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Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE) PDF Download

Q16: The operational amplifier shown in the figure is ideal. The input voltage (in Volt) is Vi = 2sin(2π × 2000t). The amplitude of the output voltage Vo (in Volt) is _______. (SET-2  (2015))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(a) 0.14
(b) 1.24
(c) 2.25
(d) 2.44
Ans: 
(b)
Sol: Vi = 2sin(2π × 2000t)
The transfer function of the system is
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)The input is 2sin⁡(2π × 2000t)
ω = 4000π
V0 = 2∣H(jω)∣ω = 4000π × sin(4000πt − ϕ)  
Output = 1.245sin(4000πt − 51.46°)
So, amplitude of output is 1.245.

Q17: The op-amp shown in the figure has a finite gain A = 1000 and an infinite input resistance. A step-voltage Vi = 1mV is applied at the input at time t = 0 as shown. Assuming that the operational amplifier is not saturated, the time constant (in millisecond) of the output voltage  Vo is (SET-1 (2015))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(a) 1001
(b) 101
(c) 11
(d) 1
Ans: 
(a)
Sol: The circuit is
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Now, the gain of op-amp is 1000
So, Vo = 1000(V− V)
Since V+ = 0 (grounded)
V- = VA
The above circuit can be redrawn as
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)So, Vo = 1000VA
Now, KCL at node 'A'
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)V− V= (1001) × 1000VAsC
V− V= s(1001000 × 10−6)VA
VA − s1.001VA = Vi
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Since, Vo = −1000VA
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Since, pole is at (1/1.001), so time constant is approax '1001'.

Q18: Consider the circuit shown in the figure. In this circuit R = 1kΩ, and C = 1μF. The input voltage is sinusoidal with a frequency of 50 Hz, represented as a phasor with magnitude Vi and phase angle 0 radian as shown in the figure. The output voltage is represented as a phasor with magnitude Vo and phase angle δ radian. What is the value of the output phase angle δ (in radian) relative to the phase angle of the input voltage? (SET-1 (2015))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) 0
(b) π
(c) π/2π/2
(d) −π/2
Ans:
(d)
Sol: The circuit is
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Since circuit has negative feedback, so with help of virtual short VA = VB
So, KVL in the loop from A to B given,
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)So, VA = −IR
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)and VA = VB
So, Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

Now, Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

So, Vo = V− IR

Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)= −Vi(sCR)
So, Vo = −jωRCVi
So, Vo lag Vi by 90° or phase of Vw.r.t Vi is −90°.  

Q19: Of the four characteristics given below, which are the major requirements for an instrumentation amplifier?
P. High common mode rejection ratio
Q. High input impedance
R. High linearity
S. High output impedance (SET-1(2015))
(a) P, Q and R only
(b) P and R only
(c) P, Q and S only
(d) Q, R and S only
Ans:
(a)

Q20: The transfer characteristic of the Op-amp circuit shown in figure is  (SET-3(2014))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(b) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(c) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(d) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Ans:
(c)
Sol: CASE-I: Vi > 0, the circuit will look like
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Hence Vo = 0
CASE-II: V< 0, the circuit will look like  
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Vo = −V01 ...(iii)
From equation (ii) and (iii),
Vo = Vi
 
Q21: An operational amplifier circuit is shown in the figure.
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)The output of the circuit for a given input vi is (SET-3 (2014))
(a) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(b) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(c) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(d) +Vsat or −Vsat

Ans: (d)
Sol: The circuit of op-amp '1' is a Schmitt trigger, therefore
V01 = ±Vsat
and the circuit of op-amp '2' is a non-inverting amplifier
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)⇒ V= 2V01
where, V01 = ±Vsat
Therefore, the answer is V0 = ±Vsat

Q22: A 10 kHz even-symmetric square ware is passed through a bandpass filter with centre frequency at 30 kHz and 3 dB passband of 6 kHz. The filter output is (SET-2 (2014))
(a) a highly attenuated square wave at 10 kHz
(b) nearly zero
(c) a nearly perfect cosine wave at 30 kHz
(d) a nearly perfect sine wave at 30 kHz
Ans: 
(c)

Q23: In the figure shown, assume the op-amp to be ideal. Which of the alternatives gives the correct Bode plote for the transfer function Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE) (SET-1 (2014))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(b) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(c) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(d) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Ans:
(a)
Sol: Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)This filter is considered as low-pass filter (LPF). The transfer function for LPF Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)ωc (corner frequency)= 103 rad/sec.
tha gain at low frequencies,
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
Q24: Given that the op-amps in the figure are ideal, the output voltage Vo is (SET-1 (2014))
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) (V1 − V2)
(b) 2(V1 − V2)
(c) (V1 − V2)/2
(d) (V1+V2)(V1 + V2)
Ans: 
(b)
Sol: Op-amp '3' circuit is a differential amplifier so,
Vo = V01 − V02 ...(i)
Now, apply KCL at node '2'
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)and apply KCL at node '1'
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)From equation (i), (ii) and (iii), we get
V0 = 2(V− V2)

Q25: In the circuit shown below the op-amps are ideal. Then, Vout in Volts is (2013)
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) 4
(b) 6
(c) 8
(d) 10
Ans: 
(c)
Sol: Output of the first op-amp
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
Q26: In the circuit shown below what is the output voltage (Vout) if a silicon transistor Q and an ideal op-amp are used? (2013)
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) -15 V
(b) -0.7V
(c) +0.7V
(d) +15V
Ans:
(b)
Sol: Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Using the concept of vitual ground, V = 0
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Vout = −0.7V

Q27: The circuit shown is a (2012)
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) low pass filter with f3dB =Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)

(b) high pass filter with f3dB = Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
(c) low pass filter with f3dB = Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
(d) high pass filter with f3dB = Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
Ans: (b)
Sol: Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)It is a high pass filter with

Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
Q28: For the circuit shown below,
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)The CORRECT transfer characteristic is (2011)
(a) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(b) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(c) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(d) Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Ans:
(d)
Sol: First section is differential amplifier having gain-1.
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Output is
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Second stage-schmitt trigger
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)
Q29: A low-pass filter with a cut-off frequency of 30 Hz is cascaded with a high pass filter with a cut-off frequency of 20 Hz. The resultant system of filters will function as (2011)
(a) an all-pass filter
(b) an all-stop filter
(c) an band stop (band-reject) filter
(d) a band-pass filter
Ans:
(d)
Sol: Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)It is band pass filter.

Q30: Given that the op-amp is ideal, the output voltage V0 is (2010)
Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)(a) 4V
(b) 6V
(c) 7.5V
(d) 12.12V
Ans:
(b)
Sol: Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE)= (1 + 2)(2) = 6V
The document Previous Year Questions- Operational Amplifiers - 2 | Analog and Digital Electronics - Electrical Engineering (EE) is a part of the Electrical Engineering (EE) Course Analog and Digital Electronics.
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