{2} - b^{2} = (a + b)(a - b)\)

The document Chapter Notes: Algebraic Expressions and Identities is a part of the Class 8 Course Mathematics (Maths) Class 8.
All you need of Class 8 at this link: Class 8

FAQs on Chapter Notes: Algebraic Expressions and Identities

1. What are algebraic expressions and how are they different from numerical expressions?
Ans.Algebraic expressions are mathematical phrases that include numbers, variables, and operation symbols (like +, −, ×, ÷). They can represent a range of values. Unlike numerical expressions, which consist only of numbers and operations, algebraic expressions include variables that can change, allowing for more complex relationships and calculations.
2. How do you add and subtract algebraic expressions?
Ans.To add or subtract algebraic expressions, you combine like terms. Like terms are terms that have the same variable raised to the same power. For example, in the expression \(3x + 5x\), you can add the coefficients (3 + 5) to get \(8x\). For subtraction, you subtract the coefficients of like terms. For example, \(7y - 2y = 5y\).
3. What is the process for multiplying a monomial by a polynomial?
Ans.To multiply a monomial by a polynomial, you distribute the monomial to each term in the polynomial. For instance, if you have \(3x\) (the monomial) and \(2x^2 + 5x - 4\) (the polynomial), you multiply \(3x\) by each term: \(3x \cdot 2x^2 = 6x^3\), \(3x \cdot 5x = 15x^2\), and \(3x \cdot (-4) = -12x\). Therefore, the result is \(6x^3 + 15x^2 - 12x\).
4. Can you explain what identities are in algebra?
Ans.Identities in algebra are equations that hold true for all values of the variables involved. They represent fundamental truths about numbers and operations. For example, the identity \(a + b = b + a\) demonstrates the commutative property of addition, showing that the order of addition does not affect the sum.
5. What are standard identities in algebra and provide an example?
Ans.Standard identities are commonly used algebraic formulas that simplify calculations and help in factoring. An example of a standard identity is \((a + b)^2 = a^2 + 2ab + b^2\). This identity is useful for expanding the square of a binomial and can be applied in various algebraic problems.
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