Table of contents | |
Stress-strain Relationships and its Constant | |
Hooke’s Law | |
Relationship between the elastic constant | |
Solved Numericals |
Young’s modulus :
Hooke's law simply states that the extension of a spring (or any other stretchable object) is directly proportional to the force acting on it.
This law is only true if the elastic limit of the object has not been reached. If the elastic limit has been reached the object will not return to its original shape and may eventually break.
Bulk Modulus of Elasticity: The Bulk Modulus of Elasticity (K) is a measure of a material's resistance to uniform compression. It represents the material's elastic response to hydrostatic pressure or equilateral tension, reflecting its volumetric response under such conditions.
Poisson's Ratio: Poisson's Ratio (v) is a measure of the elastic deformation of a material in directions perpendicular to the direction of loading. Specifically, it is the ratio of transverse strain to the corresponding axial strain when a material is subjected to uniaxial stress.
Consider a piece of material in 2-dimensions. The stress in the y direction is σy and there is no stress in the x-direction. When it is stretched in the y-direction, it causes the material to get thinner in all the other directions at right angles to it. This means that a negative strain is produced in the x-direction. For elastic materials, it is found that the applied strain (εy) is always directly proportional to the induced strain (εx) and its ratio is called Poisson’s Ratio.
The strain produced in the x-direction is εx = - vεy
If stress is applied in x-direction then the resulting strain in the y-direction would similarly be εy= - νεx The resulting strain in any one direction is the sum of the strains due to the direct force and the induced strain from the other direct force.
The resulting strain in any one direction is the sum of the strains due to the direct force and the induced strain from the other direct force.
Converting Strain into Stress
We have already derived
When the material is compressed by a pressure p the stress is equal to -p because it is compressive. The bulk modulus is thenThis shows the relation between E, K and ν.
The relation between E, G and v is given bywhere E = Young’s modulus
G = Bulk modulus
v = Poisson’s ratio
Poisson's ratio,
Where ϵt is the transverse strain and ϵl is the longitudinal strain.
Let the length of the wire be l, r its radius, and A its cross-sectional area.
Poisson's ratio,
Volume of wire, V = Length × Cross-sectional area = l × πr2
dV = πr2.dl + 2πrl.dr
Since there is no change in volume, dV = 0
⇒ 0 = πr2.dl + 2πrl.dr
⇒ πr2.dl = - 2πrl.dr
Substituting (2) in (1),
Poisson's ratio,
Q2. An experiment was conducted and it was found that shear modulus of the material is equal to the bulk modulus then what will be the value of Poisson’s ratio?
Ans:
Concept:
The relation between elastic modulus (E), Bulk modulus (K) and shear modulus (G) is given by
Also we have relation between E and G as E = 2G (1 + μ)
Now,
After combining these two equations we get
Calculation:
Given:
K = G
Now,
∴ μ = 0.125
Q3. A student conducted an experiment on a wire and observed that there was no change in the volume of the wire due to a change in its length by stretching. The Poisson's ratio of the material of the wire is:
Ans:
Poisson's ratio,
Where ϵt is the transverse strain and ϵl is the longitudinal strain.
Let the length of the wire be l, r its radius, and A its cross-sectional area.
Poisson's ratio,
Volume of wire, V = Length × Cross-sectional area = l × πr2
dV = πr2.dl + 2πrl.dr
Since there is no change in volume, dV = 0
⇒ 0 = πr2.dl + 2πrl.dr
⇒ πr2.dl = - 2πrl.dr
Substituting (2) in (1),
Poisson's ratio,
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1. What is the relationship between the elastic constants in stress-strain relationships? |
2. How can Poisson's Ratio be used to determine material properties in stress-strain relationships? |
3. What are some common values of elastic constants for different materials? |
4. How do stress-strain relationships and their constants play a role in material testing and design? |
5. Can the relationship between elastic constants be used to predict the failure of a material under stress? |
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