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JEE Advanced Previous Year Questions (2018 - 2025): Electromagnetic Induction

2024

Q1: A region in the form of an equilateral triangle (in x - y plane) of height L has a uniform magnetic field 2024 pointing in the +z-direction. A conducting loop PQR, in the form of an equilateral triangle of the same height L, is placed in the x - y plane with its vertex P at x = 0 in the orientation shown in the figure. At t = 0, the loop starts entering the region of the magnetic field with a uniform velocity 2024 along the +x-direction. The plane of the loop and its orientation remain unchanged throughout its motion.
2024

Which of the following graphs best depicts the variation of the induced emf (E) in the loop as a function of the distance (x) starting from x = 0 ?        [JEE Advanced 2024 Paper 2]
(a) 2024

(b) 2024

(c) 2024

(d) 2024

Ans:  (a)
0 to L
2024ε = B ℓent v = B × x√3 v
L to 2 L
2024|emf| = B (L√3 - x0√3) v - B 2x0√3 v
= BvL√3 - √3 Bv x0
= Bv [L√3 - √3(x - L)]
Bv√3 [L - 3x + 3L]
Bv√3 [4L - 3x]
At x = 4L3
emf = 0

2023

Q1: A thin conducting rod MN of mass  20 gm, length  25 cm and resistance  10 Ω is held on frictionless, long, perfectly conducting vertical rails as shown in the figure. There is a uniform magnetic field B= 4 T directed perpendicular to the plane of the rod-rail arrangement. The rod is released from rest at time t = 0 and it moves down along the rails. Assume air drag is negligible. Match each quantity in List-I with an appropriate value from List-II, and choose the correct option.
[Given: The acceleration due to gravity   g = 10 m s-2 and e-1 = 0.4 ] 

20232023

(a) P→5,Q→2,R→3,S→1
(b) P→3,Q→1,R→4,S→5
(c) P→4,Q→3,R→1,S→2
(d) P→3,Q→4,R→2,S→5                      [JEE Advanced 2023 Paper 1]
Ans: (d)
From force equation

2023

2023

At t = 0.2 sec

2023

(P) Now at t=0.2sec
The magnitude of the induced emf = E = Bvℓ

2023

(Q) At t = 0.2sec, the magnitude of magnetic force = BIℓsin⁡θ

2023

(R) At t  = 0.2sec, the power dissipated as heat 

2023

(S) Magnitude of terminal velocity
At terminal velocity, the net force become zero

2023

Hence, Answer is (D)

2022

Q1: Consider an LC circuit, with inductance L = 0.1H and capacitance   C = 10-3 F, kept on a plane. The area of the circuit is   1 m2. It is placed in a constant magnetic field of strength B0 which is perpendicular to the plane of the circuit. At time t = 0, the magnetic field strength starts increasing linearly as 2022 with β= 0.04Ts-1
The maximum magnitude of the current in the circuit is _________ mA.   [JEE Advanced 2022 Paper 1]
Ans: 
3.98 to 4.02
Emf induced in the circuit is

2022

So the circuit can be rearranged as

2022

Using Kirchhoff's law we can write

2022

Using SHM concept we can write 

2022

So,

2022

2021

Q1: In a circuit, a metal filament lamp is connected in series with a capacitor of capacitance C μF across a 200 V, 50 Hz supply. The power consumed by the lamp is 500 W while the voltage drop across it is 100 V. Assume that there is no inductive load in the circuit. Take rms values of the voltages. The magnitude of the phase-angle (in degrees) between the current and the supply voltage is φ. Assume, π√3  5.
The value of C is ____________.     [JEE Advanced 2021 Paper 2]
Ans:
100
for lamp,

2021

2021

Q2: In a circuit, a metal filament lamp is connected in series with a capacitor of capacitance C μF across a 200 V, 50 Hz supply. The power consumed by the lamp is 500 W while the voltage drop across it is 100 V. Assume that there is no inductive load in the circuit. Take rms values of the voltages. The magnitude of the phase-angle (in degrees) between the current and the supply voltage is φ. Assume, π√3 ≈ 5.
The value of φ is ____________.     [JEE Advanced 2021 Paper 2]
Ans:
100
for lamp,

2021

2021

2021

2020

Q1: The inductors of two LR circuits are placed next to each other, as shown in the figure. The values of the self-inductance of the inductors, resistors, mutual-inductance and applied voltages are specified in the given circuit. After both the switches are closed simultaneously, the total work done by the batteries against the induced EMF in the inductors by the time the currents reach their steady state values is _________ mJ.                      [JEE Advanced 2020 Paper 2]

2020Ans: 55
Mutual inductance is producing flux in same direction as self-inductance.

2020

= 55 mJ

2019

Q1: A 10 cm long perfectly conducting wire PQ is moving with a velocity I cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10-3 A, where the value of x is _____
[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given e-1 = 0.37, where e is base of the natural logarithm]                              [JEE Advanced 2019 Paper 2]

2019Ans: 0.63
Motional emf,

2019

i = 0.63 mA

Q2: A conducting wire of parabolic shape, initially y = x2, is moving with velocity 2019 in a non-uniform magnetic field 2019, as shown in figure. If V0, B0, L and β are positive constants and Δϕ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are 

2019

(a) |Δϕ|= 2019
(b) |Δϕ| remains the same if the parabolic wire is replaced by a straight wire, y =x initially, of length √2L
(c) |Δϕ| = 2019
(d) |Δϕ| is proportional to the length of the wire projected on the y-axis.   [JEE Advanced 2019 Paper 1]
Ans: 
(a), (b) & (d)

2019Motional emf across the length dy is,

2019

emf in loop is proportional to L for given value of β,

2019

The length of projection of the wire Y = X of length √2L on the y-axis is thus, the answer remain unchanged.
Therefore, correct options are (a), (b) and (d) 

2018

Q1: In the figure below, the switches S1 and S2 are closed simultaneously at t = 0 and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current I in the middle wire reaches its maximum magnitude Imax at time t = τ . Which of the following statements is (are) true? 

2018

(a) 2018
(b) 2018
(c) 2018
(d) 2018                        [JEE Advanced 2018 Paper 1]
Ans:
(b) & (d)

2018

2018

2018

From principle of superposition,

2018

I is maximum when dI / dt = 0, which gives

2018

2018

The document JEE Advanced Previous Year Questions (2018 - 2025): Electromagnetic Induction is a part of the JEE Course Physics for JEE Main & Advanced.
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FAQs on JEE Advanced Previous Year Questions (2018 - 2025): Electromagnetic Induction

1. What is electromagnetic induction and how does it work?
Ans.Electromagnetic induction is the process by which a changing magnetic field generates an electric current in a conductor. This phenomenon occurs when the magnetic field around a conductor changes over time, either by moving the conductor through a magnetic field or by changing the strength of the magnetic field itself. According to Faraday's law of induction, the induced electromotive force (EMF) is directly proportional to the rate of change of magnetic flux through the conductor.
2. What are the applications of electromagnetic induction in everyday life?
Ans.Electromagnetic induction has numerous applications in everyday life. Some common examples include electric generators, which convert mechanical energy into electrical energy; transformers, which change the voltage of alternating current (AC) for efficient power transmission; and induction cooktops, which heat pots and pans using induced currents. Additionally, it is fundamental in devices like electric motors and inductive charging systems for wireless charging of electronic devices.
3. How is Lenz's law related to electromagnetic induction?
Ans.Lenz's law states that the direction of the induced current generated by electromagnetic induction will always be such that it opposes the change in magnetic flux that produced it. This means that if the magnetic field through a loop of wire increases, the induced current will flow in a direction that creates a magnetic field opposing the increase. This law is a consequence of the conservation of energy and helps to determine the direction of the induced current in practical applications.
4. What is the formula for calculating induced EMF in a coil?
Ans.The induced electromotive force (EMF) in a coil can be calculated using Faraday's law of induction, which states that EMF (ε) is equal to the negative rate of change of magnetic flux (Φ) through the coil. The formula is given by: \[ \varepsilon = -\frac{d\Phi}{dt} \] Where \( \Phi \) is the magnetic flux, which is the product of the magnetic field strength (B), the area (A) through which the field lines pass, and the cosine of the angle (θ) between the magnetic field and the normal to the surface.
5. What factors affect the magnitude of induced current in a circuit?
Ans.The magnitude of the induced current in a circuit is affected by several factors, including the rate of change of magnetic flux, the number of turns in the wire coil, the resistance of the circuit, and the strength of the magnetic field. According to Ohm's law, the induced current (I) can be calculated using the formula: \[ I = \frac{ε}{R} \] Where \( ε \) is the induced EMF and \( R \) is the resistance of the circuit. Thus, a higher rate of change in magnetic flux or a larger number of turns will increase the induced EMF and, consequently, the induced current.
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