JEE Exam  >  JEE Notes  >  Physics Main & Advanced  >  JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity

JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity

2024

No Question in JEE Advanced Exam from Chapter Current Electricity in Year 2023 !

2023

No Question in JEE Advanced Exam from Chapter Current Electricity in Year 2023 !

2022

Q1: Two resistances R1 = XΩ and R2 = 1Ω are connected to a wire AB of uniform resistivity, as shown in the figure. The radius of the wire varies linearly along its axis from   0.2 mm at A to   1 mm at B. A galvanometer (G) connected to the center of the wire,   50 cm from each end along its axis, shows zero deflection when A and B are connected to a battery. The value of X is ____________. [JEE Advanced 2022 Paper 2]

2022

Q2:  In the following circuit 2022. The charge stored in C3 is ____________ μC.          [JEE Advanced 2022 Paper 1]
2022

Q3: The figure shows a circuit having eight resistances of  each, labelled R1 to R8, and two ideal batteries with voltages  ε1=12 V and  ε2=6 V.  

2022

Which of the following statement(s) is(are) correct?
(a) The magnitude of current flowing through R1 is 7.2 A.
(b) The magnitude of current flowing through R2 is 1.2 A.
(c) The magnitude of current flowing through R3 is 4.8 A.
(d) The magnitude of current flowing through R5 is 2.4 A. [JEE Advanced 2022 Paper 1]

2021

Q1: In order to measure the internal resistance r1 of a cell of emf E, a meter bridge of wire resistance R0 = 50Ω, a resistance R0/2, another cell of emf E/2 (internal resistance r) and a galvanometer G are used in a circuit, as shown in the figure. If the null point is found at l = 72 cm, then the value of r1 = __________ Ω. [JEE Advanced 2021 Paper 2]2021

2020

Q1: In the balanced condition, the values of the resistances of the four arms of a Wheatstone bridge are shown in the figure below. The resistance R3 has temperature coefficient 0.0004C-1. If the temperature of R3 is increased by 100C, the voltage developed between S and T will be ________ volt.               [JEE Advanced 2020 Paper 2]

2020

Q2: Shown in the figure is a semicircular metallic strip that has thickness t and resistivity ρ. Its inner radius is R1 and outer radius is R2. If a voltage V0 is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage ΔV develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore any role of the magnetic field due to the current). Then (figure is schematic and not drawn to scale)    [JEE Advanced 2020 Paper 1]

2020

(a) 2020
(b) the outer surface is at a higher voltage than the inner surface
(c) the outer surface is at a lower voltage than the inner surface
(d) 2020

2019

Q1: A parallel plate capacitor of capacitance C has spacing d between two plates having area A. The region between the plates is filled with N dielectric layers, parallel to its plates, each with thickness, 2019. The dielectric constant of the mth layer is 2019. For a very large N(>103), the capacitance C is 2019.

The value of α will be______
[∈0 is the permittivity of free space.] [JEE Advanced 2019 Paper 1]

Q2: In the circuit shown, initially there is no charge on the capacitors and keys S1 and S2 are open. The values of the capacitors are C1 = 10μF, C2 = 30μF and C3 = C4 = 80μF. 

2019

Which of the statement(s) is/are correct?
(a) The key S1 is kept closed for long time such that capacitors are fully charged. Now, key S2 is closed, at this time, the instantaneous current across 30Ω resistor (between points P and Q) will be 0.2 A (round off to 1st decimal place).
(b) If key S1 is kept closed for long time such that capacitors are fully charged, the voltage across the capacitor C1 will be 4V.
(c) At time t = 0, the key S1 is closed, the instantaneous current in the closed circuit will be 25 mA.
(d) If key S1 is kept closed for long time such that the capacitors are fully charged, the voltage difference between points P and Q will be 10 V. [JEE Advanced 2019 Paper 1]

The document JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity is a part of the JEE Course Physics for JEE Main & Advanced.
All you need of JEE at this link: JEE

FAQs on JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity

1. What is the principle behind Kirchhoff's laws in current electricity?
Ans.Kirchhoff's laws consist of two principles: the junction rule and the loop rule. The junction rule states that the total current entering a junction must equal the total current leaving the junction, reflecting the conservation of charge. The loop rule states that the sum of the potential differences (voltage) around any closed loop in a circuit must equal zero, which is based on the conservation of energy.
2. How do you calculate equivalent resistance in series and parallel circuits?
Ans.In a series circuit, the equivalent resistance (R_eq) is the sum of all resistances: R_eq = R1 + R2 + R3 + ... In a parallel circuit, the equivalent resistance is found using the formula: 1/R_eq = 1/R1 + 1/R2 + 1/R3 + ..., meaning the inverse of the total resistance is equal to the sum of the inverses of each individual resistance.
3. What is Ohm's Law and how is it applied in circuit calculations?
Ans.Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. It is expressed as V = IR, and is used to calculate either voltage, current, or resistance in a circuit when the other two quantities are known.
4. What are the factors affecting the resistance of a conductor?
Ans.The resistance of a conductor is affected by several factors: the material of the conductor (different materials have different resistivities), the length of the conductor (longer conductors have higher resistance), the cross-sectional area (thicker conductors have lower resistance), and the temperature (most conductors have increased resistance at higher temperatures).
5. How can the concept of electric power be defined and calculated in a circuit?
Ans.Electric power (P) is defined as the rate at which electrical energy is transferred by an electric circuit. It can be calculated using the formula P = VI, where V is the voltage and I is the current. Additionally, power can also be expressed in terms of resistance using P = I^2R or P = V^2/R, depending on which quantities are known.
Explore Courses for JEE exam
Get EduRev Notes directly in your Google search
Related Searches
shortcuts and tricks, Free, Summary, Previous Year Questions with Solutions, JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity, Objective type Questions, ppt, MCQs, Extra Questions, Semester Notes, JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity, past year papers, JEE Advanced Previous Year Questions (2018 - 2025): Current Electricity, practice quizzes, Sample Paper, Viva Questions, mock tests for examination, Important questions, Exam, study material, pdf , video lectures;