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Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT PDF Download

Page 190

Q1: A Person
How will you draw this?

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTThis figure has two components.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTYou might have figured out a way of drawing the first part. See this for drawing the second part.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTThe challenge here is to find out where to place the tip of the compass and the radius to be taken for drawing this curve. You can fix a radius in the compass and try placing the tip of the compass in different locations to see which point works for getting the curve. Use your estimate to determine where to keep the tip.
Ans: Step 1: We start with the base of the diagram. We take a line AB of length 4 cm as the base. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: At A and B, draw perpendicular lines using a protractor. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: Using a ruler, mark points C and D such that AC = 4 cm and BD = 4 cm. Join C and D by a line. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Using a ruler, take point M on the CD such that CM = 2 cm. M is the midpoint of CD. Using a protractor, draw a perpendicular to CD at M. Take a point P on this perpendicular such that PM = 2 cm. Distance PM can also be slightly less than or greater than 2 cm. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: Join PD. With centre at P, draw an arc from D to C of a radius equal to PD. With centre at P, draw a circle of radius 1.5 cm. Extend PM to touch the arc. (Fig. 5)

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 6: Erase the extra lines in Fig. 5 as in Fig. 6.

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 7: Fig. 6 represents the required depiction of the given “A person”.

Q2: Wavy Wave
Construct this.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

As the length of the central line is not specified, we can take it to be of any length.
Let us take AB to be the central line such that the length of AB is 8 cm. We write this as AB = 8 cm.
Here, the first wave is drawn as a half circle.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns: Step 1:
We start with the central line AB of length 8 cm, say. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Since 8 ÷ 2 = 4, using a ruler, take point C on AB such that AC = 4 cm. C is the mid-point of AB.
Since 4 ÷ 2 = 2, using a ruler, take points D on AC and E bn CB such that AD = 2 cm and CE = 2 cm. D is the mid-point of AC and E is the mid-point of CB. (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: With centre at D, draw a semicircle above the line AB and of radius 2 cm. With the centre at E, draw a semicircle below the line AB and of radius 2 cm. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Draw vertical lines in the semicircles above and below the line AB. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Fig. 4 represents the required depiction of the given “Wavy Wave”.

Q3: Eyes
How do you draw these eyes with a compass?

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns: Step 1: Take a line AB of length 8.5 cm (4 cm + 0.5 cm + 4 cm) as a base. Take points C and D on AB such that AC = 4 cm and AD = 4.5 cm (4 cm + 0.5 cm). (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Take points E and F on AB such that AE = 2 cm and FB = 2 cm. E is the mid-point of AC and F is the mid-point of DB. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a protractor, draw perpendiculars at E and F. (Fig. 3)

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Using a ruler, take points G, H, I, and J such that EG, EH, FI, and FJ are all equal to 1.5 cm. Equal distances can also be slightly less than or greater than 1.5 cm (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: With the centre at G, draw an arc from A to C of a radius equal to AG. Similarly, with the centre at H, I, and J draw arcs of radius equal to AG. Erase the extra lines as shown in Fig. 5.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 6: At points E and F, draw two black dots of big size. (Fig. 6)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Page 191

Q1: What radius should be taken in the compass to get this half-circle? What should be the length of AX?
Ans:
We have AB = 8 cm.
Since the “Wavy Wave” has two equal half circles, we have AX = XB.
∴ X is the mid-point of AB.
∴ AX = 8/2 = 4 cm
∴ The length of AX is 4 cm.
Let M be the mid-point of AX.
∴ AM = MX = 8/2 = 2 cm
The center of the half circle is M.
∴ Radius of half circle = AM = 2 cm
∴ The radius of the half circle is 2 cm.

Q2: Take a central line of a different length and try to draw the wave on it.
Ans: Step 1:
We start with the central line of different lengths, say, 10 cm. (Figure 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Since 10/2 = 5, using a ruler, take point C on AB such that AC = 5 cm. C is the mid-point of AB.
As 5 ÷ 2 = 2.5, using a ruler, take points D on AC and E on CB such that AD = 2.5 cm and CE = 2.5 cm.
D is the mid-point of AC and E is the mid-point of CB. (Figure 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: With centre at D, draw a half circle above the central line AB and of radius 2.5 cm. With centre at E, draw a half circle below the central line AB and of radius 2.5 cm. (Figure 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Draw vertical lines in the half circles above and below the line AB. (Figure 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: The figure represents the required depiction of the given “Wavy Wave” with the central line of length 10 cm.

Q3: Try to recreate the figure where the waves are smaller than a half circle (as appears in the neck of the figure ‘A Person’). The challenge here is to get both the waves to be identical. This may be tricky!
Ans: 
We shall draw a “Wavy Wave” of the form given in Figure 1.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Here, the waves are smaller than a half circle.
Step 1: We start with the central line AB of length 10 cm, say. (Figure 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Since 10 ÷ 2 = 5, using a ruler take a point C on AB such that AC = 5 cm. C is the mid-point of AB.
Since 5 ÷ 2 = 2.5, using a ruler, take points D on AC and E on CB such that AD = 2.5 cm and CE = 2.5 cm.
D is the mid-point of AC and E is the mid-point of CB. (Figure 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: At D, draw a perpendicular line below AB, using a protractor. At E, draw a perpendicular line above AB, using a protractor. (Figure 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Using a ruler, mark points F and G such that DF = 1.5 cm and EG = 1.5 cm.
Equal distances between DF and EG can also be slightly less than or greater than 1.5 cm. (Figure 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Join AF and BG. With the centre at F, draw an arc from A to C of a radius equal to AF. With the centre at G, draw an arc from B to C of a radius equal to GB. (Figure 5)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 6: Draw vertical lines in Figure 5. Also, erase the extra lines in Figure 5 as shown in Figure 6.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 7: Figure 6 represents the required depiction of a “Wavy Wave”, where the waves are smaller than a half circle.

Page 194

Q1: Draw a configuration of one rectangle and four squares on a square dot paper as shown in the given figure.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTWhat did you do to recreate this figure so that the four squares are placed symmetrically around the rectangle? Discuss with your classmates.
Ans: Step 1: Take a square dot paper and mark a dot on it at A. Start from A move 10 dots to the right and mark the tenth dot at B.
Step 2: Start from B and move 6 dots above B and mark the 6th dot as C. Start from A and move 6 dots above A and mark the 6th dot as D. Join AB, BC, CD, and DA.
Step 3: Take points E, F, G, and H on the dot paper as shown in the figure.
Step 4: Take points I, J, K, and L at a distance of 4 dots from E, F, G, and H respectively. Join IE, FJ, GK, and LH.
Step 5: On LH and GK, construct squares above the rectangle.
Step 6: On IE and FJ, construct squares below the rectangle.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 7: The figure is the required configuration of one rectangle and four squares on a square dot paper.


Q2: Identify if there are any squares in this collection. Use measurements, if needed.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTThink: Is it possible to reason out if the sides are equal or not, and if the angles are right or not without using any measuring instruments in the above figure? Can we do this by only looking at the position of corners in the dot grid?
Ans:

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Fig. I: In this figure, AB and BC are not equal. So, ABCD cannot be a square.
Fig. II: In this figure, ∠BAD is not equal to 90°. So, ABCD cannot be a square.
Fig. III: In this figure, counting dots between sides, we find that AB, BC, CD, and DA are all equal sides. Also, the position of the dots on the sides shows, that each angle of ABCD is 90°.
∴ ABCD is a square.
Fig. IV: In this figure, counting dots between sides, we find that AB, BC, CD, and DA are all equal sides. Also, using a protractor, we find that each angle of ABCD is 90°.
∴ ABCD is a square.

Q3: Draw at least 3 rotated squares and rectangles on a dot grid. Draw them such that their corners are on the dots. Verify if the squares and rectangles that you have drawn satisfy their respective properties.
Ans: 
We draw two rotated squares and two rotated rectangles on a dot grid such that the comers of squares and rectangles are on dots.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

We have drawn two rotated squares (II and III) and two rotated rectangles (I and IV). These squares and rectangles are drawn keeping in view the number of dots between sides and also the position of sides.
Using a protractor, we find that all angles of figures I to IV are 90°.
Using a ruler, we find that the opposite sides of Figures I and IV are equal and all sides of Figures II and III are equal.
∴ By definition, figures I and IV are rectangles, and figures II and III are squares.

Page 197

Q1: Draw a rectangle with sides of length 4 cm and 6 cm. After drawing, check if it satisfies both the rectangle properties.
Ans: 
We shall draw a rectangle of the form shown in Fig. 1.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 1: Using a ruler, draw a line AB equal to 6 cm. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a protractor, draw perpendicular lines at A and B (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a ruler, mark point P on the perpendicular line at A such that AP = 4 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 4 cm. (Fig. 4).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Join P and Q using a ruler. Erase the lines above P and Q. (Fig. 5).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: Using a ruler, verify that PQ is of length 6 cm.
Using a protractor, verify that ∠P and ∠Q are 90° each.
Step 6: We have:
(i) AB = PQ = 6 cm and AP = BQ = 4 cm
(ii) ∠A = ∠B = ∠Q = ∠P = 90°.
Step 7: ABQP in Fig. 5 is the required rectangle of sides 4 cm and 6 cm.

Q2: Draw a rectangle of sides 2 cm and 10 cm. After drawing check if it satisfies both the rectangle properties.
Ans: 
We shall draw a rectangle of the form shown in Fig. 1.

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 1: Using a ruler, draw a line AB equal to 10 cm. (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Using a protractor, draw perpendicular lines at A and B (Fig. 3).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: Using a ruler, mark point P on the perpendicular at A such that AP = 2 cm. Using a ruler, mark point Q on the perpendicular at B such that BQ = 2 cm. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Join P and Q using a ruler. Erase the lines above P and Q. (Fig. 5)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: Using a ruler, verify that PQ is of length 10 cm.
Using a protractor, verify that ∠P and ∠Q are 90° each.
Step 6: We have:
(i) AB = PQ = 10 cm and AP = BQ = 2 cm
(ii) ∠A = ∠B = ∠P = ∠Q = 90°.
Step 7: ABQP in Fig. 5 is the required rectangle of sides 2 cm and 10 cm.

Q3: Is it possible to construct a 4-sided figure in which-

  • all the angles are equal to 90° but
  • opposite sides are not equal?

Ans: Step 1: Using a ruler, draw a line AB equal to 6 cm, say. (Fig. 1).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Using a protractor, draw perpendicular lines at A and B (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a ruler, mark point P on the perpendicular at A such that AP = 4 cm.
Using a ruler, mark point Q on the perpendicular at B such that BQ = 2 cm, which is not equal to AP. (Fig. 3).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: In Fig. 3, the opposite sides of AP and BQ are not equal. Join P and Q using a ruler. Erase the lines above P and Q (Fig. 4).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Using a protractor, we find that neither ∠P nor ∠Q is 90°.
Step 6: We conclude that it is not possible to construct a 4-sided figure in which all angles are 90° and opposite sides are not equal.

Page 199

Q: Breaking Rectangles
Construct a rectangle that can be divided into 3 identical squares.

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns: We shall draw a rectangle of the form shown in Fig. 1.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 1: Let us keep the vertical side of the rectangle to 3 cm. Since the rectangle is to be divided into three identical squares, the length of the rectangle must be 3 cm + 3 cm + 3 cm = 9 cm.
Step 2: Using a ruler, draw a line AB equal to 9 cm. (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a ruler, find points P and Q on AB such that AP = 3 cm and PQ = 3 cm. Here, QB is also 3 cm. (Fig. 3).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Using a protractor, draw perpendicular lines at A, P, Q, and B. (Fig. 4).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: Using a ruler, mark points A’, P’, Q’, and B’ on perpendiculars at A, P, Q, and B respectively such that AA’ = PP’ = QQ’ BR’ = 3 cm. (Fig. 5).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 6: Join A’ and P’, P’ and Q’, and Q’ and B’ using a ruler. Erase the lines above A’, P’, Q’, and B’. (Fig. 6).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 7: ABB’A’ is the required rectangle which is divided into 3 identical squares APP’A’, PQQ’P’, and QBB’Q’.

Page 201

Q: Give the lengths of the sides of a rectangle that cannot be divided into:
(i) Two identical squares;
(ii) Three identical squares.
Ans: (i) Let the smaller side of a rectangle be x cm. If the larger side of the rectangle is 2x cm (x cm + x cm), then this rectangle can be divided into two identical squares of side x cm. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTLet us consider a rectangle of sides 4 cm and 6 cm. Here, 6 is not equal to 8 (4 + 4), so, it cannot be divided into two identical squares as shown in Fig. 2
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

(ii) Let the smaller side of a rectangle be x cm. If the larger side of the rectangle is 3x cm (x cm + x cm + x cm), then this rectangle can be divided into three identical squares of side x cm. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTLet us consider a rectangle of sides 3 cm and 8 cm. Here, 8 is not equal to 9 (3 + 3 + 3), so, it cannot be divided into three identical squares as shown in Fig. 4.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Construct

Q1: A Square within a Rectangle
Construct a rectangle of sides 8 cm and 4 cm. How will you construct a square inside, as shown in the figure, such that the centre of the square is the same as the centre of the rectangle?

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTHint: Draw a rough figure. What will be the sidelength of the square? What will be the distance between the corners of the square and the outer rectangle?
Ans: 
The centre of a rectangle (or square) is the point of intersection of its diagonals.
Step 1: Using a ruler, draw a line AB equal to 8 cm. Using a protractor, draw perpendicular lines at A and B. Using a ruler, mark point P on the perpendicular line at A such that AP = 4 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 4 cm. Join P and Q using a ruler. Erase the lines above P and Q. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Draw diagonals AQ and BP, using a ruler. Let the diagonals intersect at C. This point is the centre of the rectangle ABQP and of the required square. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Erase diagonals AQ and BP. Using a protractor, draw a perpendicular line on AB and pass through the centre C. Let this perpendicular meet AB at R and PQ at S. (Fig. 3).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Since AP = 4 cm, each side of the square must be 4 cm. Using a ruler, mark points A’ and B’ on AB such that A’R = 2 cm and RB’ = 2 cm. Thus, A’B’ = A’R + RB’ = 2 cm + 2 cm = 4 cm.
Similarly, using a ruler, mark points P’ and Q’ on PQ such that P’S = 2 cm and SQ’ = 2 cm. Thus, P’Q’ = P’S + SQ’ = 2 cm + 2 cm = 4 cm. (Fig. 4).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Using a ruler, join A’ and P’ and also B’ and Q’. Erase the line RS. (Fig. 5).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 6: In Fig. 5, A’B’Q’P’ is the required square with centre C, which is also the centre of the given rectangle.

Q2: Falling Squares
Construct the ‘Falling Squares” figure shown below:

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTMake sure that the squares are aligned the way they are shown. Now, try this.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns:
In the given figure, there are three falling squares and the side of each square is 4 cm.
Step 1: Using a ruler, draw a line AB equal to 4 cm. Using a protractor, draw perpendicular lines at A and B.
Using a ruler, mark point C on a perpendicular line at A such that AC = 4 cm.
Using a ruler, mark points D and E on a perpendicular line at B such that BD = 4 cm and DE = 4 cm. (Fig. 1).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Join C and D. Produce CD to F such that DF = 4 cm. Using a protractor, draw a perpendicular line at F. Using a ruler, mark points G and H on a perpendicular line at F such that FG = 4 cm and GH = 4 cm. (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: Join E and G. Produce EG to I such that GE = 4 cm. Using a protractor, draw a perpendicular line at I. Using a ruler, mark point J on the perpendicular line at I such that IJ = 4 cm. Join H and J. Erase extra lines in the figure. (Fig. 3).

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Fig. 3 is the required figure of three “falling squares” each of side 4 cm.

Q3: Shadings
Construct the figure given below. Choose the measurement of your choice. Note that the larger 4-sided figure is square and so tire the smaller ones.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns: Step 1:
Using a ruler, draw a line AB equal to 8 cm. Because, 8 ÷ 4 = 2, we shall draw smaller squares of side 2 cm. Using a protractor, draw perpendicular lines at A and B. Using a ruler, mark point P on the perpendicular line at A such that AP = 8 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 8 cm. Join P and Q using a ruler. Erase the lines above P and Q (Fig. 1).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: On the lines AB, BQ, QP, and PA, mark points at distances of 2 cm, using a ruler. Draw horizontal lines and vertical lines to get 16 squares. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: From comer A, erase the inner sides of four squares to get a square of side 4 cm with one comer at A. Draw parallel diagonals of the remaining 12 small squares of side 2 cm each. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: In the 12 small squares, draw horizontal lines in the portion above the diagonals. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 5: Fig. 4 is the required figure having 12 small squares in a square.

Q4: Square with a Hole
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Observe that the circular hole is the same as the centre of the square.
Construct a “Square with a Hole” as shown in the given figure. The centre of the hole is the same as the center of the square.
Hint: Think where the centre of the circle should be.
Ans:
The centre of a square is the point of intersection of its diagonals. This centre is also the centre of the hole in the figure.
Step 1: Using a ruler, draw a line AB equal to 5 cm, say. Using a protractor, draw perpendicular lines at A and B. Using a ruler, mark point P on the perpendicular line at A such that AP = 5 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 5 cm. Join P and Q using a ruler. Erase the lines above P and Q (Fig. 1).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Draw diagonals AQ and BP using a ruler. Let the diagonals intersect at C. This point is the centre of the square ABQP. Erase the diagonals AQ and BP. (Fig. 2).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: With centre at C and a radius of 1.5 cm, say, draw a circle using a compass. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 4: Fig. 3 is the required “Square with a Hole”.

Q5: Square with more Holes
Construct a “Square with Four Holes” as shown in the given figure.

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTAns: In the figure, the centre of a circle is the same as that of the corresponding square.
Step 1: Using a ruler, draw a line AB equal to 8 cm, say. Using a protractor, draw perpendicular lines at A and B. Using a ruler, mark point P on the perpendicular line at A such that AP = 8 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 8 cm. Join P and Q using a ruler. Erase the lines above P and Q. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 2: Using a ruler, find points C, D, E, and F such that AC = 4 cm, BD = 4 cm, QE = 4 cm, and PF = 4 cm. Join C and E and also F and D. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 3: Let G be the intersection of lines FD and CE. Find the centres of squares ACGF, CBDG, DQEG, and GEPF by joining their respective diagonals. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Erase the extra lines used for finding the centres of the smaller circles. With centre at centres of small squares, draw four circles of radius 1.3 cm, say. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Fig. 4 is the required “‘Square with Four Holes”.

Q6: Square with Curves
This is a square with 8 cm sidelengths.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTConstruct a “Square with Curves ”, taking a square of side 8 cm as shown in the figure.
Hint: Think where the tip of the compass can be placed to get all 4 arcs to bulge uniformly from each of the sides. Try it out!
Ans:
In the given figure, the centres of the four arcs are outside the square.
Step 1: Using a ruler, draw a line AB equal to 8 cm. Using a protractor, draw perpendicular lines at A and B. Using a ruler, mark point P on the perpendicular line at A such that AP = 8 cm. Using a ruler, mark point Q on the perpendicular line at B such that BQ = 8 cm. Join P and Q using a ruler. Erase the lines above P and Q. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a ruler, mark points C, D, E, and F such that AC = 4 cm, BD = 4 cm, QE = 4 cm, and PF = 4 cm. Join C and E and also D and F. Extend these lines outside the square. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Extend DF and take points G and H on it so that DG and FH are equal to 4 cm. Extend CE and take points I and J on it so that Cl and EJ are equal to 4 cm. The distance 4 cm can be taken slightly less than or greater than 4 cm. Join B and G. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: With centres at G, H, I, and J and a radius equal to BG, draw four arcs inside the square as shown in the given figure. Erase the extra lines. (Fig. 4).
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Fig. 4 is the required “Square with Curves” with the square of side 8 cm.

Page 211

Q1: Construct a rectangle in which one of the diagonals divides the opposite angles into 50° and 40°.
Ans: 
We shall draw a rectangle of the form shown in Fig. 1.

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 1: Using a ruler, draw a line AB equal to 4 cm, say. (Fig. 2.)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a protractor, mark dots C and D at angles 50° and 90° (50° + 40°), keeping the central point of the protractor at A. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a protractor, draw a perpendicular line to AB at B and let it intersect the extended line AC at E. (Fig 3)
Step 4: Using a protractor, draw a perpendicular line to BE at E and let it intersect the extended line AD at F. (Fig 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Erase the extra lines in Fig. 4. (Fig. 5)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 6: Fig. 5 is the required rectangle in which one of the diagonals divides the opposite angles into 50° and 40°.

Q2: Construct a rectangle in which one of the diagonals divides the opposite angles into 45° and 45°. What do you observe about the sides?
Ans: 
Do yourself.

Q3: Construct a rectangle one of whose sides is 4 cm and the diagonal is of length 8 cm.
Ans: 
We shall draw a rectangle of the form shown in Fig. 1.
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 1: Using a ruler, draw a line AB equal to 4 cm. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a protractor, draw a perpendicular line to AB at A and B (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: With the centre at A and a radius equal to 8 cm, draw an arc to intersect the perpendicular at B. Similarly, draw an arc of radius 8 cm with a centre at B to intersect perpendicular at A. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Join the points of intersection of arcs by PQ. (Fig. 5)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Erase the extra lines in Fig. 5 (Fig. 6)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 6: Fig. 6 is the required rectangle with one side equal to 4 cm and diagonals of length 8 cm.

Q4: Construct a rectangle one of whose sides is 3 cm and the diagonal is of length 7 cm.
Ans:
Do yourself.

Page 215

Q1: Construct a bigger house in which all the sides are of length 7 cm.
Recreate the given figure. Note that all the lines forming the border of the house are of length 7 cm.
Ans: 

Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT

Step 1: Using a ruler, draw a line DE equal to 7 cm. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a protractor, draw perpendicular lines to DE at D and E. Take point B perpendicular at D such that BD is 7 cm. Take point C on perpendicular at E such that CE is 7 cm. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: 7 cm – 1 cm = 6 cm and 6 cm ÷ 2 = 3 cm. Using a ruler, take points P and Q on DE such that DP = 3 cm and QE = 3 cm. Using a protractor, draw perpendiculars to DE at P and Q of length 2 cm each. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Join R and S. With centres at B and C and a radius of 7 cm, draw arcs to intersect at point A. Join AB and AC. With the centre at A and a radius of 7 cm, draw an arc from B to C. Also, erase the extra lines. (Fig. 4)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 5: Fig. 4 is the required recreation of the given house with all the lines forming the border of the house of length 7 cm.

Q2: Try to recreate ‘A Person’, ‘Wavy Wave’, and ‘Eyes’ from the section Artwork, using ideas involved in the ‘House’ construction.
Ans:
Do yourself.

Q3: Is there a 4-sided figure in which all the sides are equal in length but are not squares? If such a figure exists, can you construct it?
Ans: 
Step 1: Draw a line and take points A and B on it such that AB = 5 cm, say. (Fig. 1)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 2: Using a protractor, take points C and D such that angles on the right of A and on the right of B are 60° each. (Fig. 2)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 3: Using a ruler, take point P on AC such that AC = 5 cm and Q on BD such that BD = 5 cm. Join P and Q. (Fig. 3)
Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERTStep 4: Using a ruler, we measure the distance PQ. PQ is equal to 5 cm. Thus, in Figure ABQP, each side is equal to 5 cm. Here ∠A is 60°, which is not equal to 90°.
∴ ABQP is not a square.
Step 5: We find that there are 4-sided figures in which all the sides are equal in length but are not squares.

The document Playing with Constructions NCERT Solutions | Maths for Class 6 (Ganita Prakash) - New NCERT is a part of the Class 6 Course Maths for Class 6 (Ganita Prakash) - New NCERT.
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FAQs on Playing with Constructions NCERT Solutions - Maths for Class 6 (Ganita Prakash) - New NCERT

1. What are the basic tools needed for constructions in geometry?
Ans. The basic tools needed for constructions in geometry include a compass, a ruler (straightedge), and a pencil. These tools help in drawing accurate lines, angles, and circles.
2. How do you construct a perpendicular bisector of a line segment?
Ans. To construct a perpendicular bisector of a line segment, follow these steps: 1. Draw the line segment AB. 2. Place the compass on point A and draw arcs above and below the line. 3. Without changing the compass width, place the compass on point B and draw two arcs that intersect the first arcs. 4. Draw a line through the intersection points. This line is the perpendicular bisector of segment AB.
3. What is the importance of constructions in geometry?
Ans. Constructions in geometry are important because they help in visualizing and understanding geometric concepts. They also form the foundation for solving complex geometric problems and proofs, enhancing spatial reasoning skills.
4. Can you explain how to construct an equilateral triangle?
Ans. To construct an equilateral triangle, start with a line segment (the base). 1. Use a compass to measure the length of the segment. 2. With the compass point on one end of the segment, draw an arc above the line. 3. Without changing the compass width, place the compass point on the other end and draw another arc that intersects the first arc. 4. Draw lines from the endpoints of the original segment to the intersection point. This forms an equilateral triangle.
5. What are some common mistakes to avoid while performing constructions?
Ans. Common mistakes to avoid while performing constructions include not keeping the compass width consistent, misaligning the ruler, and not accurately marking points. It’s important to double-check measurements and ensure that all tools are used correctly for precise constructions.
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