Whole Numbers | Maths Olympiad Class 6 PDF Download

Q1: A vendor delivers 105 litres of milk to a hotel in the morning and 85 litres in the evening. If the price of milk is ₹ 20 per litre, what is the total amount owed to the vendor each day?
(a) ₹ 3500
(b) ₹ 4200
(c) ₹ 3950
(d) ₹ 3800
Ans: (D)

• Morning milk supply = 105 L
• Evening milk supply = 85 L
• Total milk supplied in a day = (105 + 85) L = 190 L
• Price per litre of milk = ₹ 20
• Total cost for 190 L of milk = ₹ (20 × 190) = ₹ 3800

Q2: Mohit scored 85 in Mathematics, 75 in English, and 84 in Science. Kapil scored 82 in Mathematics, 84 in English, and 88 in Science. What is their combined total score?
(a) 495
(b) 490
(c) 498
(d) 500
Ans: (C)

• Total marks obtained by Mohit = 85 + 75 + 84 = 244
• Total marks obtained by Kapil = 82 + 84 + 88 = 254
• Therefore, the combined total marks for both = 244 + 254 = 498

Q3: A gardener has 389 saplings to plant in 16 rows. If he can fit only 24 saplings in each row, how many saplings will remain unplanted?
(a) 9
(b) 5
(c) 15
(d) 10
Ans: (B)

• Calculate the total saplings he can plant: 24 saplings per row multiplied by 16 rows equals 384 saplings.
• Determine the unplanted saplings: Subtract the total he can plant (384) from the total he has (389).
• Result: 389 minus 384 equals 5 saplings that cannot be planted.
• This means the gardener will have 5 saplings left over after planting.

Q4: There are 222 red balls in a basket. A boy removes 6 red balls and adds 12 white balls in their place. He keeps doing this until all the red balls are replaced with white ones. What is the total number of white balls added to the basket?
(a) 333
(b) 444
(c) 345
(d) 400
Ans: (B)

• Let n represent the number of times the boy performs this action.
• From the problem, we can set up the equation: 222 - 6 × n = 0.
• This simplifies to 6n = 222, leading to n = 222 / 6 = 37.
• In each step, he adds 12 white balls, so in 37 steps, the total number of white balls added is 12 × 37 = 444.

Q5: 50 chairs and 15 blackboards were bought for a school. If each chair is priced at ₹ 115 and a blackboard costs ₹ 345, what is the total bill amount?
(a) ₹ 10925
(b) ₹ 74740
(c) ₹ 51750
(d) ₹ 11940
Ans: (A)

• Total cost of chairs = ₹(50 × 115) = ₹ 5750
• Total cost of blackboards = ₹(15 × 345) = ₹ 5175
• Total amount of the bill = ₹(5750 + 5175) = ₹ 10925

In this problem, we first calculate the total cost of chairs by multiplying the number of chairs (50) by the cost per chair (₹ 115), which gives us ₹ 5750. Next, we find the total cost of blackboards by multiplying the number of blackboards (15) by the cost per blackboard (₹ 345), resulting in ₹ 5175. Finally, we add these two amounts together to get the total bill, which is ₹ 10925.