Chemical changes occur when elements or compounds react to form new substances. These changes can be represented in three common ways:
Another example:
In a chemical equation, the substances written on the left of the arrow are the reactants and those on the right are the products.
To write balanced chemical equations you must:
Chemical symbols (one- or two-letter shorthand for elements) are used in chemical equations. You should learn the symbols for common elements, especially the first 36 elements of the periodic table, and other frequently encountered elements such as Fe, Cu, Ag, Pb, Zn, Al, etc.
Activity suggestions:
A chemical formula shows which elements are present in a compound and the number of atoms of each element. The number of atoms of an element (if greater than one) is shown as a subscript. For example, calcium carbonate is CaCO3, and water is H2O.
If you need more practice with writing formulae, review earlier chapters on bonding and ion formation (ionic and covalent formula writing).
Write down the chemical formula for each of the following compounds:
Write down the name for each of the following compounds:
Definition: The mass of a closed system of substances remains constant regardless of the processes acting inside the system. Matter can change form but cannot be created or destroyed.
Because of this law, in any chemical reaction the total mass (and hence the total number of atoms of each element) of the reactants must equal the total mass (and total number of atoms of each element) of the products.
Example (simple): Fe + S → FeS.
Relative atomic masses: Fe ≈ 55.8, S ≈ 32.1, so one Fe atom plus one S atom gives a formula unit FeS with relative mass ≈ 87.9. The mass of reactants equals the mass of product when the equation is balanced.
Note: Some elements exist as molecules in their elemental form (e.g., S8, O2). For writing empirical or formula-unit equations we often use the simplest unit (S, O, etc.) when forming formulae, but when balancing equations their molecular forms must be taken into account as appropriate.
Using coloured balls, jelly sweets, marbles or paper cut-outs to represent atoms and molecules helps visualise balancing. Build reactant and product models and adjust coefficients until the number of each type of atom is equal on both sides.
QUESTION
Balance the following equation:
Mg + HCl → MgCl2 + H2
Sol
Count atoms in reactants and products: reactants have Mg = 1, H = 1, Cl = 1; products have Mg = 1, H = 2, Cl = 2. Increase HCl to 2 by placing coefficient 2 before HCl so that H and Cl balance on both sides. The balanced equation is:
Mg + 2HCl → MgCl2 + H2
QUESTION
Balance the following equation:
CH4 + O2 → CO2 + H2O
Sol
Initial atom count: reactants C = 1, H = 4, O = 2; products C = 1, H = 2, O = 3. Add coefficient 2 before H2O to balance hydrogen (now H = 4 on products). New oxygen count on products is 1×2 + 2×1 = 4; put coefficient 2 before O2 to supply 4 oxygen atoms. The balanced equation becomes:
CH4 + 2O2 → CO2 + 2H2O
QUESTION
In our bodies, sugar (C6H12O6) reacts with oxygen to produce carbon dioxide, water and energy. Write the balanced equation for this reaction.
Sol
Write the unbalanced equation: C6H12O6 + O2 → CO2 + H2O. Balance carbon first by placing coefficient 6 before CO2 (C becomes 6 on both sides). Balance hydrogen by placing coefficient 6 before H2O (H becomes 12 on both sides). Finally, count oxygen atoms: reactants O = 6 from sugar + 2×? from O2; products O = 6×2 + 6×1 = 18. To supply 18 oxygen atoms, O2 must have coefficient 6 (gives 12 atoms) plus the 6 from sugar = total 18. The balanced equation is:
C6H12O6 + 6O2 → 6CO2 + 6H2O
QUESTION
Solid zinc metal reacts with aqueous hydrochloric acid to form an aqueous solution of zinc chloride (ZnCl2) and hydrogen gas. Write a balanced equation for this reaction (include state symbols).
Sol
Unbalanced equation: Zn + HCl → ZnCl2 + H2. Zinc atoms already balance (1 each). Chlorine and hydrogen do not. Place coefficient 2 before HCl so there are two Cl atoms on the left to match ZnCl2 and H becomes 2 on left to match H2. Add state symbols: zinc is solid (s), hydrochloric acid aqueous (aq), zinc chloride aqueous (aq), hydrogen gas (g). The balanced equation is:
Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g)
Balance the following equations (show balanced equations only):
The physical state of each substance in a chemical equation is indicated in brackets immediately after its formula:
Heat required for a reaction is commonly indicated by placing the delta symbol (Δ) above the arrow or by writing "Δ" before the arrow. For example:
NH4Cl → Δ → NH3 (g) + HCl (g)
QUESTION
Lead (II) nitrate solution reacts with potassium iodide solution to form a precipitate of lead iodide while potassium nitrate remains in solution. Write a balanced equation (include state symbols).
Sol
Reactants: Pb(NO3)2 (aq) + 2KI (aq). Products: PbI2 (s) + 2KNO3 (aq). The balanced equation is:
Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)
QUESTION
When heated, aluminium metal reacts with solid copper(II) oxide to produce copper metal and aluminium oxide (Al2O3). Write the balanced equation (include state symbols).
Sol
Al (s) + CuO (s) → Cu (s) + Al2O3 (s). Balance: 2Al + 3CuO → 3Cu + Al2O3.
QUESTION
When calcium chloride solution is mixed with silver nitrate solution, a white precipitate of silver chloride appears and calcium nitrate is produced in solution. Write the balanced equation including state symbols.
Sol
CaCl2 (aq) + 2AgNO3 (aq) → 2AgCl (s) + Ca(NO3)2 (aq)
QUESTION
Solid ammonium carbonate decomposes to form three gaseous products. Write the balanced decomposition equation including state symbols.
Sol
(NH4)2CO3 (s) → 2NH3 (g) + CO2 (g) + H2O (g)
Aim: To investigate how the amount of product formed changes with the amount of reactant used.
Apparatus:
Method (outline):
Expected observation: More gas is collected when a larger volume (or amount) of acid is used, provided the solid is in excess or not limiting.
Balanced equation for the reaction between sodium hydrogen carbonate and sulphuric acid (one possible balanced form):
2NaHCO3 (s) + H2SO4 (aq) → Na2SO4 (aq) + 2CO2 (g) + 2H2O (l)
C3H8 (l) + O2 (g) → CO2 (g) + H2O (l)
Balance the following reaction for methane (CH4) burning in oxygen.