CBSE Class 5  >  Class 5 Notes  >  Mathematics  >  NCERT Solutions: Animal Jumps

NCERT Solutions: Animal Jumps

Page No. 165

Q: Do you see why 12 is a multiple of 1, 2, 3, 4, 6, and 12?
Ans:

2 × 6 = 12, 3 × 4 = 12, 12 × 1 = 12

Let Us Do

Q1: Make different arrays for the following numbers. Identify the factors in each case.
(a) 10
Ans:

Let Us Do

Factors of 10 are 1, 2, 5, and 10.

(b) 14
Ans:

Let Us Do

Factors of 14 are 1, 2, 7, and 14.


(c) 13
Ans:

Let Us Do

Factors of 13 are 1 and 13 only. So, 13 is a prime number.

(d) 20
Ans:

Let Us Do

Factors of 20 are 1, 2, 4, 5, 10, and 20.

(e) 25
Ans:

Let Us Do

Factors of 25 are 1, 5, and 25.

(f) 32
Ans:

Let Us Do

Factors of 32 are 1, 2, 4, 8, 16, and 32.

(g) 37

Ans:
Let Us Do

Factors of 37 are 1 and 37 only. So, 37 is a prime number.

(h) 46
Ans:

Let Us Do

Factors of 46 are 1, 2, 23 and 46.

(i) 54
Ans:

Let Us Do

Factors of 54 are 1, 2, 3, 6, 9, 18, 27 and 54.

Q: What do you notice about the common multiples of 3 and 4? Discuss in class.
Ans: 
Do it yourself.

Page No. 166-170

Let Us Do

Q1: Find 5 common multiples of the following pairs of numbers.
(a) 2 and 3
Ans:

2 and 3
Multiples of 2:
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, ...
Multiples of 3:
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, ...
 5 common multiples of 2 and 3 are: 6, 12, 18, 24, and 30.
(b) 5 and 8
Ans:
5 and 8
Multiples of 5:
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, 105, 110, 115, 120, 125, 130, 135, 140, 145, 150, 155, 160, 165, 170, 175, 180, 185, 190, 195, 200, ...
Multiples of 8:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200, ...
 5 common multiples of 5 and 8 are: 40, 80, 120, 160, and 200.

(c) 2 and 4
Ans:

Multiples of 2:
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, ...
Multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, ...
 5 common multiples of 2 and 4 are:
4, 8, 12, 16, and 20.

(d) 3 and 9
Ans:

Multiples of 3:
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, .......
Multiples of 9:
9, 18, 27, 36, 45, 54 ...
5 common multiples of 3 and 9 are:
9, 18, 27, 36, and 45.

(e) 5 and 10
Ans:

Multiples of 5:
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, ...
Multiples of 10:
10, 20, 30, 40, 50, 60, 70, 80, 90, 100, ...
5 common multiples of 5 and 10 are:
10, 20, 30, 40, and 50.

(f) 9 and 12
Ans:

Multiples of 9:
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, 180, 189, ...
Multiples of 12:
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180, 192, ...
5 common multiples of 9 and 12 are: 36, 72, 108, 144, and 180.

(g) 8 and 12
Ans:

Multiples of 8:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, ...
Multiples of 12:
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, ...........
5 common multiples of 8 and 12 are:
24, 48, 72, 96, and 120.

(h) 6 and 8
Ans:

Multiples of 6:
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, ...
Multiples of 8:
8,16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, ...
 5 common multiples of 6 and 8 are: 24, 48, 72, 96 and 120.

(i) 6 and 9
Ans:

Multiples of 6:
6, 12, 18, 24, 30, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, ...
Multiples of 9:
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, ...
5 common multiples of 6 and 9 are: 18, 36, 54, 72 and 90.

Q: What do you notice about the common multiples of different pairs of numbers? Discuss in class.
Ans:

Do it yourself.

Q2: Food is available at the end of a cobbled road. Robby, the rabbit, takes a jump of 4 each time. Deeku, the deer, takes a jump of 6 each time. They both start at 0. Will both Robby and Deeku reach the food? Who will reach first? How do you know? Explain your answer.
Let Us DoAns:

Robby (Rabbit): Jumps 4 steps at a time. This means Robby will land on multiples of 4 (0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64).
Deeku (Deer): Jumps 6 steps at a time. This means Deeku will land on multiples of 6 (0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60).
Robby: Yes, 64 is a multiple of 4 (4 x 16 = 64). Therefore, Robby will land exactly on 64.
Deeku: No, 64 is not a multiple of 6. (60 is 6 × 10, and 66 is 6 × 11. 64 falls in between). So, Deeku will not land exactly on 64.
Since Robby can land on 64 and Deeku cannot, Robby will be the one to reach the food.
Let Us Do

Q:  Mowgli's friends live along the trail on the marked places below. Which of his friends will he be able to visit, if he jumps by 2 steps starting from 0?

Ans: He will meet the ant, the frog, the bird, the bear, and the rabbit.

Q: Did Mowgli meet the ant, frog, bird and the rabbit? Notice their positions- 4, 12, 14, and 50. 2 is a common factor of these numbers.
Ans: 
Yes, Mowgli met the ant, the frog, the bird, and the rabbit.

Q: Which of his friends will he be able to meet if he jumps by 3 steps?
Ans: 
If Mowgli jumps by 3 steps, at 9 he met the spider, at 12 he met frog, at 21 he met snake, at 30 he met bear, at 39 he met deer, and at 57 he met with monkey as 3 is a common factor of the numbers 9, 12, 21, 30, 39, and 57.

Q: Which numbers will he touch if he jumps by 5 steps?
Ans: 
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55.
Q: 5 is a common factor of the numbers___________.
Ans: 
5 is a common factor of the numbers: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, ...
Q: Which numbers will he touch if he jumps by 10 steps?
Ans: 
10, 20, 30, 40,50.
Q: 10 is a common factor of the numbers_______.
Ans:
10 is a common factor of the numbers: 10, 20, 30, 40, 50, 60, ...
Q4: Let us find some common factors of the numbers 24 and 36. Note that all jumps in the following questions start from 0.
(a) Can we jump by 2 steps at a time to reach both 24 and 36? Yes/No. 2 is/is not a common factor of 24 and 36. ,
(b) Can we jump by 3 steps at a time to reach both 24 and 36? Yes/No. 3 is/is not a common factor of 24 and 36.
(c) Can we jump by 4 steps at a time to reach both 24 and 36? Yes/No. 4 is/is not a common factor of 24 and 36.
(d) What other jumps can we take to reach both 24 and 36?
(e) How many common factors can you find for 24 and 36? List them.
(f) What about jumping by 1 step each time to reach both 24 and 36?
Ans:

(a) Yes, we can jump by 2 steps at a time to reach both 24 and 36. 2 is a common factor of 24 and 36.
(b) Yes, we can jump by 3 step at a time to reach both 24 and 36. 3 is a common factor of 24 and 36.
(c) Yes, we can jump by 4 steps at a time to reach both 24 and 36. 4 is a common factor of 24 and 36.
(d) Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24
Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36
Common factors = 1, 2, 3, 4, 6, 12.
So we can also jump by 6 steps and 12 steps.
(e) The common factors of 24 and 36 are: 1, 2, 3, 4, 6, 12. They are six in number.
(f) Every number is a multiple of 1. So, 24 and 36 are also reached by 1-step jumps.
Q5: What are the common factors of 12 and 13?
Ans: Factors of 12 = 1, 2, 3, 4, 6, 12
Factors of 13 = 1, 13
So, the common factor of 12 and 13 is 1.

Q6:  Find which of the following numbers can be reached by jumps of 4 steps?
Let Us Do4 is the common factor of the numbers _____________________________.
Ans:

Let Us Do4 divides 16, 36 and 48 exactly.
So, numbers that can be reached by jumps of 4 steps are 16, 36 and 48.
4 is the common factor of the numbers  16, 36, and 48.
Q7:  Find the common factors of the following pairs of numbers.
(a) 12 and 16
Ans:

Factors of 12: (1), (2), 3, (4), 6, and 12.
Factors of 16: (1), (2), (4), 8, and 16.
Common factors of 12 and 16 are: 1, 2 and 4.

(b) 8 and 12
Ans:
Factors of 8: (1), (2), (4), and 8.
Factors of 12: (1), (2), 3, (4), and 12.
Common factors of 8 and 12 are: 1, 2, and 4

(c) 4 and 16
Ans:
Factors of 4: (1), (2), and (4).
Factors of 16: (1), (2), (4), 8, and 16. Common factors of 4 and 16 are: 1, 2 and 4

(d) 2 and 9
Ans:

Factors of 2: (1), and 2 Factors of 9: (1), 3, and 9
Common factor of 2 and 9 is only 1.

(e) 3 and 5
Ans:

Factors of 3: (1) and 3.
Factors of 5: (1) and 5.
Common factor of 3 and 5 is only 1.

(f ) 12 and 15
Ans:

Factors of 12: (1), (2), 3, 4, 6 and 12.
Factors of 15: (1), (3), 5 and 15.
Common factors of 12 and 15 are: 1 and 3.

(g) 20 and 5
Ans:

Factors of 20: (1) 2, 4, (5) 10 and 20.
Factors of 5: (1) and (5).
Common factors of 20 and 5 are: 1 and 5.

(h) 9 and 21
Ans:

Factors of 9: (1), (3) and 9.
Factors of 21: (1), (3), 7 and 21.
Common factors of 9 and 21 are: 1 and 3.

(i) 6 and 27
Ans:

Factors of 6: (1), 2, (3) and 6.
Factors of 27: (1), (3), 9 and 27.
Common factors of 6 and 27 are: 1 and 3.

Q: What do you notice about the common factors of different pairs of numbers? Discuss in class.
Ans: 
Do it yourself.

Q8:  State whether the following statements are true (T) or false (F). .
(a) Factors of even numbers must be even.
Ans: Example: Factors of 12 = 1, 2, 3, 4, 6, 12, which includes the odd numbers 1 and 3.
False.

(b) Multiples of odd numbers cannot be even.
Ans: Example: Multiples of 3 = 3, 6, 9, 12, which includes even numbers 6, 12.
False.

(c) Factors of odd numbers cannot be even.
Ans: Example: Factors of 15 = 1, 3, 5, 15 → all odd.
Example: Factors of 9 = 1, 3, 9 → all odd.
True.

(d) One of the common multiples of two consecutive numbers is their product.
Ans: Example: Consecutive numbers 4 and 5
Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40....
Multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60....
Common multiples: 20, 40, 60...
True.

(e) The only common factor of any two consecutive numbers is 1.
Ans: Example: Consecutive numbers 6 and 7
Factors of 6: 1, 2, 3, 6
Factors of 7: 1, 7
Common factors: 1
True.

(f) 0 cannot be a factor of any number.
Ans: 
True

Q9: Sher Khan, the tiger, goes hunting every 3rd day. Bagheera, the panther, goes hunting every 5th day. If both of them start on the same day, on which days will they be hunting together?
Ans: They will be hunting together on the days that are common multiples of 3 and 5.
Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27,
Multiples of 5: 5, 10, 15, 20, 25, 30...
If both of them start on the same day then the first day they hunt together is on the 15th day. They will also hunt together on the 30th day, 45th day, and so on (multiples of 15).

Q10:  (a) In the trail shown earlier, Sher Khan's house is on number 25 and that of Baloo the bear is on number 30. Mowgli wants to meet his friend Baloo the bear but wants to avoid Sher Khan's house. How long (in steps) could each jump be?
(b) What number of jumps (in steps) he could choose so that he can meet both Kaa, the snake, at 21 and Akela, the wolf, at 35?
Ans:

(a) Mowgli needs to choose a jump length that is a factor of 30 but NOT a factor of 25. Factors of 25: 1, 5, and 25 Factors of 30: 1, 2, 3, 5, 6, 10, 15, and 30
Numbers that are factors of 30 but not factors of 25: 2, 3, 6, 10, 15, 30.
Possible jump lengths Mowgli could choose: 2, 3, 6, 10, 15, 30.

(b) Mowgli needs to choose a jump length that is a common factor of both 21 and 35.
Factors of 21: (1), 3, (7), and 21
Factors of 35: (1), 5, (7), and 35 Common factors of 21 and 35: 1 and 7.
Possible jump's length Mowgli could choose: 1 and 7.

Q11: Sort the following numbers into those that are
(a) divisible by 2 only
(b) divisible by 5 only
(c) divisible by 10 only
(d) divisible by 2, 5, and 10.

Let Us DoAns:
(a) 22, 30, 38, 40, 56, 62, 66, 78, 84, 90.
(b) 25, 30, 40, 45, 55, 75, 90, 95.
(c) 30, 40, 90.
(d) 30, 40, 90.Let Us Do

The document NCERT Solutions: Animal Jumps is a part of the Class 5 Course Mathematics for Class 5.
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FAQs on NCERT Solutions: Animal Jumps

1. What are some examples of animals that can jump, and how do they differ in their jumping abilities?
Ans. Various animals are known for their jumping abilities, including frogs, kangaroos, and grasshoppers. Frogs utilize their powerful hind legs to leap long distances relative to their body size, making them excellent jumpers in water and on land. Kangaroos, on the other hand, have strong, elongated hind legs that allow them to cover large distances in a single bound, often reaching heights of over 3 meters. Grasshoppers can jump many times their body length thanks to a specialized mechanism in their hind legs, which act like springs. Each of these animals has adapted their jumping abilities for different environments and survival needs.
2. How do the physical structures of jumping animals contribute to their ability to leap?
Ans. The physical structures of jumping animals play a crucial role in their leaping ability. For instance, animals like frogs have long, muscular hind limbs that provide the necessary strength and force to propel themselves into the air. The tendons in their legs store elastic energy, which is released during a jump, enhancing their leaping distance. Similarly, kangaroos have a unique skeletal structure, where their large tail helps balance them during jumps. The design of their legs allows for efficient energy transfer, enabling them to hop for long distances with minimal effort.
3. What adaptations help animals in their jumping abilities?
Ans. Animals have developed several adaptations that enhance their jumping abilities. These include powerful leg muscles, elastic tendons, and lightweight bodies. For example, the limb muscles of frogs are highly developed for rapid contraction, enabling quick and powerful jumps. Additionally, many jumping animals have a flexible spine, which helps in storing energy during preparation for a leap. The design of their feet can also aid in gripping surfaces, allowing for better take-off and stability when landing.
4. Why is jumping an important survival mechanism for certain animals?
Ans. Jumping serves as a vital survival mechanism for various animals, primarily for evading predators, escaping threats, and finding food. For example, frogs often jump away from predators quickly, using their agile movements to evade capture. Similarly, grasshoppers can leap away from potential dangers, allowing them to survive in the wild. Jumping also helps animals reach food sources that are high off the ground, as seen in certain species of tree-dwelling frogs and insects that need to access vegetation.
5. How do scientists study the jumping abilities of animals, and what have they discovered?
Ans. Scientists study the jumping abilities of animals using various methods, including biomechanics, high-speed filming, and comparative anatomy. By analyzing how animals move and the forces involved in their jumps, researchers have discovered patterns in muscle use, energy efficiency, and the mechanics of take-off and landing. These studies have revealed that different species have evolved unique strategies for jumping that are well-suited to their environments, providing insights into the evolutionary pathways of these animals.
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