When an electric circuit is complete, charges move through the circuit only if a force drives them. This force must do work on the charges to make them move. In most simple circuits the force is provided by a battery or cell. A battery converts chemical potential energy into electrical energy and can do work on charges to drive them around a closed circuit.
Definition - Potential difference
The potential difference (voltage) between two points is the work done per unit charge to move a small positive test charge between those points. It is denoted by V and has the SI unit volt (V), where 1 V = 1 J·C-1.
The electromotive force (emf) of a battery is the maximum work per unit charge the battery can supply to move charge from one terminal to the other when no current is drawn (open circuit). The measured potential difference across the battery terminals when no current flows equals the emf.
When the battery is connected in a complete circuit and current flows, the potential difference across its terminals is generally smaller than the emf because some work is done inside the battery to move charges through its internal structure. The terminal potential difference Vterminal is related to the emf E and the battery's internal resistance r by
Vterminal = E - I·r
where I is the current leaving the battery. The difference E - Vterminal equals the work per unit charge done inside the battery (or the voltage drop across the internal resistance).
A voltmeter measures the potential difference between two points in a circuit. A voltmeter is always connected in parallel with the component across which the potential difference is to be measured. Ideal voltmeters have very high resistance so they draw negligible current from the circuit, minimising disturbance of the circuit conditions.
Definition - Electric current
Electric current I is the rate at which electric charge Q passes a fixed point in a circuit. It is measured in amperes (A), where 1 A = 1 C·s-1. The relationship is
I = Q / t
Conventional current is defined as the flow of positive charge; by this convention it flows from the positive terminal of a battery, through the circuit, to the negative terminal. In metallic conductors the actual charge carriers are electrons, which move in the opposite direction to conventional current.
Although individual charges drift slowly, when a battery is connected the electric field propagates through the conductor at a substantial fraction of the speed of light, so the effect (current starting to flow) appears almost instantaneous throughout the circuit. A useful analogy is pushing a line of marbles in a tube: pushing at one end causes a marble to emerge at the other end without each marble having to travel the full length.
An ammeter measures the rate of flow of charge in a circuit. An ammeter must be connected in series with the component whose current is to be measured. Ideal ammeters have very low resistance so they do not significantly change the current they are measuring.
Construct simple circuits using batteries, resistors, switches, connecting leads, an ammeter and a voltmeter. Use the ammeter in series to measure current through a component and the voltmeter in parallel to measure potential difference across it. If a meter has multiple ranges, always start with the largest range to avoid damaging the instrument.
QUESTION
An amount of charge equal to 45 C moves past a point in a circuit in 1 second. What is the current in the circuit?
SOLUTION
We use the definition I = Q / t.
I = 45 C / 1 s = 45 C·s-1 = 45 A.
The current is 45 A.
QUESTION
An amount of charge equal to 53 C moves past a fixed point in a circuit in 2 seconds. What is the current in the circuit?
SOLUTION
I = Q / t = 53 C / 2 s = 26.5 C·s-1 = 26.5 A.
The current is 26.5 A.
QUESTION
95 electrons move past a fixed point in a circuit in one tenth of a second. What is the current in the circuit?
SOLUTION
Each electron carries charge e = 1.6 × 10-19 C.
Total charge Q = 95 × 1.6 × 10-19 C = 1.52 × 10-17 C.
Time t = 0.1 s.
I = Q / t = 1.52 × 10-17 C / 0.1 s = 1.52 × 10-16 A.
The current is 1.52 × 10-16 A.
Definition - Resistance
Resistance R is a measure of how strongly a component opposes the flow of electric charge. Its SI unit is the ohm (Ω). One ohm is one volt per ampere (1 Ω = 1 V·A-1).
Resistance arises microscopically because moving charge carriers (electrons) collide with atoms and other imperfections in a conductor, transferring energy and producing heating.
The resistance of a uniform conductor depends on:
For a uniform conductor of length L and cross-sectional area A,
R = ρ · L / A
where ρ (rho) is the electrical resistivity of the material. Materials with very low resistivity can be superconducting at sufficiently low temperatures, in which case R = 0 for practical purposes.
When resistors are connected in series:
RS = R1 + R2 + ...
QUESTION
A circuit contains two resistors in series. The resistors have resistance values of 5 Ω and 17 Ω. What is the total resistance in the circuit?
SOLUTION
RS = R1 + R2 = 5 Ω + 17 Ω = 22 Ω.
The total resistance is 22 Ω.
QUESTION
A circuit contains three resistors in series with resistance values 0.5 Ω, 7.5 Ω and 11 Ω. What is the total resistance?
SOLUTION
RS = 0.5 Ω + 7.5 Ω + 11 Ω = 19 Ω.
The total resistance is 19 Ω.
QUESTION
A circuit contains two resistors in series. The resistors have resistance values of 750 kΩ and 1.7 MΩ. What is the total resistance in the circuit?
SOLUTION
Convert to the same unit: 750 kΩ = 750 × 103 Ω = 0.75 × 106 Ω; 1.7 MΩ = 1.7 × 106 Ω.
RS = 0.75 × 106 Ω + 1.7 × 106 Ω = 2.45 × 106 Ω = 2.45 MΩ.
The total resistance is 2.45 MΩ.
When resistors are connected in parallel:
1 / RP = 1 / R1 + 1 / R2 + ...
For two resistors in parallel this simplifies to
RP = (R1·R2) / (R1 + R2).
QUESTION
A circuit contains two resistors in parallel with values 15 Ω and 7 Ω. What is the total resistance?
SOLUTION
Use RP = (R1·R2)/(R1 + R2). Thus
RP = (15 × 7) / (15 + 7) = 105 / 22 ≈ 4.77 Ω.
The total resistance is approximately 4.77 Ω.
QUESTION
Starting from the previous example (15 Ω and 7 Ω in parallel), add a third parallel resistor of 3 Ω. What is the total resistance of the three parallel resistors?
SOLUTION
Compute 1 / RP = 1 / 15 + 1 / 7 + 1 / 3.
1 / RP = 0.0666667 + 0.142857 + 0.333333 = 0.542857.
RP = 1 / 0.542857 ≈ 1.84 Ω.
The total resistance is approximately 1.84 Ω.
Alternatively, compute the resistance of any two first (for instance 15 Ω and 7 Ω → 4.77 Ω), then put that result in parallel with 3 Ω and apply the two-resistor formula to obtain the same answer.
Suggested experiments include measuring how voltages and currents change as you add resistors in series and parallel. Typical observations:
| Component | Symbol | Usage |
|---|---|---|
| Light bulb | - (bulb symbol) | Glows when charge moves through it |
| Battery | - (battery symbol) | Provides energy for charge to move |
| Switch | - (switch symbol) | Opens or closes a circuit |
| Resistor | - (resistor symbol) | Resists the flow of charge |
| Voltmeter | V | Measures potential difference (connect in parallel) |
| Ammeter | A | Measures current (connect in series) |
| Connecting lead | - (wire) | Connects circuit elements |
| Instrument | Measured quantity | Proper connection |
|---|---|---|
| Voltmeter | Voltage | In parallel |
| Ammeter | Current | In series |
| Quantity | Unit name | Unit symbol |
|---|---|---|
| Potential difference / emf / voltage | volt | V |
| Current (I) | ampere | A |
| Resistance (R) | ohm | Ω |