Profit & Loss Worksheet - Class 5 Mathematics | Step-by-Step Answers & Quick Revision Guide

Q1: How to find Profit and loss?
Ans: Profit = SP - CP, Loss = CP - SP, where SP = Selling Price and CP = Cost Price.
If SP > CP it is a profit; if SP < CP it is a loss.
Q2: What is C.P?
Ans: The price paid by the shopkeeper to buy the goods from the manufacturer is called CP (cost price).
Q3: How to find C.P?
Ans: In case of profit, CP = SP − profit. In case of loss, CP = SP + loss.
Q4: How to find S.P?
Ans: In case of profit, SP = CP + profit. In case of loss, SP = CP − loss.
Q5: Find the Profit  or Loss -
(i) S.P=600, C.P=398
Ans: Profit = SP − CP = 600 − 398 = 202.
(ii) S.P=998, C.P=789
Ans: Profit = SP − CP = 998 − 789 = 209.
(iii) S.P= 11300, C.P=11300
Ans: No profit, no loss because SP = CP (11300 = 11300).

Q6: Find the profit or loss percentage:
(i) C.p = 700, s.p = 459
Ans: CP = 700, SP = 459.
Loss = CP − SP = 700 − 459 = 241.
Loss % = (241 / 700) × 100 = 34.428...% ≈ 34.43%.
(ii) C.p = 1999, s.p = 1990
Ans: CP = 1999, SP = 1990.
Loss = 1999 − 1990 = 9.
Loss % = (9 / 1999) × 100 ≈ 0.4502% ≈ 0.45%.
(iii) C.p = 2890, s.p = 2900
Ans: CP = 2890, SP = 2900.
Profit = 2900 − 2890 = 10.
Profit % = (10 / 2890) × 100 ≈ 0.3460% ≈ 0.35%.
(iv) C.p = 6392, s.p = 7392
Ans: CP = 6392, SP = 7392.
Profit = 7392 − 6392 = 1000.
Profit % = (1000 / 6392) × 100 ≈ 15.646% ≈ 15.65%.
(v) C.p = 6382, s.p = 2638
Ans: CP = 6382, SP = 2638.
Loss = 6382 − 2638 = 3744.
Loss % = (3744 / 6382) × 100 ≈ 58.66%.

Q7: Ram bought a scooter worth rupees 19000, spent 6000 on repair. Then he sold the scooter at rupees 26000. How much he gain or loss(in percent)?
Ans: Total cost (CP) = 19000 + 6000 = 25000.
SP = 26000.
Gain = SP − CP = 26000 − 25000 = 1000.
Gain % = (1000 / 25000) × 100 = 4%.

Q8: Nidhi bought 19 pens at rupees 11/piece, and sells at rupees 13/piece. Find her the percent of loss or profit.
Ans: Cost per pen = 11, Selling price per pen = 13.
Profit per pen = 13 − 11 = 2.
Profit % = (2 / 11) × 100 ≈ 18.18%.

Q9: Ronny bought a mirror at rupees 900, and sells at 1900. Find the percent of profit.
Ans: Profit = 1900 − 900 = 1000.
Profit % = (1000 / 900) × 100 ≈ 111.11%.

Q10: Ram and Rimi bought 4 chocolates each at rupees 900 each. If Ram only sells his chocolate at the price of 1100 each. Then find their percent of  profit.

Ans: Cost of 4 chocolates = 4 × 900 = 3600.
Ram's selling price for 4 chocolates = 4 × 1100 = 4400.
Profit = 4400 − 3600 = 800.
Profit % = (800 / 3600) × 100 ≈ 22.22%.
Rimi has not sold his chocolates, so no profit or loss for Rimi yet.

Q11: Rakesh bought a car worth rupees 450000 and sell it at rupees 505000. Find his percent of profit and loss.
Ans: CP = 450000, SP = 505000.
Profit = SP − CP = 505000 − 450000 = 55000.
Profit % = (55000 / 450000) × 100 ≈ 12.22%.

Q12: Ram bought a scooter worth rupees 19800, spent 6000 on repair. Then he sold the scooter at rupees 22000. How much he gain or loss (in percent)?
Ans: Total cost (CP) = 19800 + 6000 = 25800.
SP = 22000.
Loss = CP − SP = 25800 − 22000 = 3800.
Loss % = (3800 / 25800) × 100 ≈ 14.73%.

Q13: Nidhi bought 19 pens at rupees 19/piece, and sells at rupees 13/piece. Find her the percent of loss or profit.
Ans: Loss per pen = 19 − 13 = 6.
Loss % = (6 / 19) × 100 ≈ 31.58%.

Q14: Ronny bought a mirror at rupees 800, and sells at 1100. Find the percent of profit.
Ans: Profit = 1100 − 800 = 300.
Profit % = (300 / 800) × 100 = 37.5%.

Q15: Ram and Rimi bought 4 chocolates each at rupees 900 each. If Ram only sells his chocolate at the price of 1300 e. Then find their percent of  profit.
Ans: Cost of 4 chocolates = 4 × 900 = 3600.
Ram's selling price for 4 chocolates = 4 × 1300 = 5200.
Profit = 5200 − 3600 = 1600.
Profit % = (1600 / 3600) × 100 ≈ 44.44%.
Rimi has not sold his chocolates, so no profit or loss for Rimi yet.

Q16: Rakesh bought a car worth rupees 4508000 and sell it at rupees 5058000. Find his percent of profit and loss.
Ans: CP = 4,508,000; SP = 5,058,000.
Net profit = SP − CP = 5,058,000 − 4,508,000 = 550,000.
Profit % = (550,000 / 4,508,000) × 100 ≈ 12.20%.