Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation.
Logical Reasoning
Q1: Which of the following letters is not hidden in the given figure? (a) A (b) Q (c) I (d) H
Solution:
Ans: (b) Q is not there in the figure.
Q2: Find the odd one out. (a) Milk (b) Honey (c) Ice (d) Coffee
Solution:
Ans: (c) Except ice, everything is a liquid.
Q3: If 'home' is called 'pizza', 'pizza' is called 'glass', 'glass' is called 'cycle', and 'cycle' is called 'car', then Ravi will eat ______ with his friend. (a) home (b) glass (c) pizza (d) cycle
Solution:
Ans: (b) Ravi will eat pizza, but pizza is coded as 'glass'. So, Ravi will eat glass.
Q4: In a park, 35 students are sitting in a line. Raveena is sitting in the middle. What is her position from the left end? (a) 19th (b) 18th (c) 17th (d) 16th
Solution:
Ans: (b)
In the above diagram, it is clear that Raveena is sitting exactly in the middle of the line. So, Raveena is at the 18th position from the left end of the line.
Q5: Given below is a series of numbers, which follows a certain pattern: 19, 28, 37, 46, ? If the pattern continues in the same way, what will be the next number? (a) 49 (b) 53 (c) 55 (d) 57
Solution:
Ans: (c) The pattern followed is:
Q6: There is a certain relationship between the numbers of the pair on either side of the symbol (: :). Identify the relationship of the given pair and find the missing number. (a) 10 (b) 13 (c) 15 (d) 20
Solution:
Ans: (c) The relation between the numbers of the pair to the left side of (: :) is 3 x 3 = 9. Similarly, the relation between the numbers to the right side of (: :) is 5 x 3 = 15.
Q7: Which letter from the given options will replace the question mark (?) to form the name of a vegetable and the name of a fruit?
(a) A (b) I (c) S (d) C
Solution:
Ans: (d) The name of the fruit is LYCHEE and the name of the vegetable is LETTUCE. So, letter 'C' will replace the question mark.
Q8: How many more squares are there in the picture than hearts?
(a) 15 (b) 14 (c) 13 (d) 12
Solution:
Ans: (a) Number of squares in the picture = 26 Number of hearts in the picture = 11 Difference = 26 -11 = 15 So, there are 15 more squares than hearts in the picture.
Q9: Identify the category of the word formed after arranging the given letters. GNAOM (a) Flower (b) Animal (c) Fruit (d) Food
Solution:
Ans: (c) The meaningful word formed from the letters G, N, A, O and M is MANGO, which is the name of a fruit.
Q10: Which of the following words cannot be formed from the letters of the given word? COMMUNICATION (a) Cat (b) Onion (c) Coconut (d) Munich
Solution:
Ans: (d) In COMMUNICATION, there is no H. So, MUNICH cannot be formed.
Mathematical Reasoning
Q11: How many times should the number 9 be subtracted from 90 to get 0? (a) 10 (b) 9 (c) 8 (d) 7
Q12: Division is the inverse of (a) multiplication (b) addition (c) subtraction (d) None of these
Solution:
Ans: (a)
The four main mathematical operations are addition, subtraction, multiplication and division.
The inverse of addition is subtraction and vice versa.
The inverse of multiplication is division and vice versa.
Q13: What number should be added to 99,999 to get the smallest 6-digit number? (a) 1 (b) 2 (c) 3 (d) 5
Solution:
Ans: (a) It is only 1 which can be added to 99,999 to get the smallest 6-digit number. 99,999 + 1= 1,00,000 So, the correct answer is option A.
Q14: Look at the number sentence given below:
Which of the following numbers will make the above sentence true? (a) 53 (b) 64 (c) 71 (d) 85
Solution:
Ans: (a) The correct answer is 53. 82 + ? = 135 ? = 135 - 82 = 53
Q15: Which of the shapes given as options is missing in the figure below?
(a) Square (b) Hexagon (c) Circle (d) Rectangle
Solution:
Ans: (b) In the given figure, we have a square, a rectangle and a circle, but there is no hexagon.
Q16: is a cube. How many such cubes are needed to make the figure below?
(a) 4 (b) 5 (c) 6 (d) 8
Ans: (d)
Solution:
It can be easily seen that there is only one line and it contains 8 cubes.
Q17: is a cube. How many such cubes are needed to make the figure below?
(a) 4 (b) 8 (c) 12 (d) 16
Solution:
Ans: (d) We can see from the figure that there are five cubes in the middle line, two attached above the cube at one end and one attached below the cube at the other end. So, there are 8 cubes in total.
Q18: How many corner points are there in the figure given below?
(a) 15 (b) 12 (c) 11 (d) 10
Solution:
Ans: (a)
There are 3 corners in each triangle, which makes a total of 9 corners.Then, there are 2 corners formed by the sides of the second triangle and the base of the first triangle.
Also, there are 2 corners formed by the sides of the third triangle and the base of the first triangle. And, there are 2 corners formed by the sides of the third triangle and the base of the second triangle. So, total number of corners = 9 + 2 + 2 + 2 = 15
Q19: There are 1,39,230 students in a school. If 63,596 students are absent on a particular day, how many students are present on that day? (a) 75,634 (b) 70,634 (c) 65,634 (d) 60,634
Solution:
Ans: (a) Total number of students = 1,39,230 Number of students who are absent = 63,596\ So, number of students who are present = (1,39,230 - 63,596) = 75,634
Q20: Arpit travelled from point A to point B and covered 1750 km. While returning, he took a shortcut, in which he just travelled 1250 km. What is the difference between the two distances travelled? (a) 400 km (b) 450 km (c) 500 km (d) 550 km
Solution:
Ans: (c) Distance travelled while returning = 1250 km Distance travelled from point A to point B = 1750 km So, required difference = (1750 - 1250) km = 500 km
Q21: There are 467 bird families living near a mountain. If 32 bird families fly away for winter, how many bird families are left near the mountain? (a) 147 (b) 227 (c) 425 (d) 435
Solution:
Ans: (d) Total number of bird families = 467 Number of bird families that fly away = 32 Number of bird families left = 467 - 32 = 435
Q22: What fraction of the given figure is unshaded?
(a) 4/9 (b) 2/5 (c) 5/9 (d) 1/2
Solution:
Ans: (c) Total parts in the figure = 9 Number of unshaded parts = 5 Fraction of unshaded parts = 5/9
Q23: Which of the following is true? (a) 2016 - 1290 = 726 (b) 3206 - 1256 = 1850 (c) 2407 - 1265 = 1042 (d) Both (1) and (3)
Solution:
Ans: (a) This is the correct option as 2016 - 1290 = 726.
Q24: If A × A = 49, A + B = 19, then find the value of A × B. (a) 19 (b) 68 (c) 82 (d) 84
Solution:
Ans: (d) As, A × A = 49 = 7 × 7 So, A = 7 Now, A + B = 19 and A = 7 So, B = 12 Therefore, A × B = 7 × 12 = 84
Q25: Manish thinks of a number and then adds 5 to it. The answer that he gets is 14. What is the number he thought of? (a) 9 (b) 10 (c) 8 (d) 7
Solution:
Ans: (a) Let the missing number be A. So, according to the question, A + 5 = 14 So, A = 14 - 5 = 9 A is equal to 9.
Q26: The difference between 367 tens and ______ is 1367. Which of the following numbers will come in the blank space? (a) 2560 (b) 1734 (c) 2303 (d) 4520
Ans: (b) According to question: Total balloons = 45 If Lilly has 27 balloons, total would be 27 + __ = 45.
Q28: Miss Sunita wants to give one pen to each student. (i) There are 42 students in her class. (ii) The pens come in packs of 7. Which of the following can be used to find the number of boxes of pens Miss Sunita needs? (a) 42 + 7 (b) 42 ÷ 7 (c) 42 - 7 (d) 42 x 7
Solution:
Ans: (b) The total number of students is 42 and the pens come in packs of 7. Total number of pens needed = 42 42 ÷ 7 = 6
Q29: If Jug + Jug + Jug + Jug + Jug = 775 ml, then Jug = _________. (a) 165 ml (b) 155 ml (c) 145 ml (d) 135 ml
Solution:
Ans: (b) Jug + Jug + Jug + Jug + Jug = 775 ml Or, 5 Jugs = 775 ml Jug = 775 ÷ 5 = 155 ml
Q30: If , then the weight of each apple is ________. (a) 30 g (b) 40 g (c) 50 g (d) 60 g
Solution:
Ans: (d) Number of apples = 5 Total weight = 300 grams Weight of 1 apple = 300 ÷ 5 = 60 grams
Achievers Section
Q31: Rahul went to buy groceries. He purchased 3 pineapples, 2 pumpkins and 2 watermelons. How much weight would he have to carry home? (a) 13 kg (b) 16 kg (c) 17 kg (d) 18 kg
Solution:
Ans: (a) Weight of one watermelon = 2 kg Weight of two watermelons = 2 x 2 = 4 kg Weight of one pineapple = 1 kg = 3 x 1 kg = 3 kg Weight of one pumpkin = 3 kg Weight of two pumpkins = 2 x 3 kg = 6 kg So, total weight Rahul would have to carry = 4 + 3 + 6 = 13 kg
Q32: In a hotel, different combinations of food items are available as follows.
Which of the given combinations costs least? (a) Combo 2 (b) Combo 1 (c) Combo 3 (d) Combo 4
Q33: A figure containing 5 squares is given below. Find the length of each side of square B.
(a) 5 cm (b) 6 cm (c) 7 cm (d) 8 cm
Solution:
Ans: (c) Total length of all the squares joined together = 55 cm Side of square A = 20 cm Side of square B = ? Side of square C = 18 cm Side of square D = 5 cm Side of square E = Side of square D = 5 cm Therefore, 20 + B + 18 + 5 + 5 = 55 B + 48 = 55 B = 7 cm
Q34: Find the 4-digit number. (i) It is an odd number (ii) The tens digit is the smallest one-digit number. (iii) The hundreds digit is the tens digit of 2500 - 563. (iv) The thousands digit is the largest one-digit number. (a) 1931 (b) 2356 (c) 9311 (d) 9513
Solution:
Ans: (c) The tens digit is the smallest one-digit number = 1. The hundreds digit is the tens digit of 2500 - 563 = 1937 = 3. The thousands digit is the largest one-digit number = 9. Therefore, the required 4-digit odd number is 9311.
Q35: A play is scheduled in a theatre for the third Thursday of August. A magic show is scheduled to be held 8 days prior to that. For which date is the magic show scheduled?
(a) August 4 (b) August 7 (c) August 9 (d) August 11
Solution:
Ans: (b) The play is scheduled for third Thursday, which happens to be August 15. 8 days before August 15 = August 7 So, the magic show is scheduled for August 7.
FAQs on Mathematics Olympiad Previous Year Paper - 3
1. What topics are typically covered in the Class 3 Mathematics Olympiad?
Ans. The Class 3 Mathematics Olympiad usually covers topics such as basic arithmetic (addition, subtraction, multiplication, and division), simple fractions, patterns and sequences, basic geometry (shapes and their properties), and logical reasoning problems. It aims to assess students' understanding and application of mathematical concepts.
2. How can students prepare effectively for the Class 3 Mathematics Olympiad?
Ans. Students can prepare effectively by practicing past papers, solving sample questions, and engaging in regular math exercises at home. Additionally, they can use resources like math workbooks, online quizzes, and interactive games that focus on the relevant topics to enhance their problem-solving skills.
3. What is the format of the Class 3 Mathematics Olympiad exam?
Ans. The format of the Class 3 Mathematics Olympiad exam typically includes multiple-choice questions and problem-solving questions. The exam is usually timed, and students are required to answer a set number of questions within the given time frame. The questions are designed to test both fundamental math skills and logical reasoning.
4. Are there any specific strategies to tackle logical reasoning questions in the Olympiad?
Ans. Yes, to tackle logical reasoning questions, students should carefully read the questions and options. They should practice identifying patterns, making connections, and using elimination techniques to narrow down their choices. Regular practice with logical puzzles can also help improve their reasoning abilities.
5. What should parents do to support their children in preparing for the Mathematics Olympiad?
Ans. Parents can support their children by creating a positive study environment, encouraging regular study habits, and helping them with practice problems. They should also participate in their learning by discussing math concepts and providing resources such as math games and books to make learning enjoyable.
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