CBSE Class 6  >  Class 6 Notes  >  Mathematics  >  RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

Q1:  Represent each of the whole numbers give below on number line.
(i) 0  
(ii) 8 
(iii) 13  
(iv) 15

Solution:
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

Q2: Use number line to find
(i) 5 + 4 
(ii) 6 + 3 
(iii) 7 + 1
(iv) 6 + 5
Solution:
(i) Start from 5, move towards right and make 4 jumps of 1 unit each.
∴ 5 + 4 = 9
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)
(ii) Start from 6, move towards right and make 3 jumps of 1 unit each.
∴ 6 + 3 = 9
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)
(iii) Start from 7, move towards right and make 1 jump of 1 unit.
∴ 7 + 1 = 8
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)
(iv) Start from 6, move towards right and make 5 jumps of 1 unit each.
∴ 6 + 5 = 11

RS Aggarwal Solutions: Whole Numbers (Exercise 3F)


Q3: Use number line to find
(i) 7 - 5
(ii) 9 - 4
(iii) 8 - 1
(iv) 13 - 8

Solution:
(i) Start from 7, move towards left and make 2 jumps of 1 unit each.
∴ 7 - 5 = 2
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

(ii) Start from 9, move towards left and make 4 jumps of 1 unit each.
∴ 9 - 4 = 5
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

(iii) Start from 13, move towards left and make 8 jumps of 1 unit each.
∴ 13 - 8 = 5

RS Aggarwal Solutions: Whole Numbers (Exercise 3F)
(iv) Start from 13, move towards left and make 8 jumps of 1 unit each.
∴ 13 - 8 = 5
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)


Q4: Use number line to find
(i) 3 × 5
(ii) 4 × 2
(iii) 7 × 3
(iv) 3 × 6

Solution:
(i) Actually 3 × 5 means 5 three times.
Start from 0, move 5 units at a time to the right and make 3 such moves to reach 15.
∴ 3 × 5 = 15
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

(ii) Actually 4 × 2 means 4 two times.
Start from 0, move 4 units at a time to the right and make 2 such moves to reach 8.
∴ 4 × 2 = 8
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

(iii) Actually 7 × 3 means 7 three times.
Start from 0, move 7 units at a time to the right and make 3 such moves to reach 21.
∴ 7 × 3 = 21
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)(iv) Actually 3 × 6 means 6 three times.
Start from 0, move 6 units at a time to the right and make 3 such moves to reach 18.
∴ 3 × 6 = 18
RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

The document RS Aggarwal Solutions: Whole Numbers (Exercise 3F) is a part of the Class 6 Course Mathematics for Class 6.
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FAQs on RS Aggarwal Solutions: Whole Numbers (Exercise 3F)

1. What are whole numbers?
Ans. Whole numbers are a set of numbers that include all natural numbers along with zero. They are used for counting and ordering and do not include any fractions or decimals. The set of whole numbers is represented as {0, 1, 2, 3, 4, ...}.
2. How do you perform addition with whole numbers?
Ans. To add whole numbers, you align the numbers by their place values (units, tens, hundreds, etc.) and add starting from the rightmost digit. If the sum exceeds 9, you carry over the extra value to the next left column. For example, adding 23 and 45 involves adding 3 + 5 = 8 and 2 + 4 = 6, giving a total of 68.
3. What is the significance of the number zero in whole numbers?
Ans. The number zero is significant in whole numbers as it acts as the identity element for addition. When zero is added to any whole number, the result remains unchanged. Additionally, zero indicates the absence of quantity and serves as a fundamental building block in the number system.
4. Can whole numbers be negative?
Ans. No, whole numbers cannot be negative. Whole numbers are defined to include zero and all positive numbers, but they do not include negative numbers. The set of whole numbers is distinct from integers, which do include negative numbers.
5. How do you subtract whole numbers?
Ans. To subtract whole numbers, you align the numbers by their place values and subtract starting from the rightmost digit. If the digit in the top number is smaller than the digit in the bottom number, you need to borrow from the next column. For example, to subtract 15 from 42, you would calculate 2 - 5 (borrowing) and 3 - 1, resulting in a total of 27.
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