DIRECTIONS: Each question has five answer choices. Select the one best answer. Do not use a calculator.
1. Which of the following is the best estimate of 487 × 52?
2. The value of \(\frac{3,987}{198}\) is closest to which integer?
3. Rounded to the nearest tenth, what is the value of 47.862?
4. A reasonable estimate for 21% of 398 is
5. Which expression gives the best estimate of \(\frac{5.97 \times 8.12}{3.89}\)?
6. The sum 1,872 + 4,923 + 2,104 is approximately
7. If a store sells 48 items at $9.95 each, approximately how much total revenue does the store collect?
8. What is a reasonable estimate for \(\sqrt{83}\)?
9. The expression \(\frac{(19.8)^2}{4.1}\) is closest to
10. A student estimates \(3.87 \times 10^5 \div 1.92 \times 10^2\) by computing \(\frac{4 \times 10^5}{2 \times 10^2}\). What is the result of the student's estimate?
11. Which of the following is the best approximation of \(\frac{897 + 1,123}{52 - 11}\)?
12. If \(x = 4.93\) and \(y = 2.08\), then \(\frac{x^2}{y}\) is approximately
13. The product 0.487 × 0.0312 is closest to
14. A reasonable estimate for \(\sqrt{47} + \sqrt{83}\) is
15. A rectangular field is 287 meters long and 193 meters wide. Which of the following is the best estimate of the perimeter of the field in meters?
16. A factory produces 1,892 units per day. If the factory operates for 21 days in a month, approximately how many units are produced that month?
17. The circumference of a circle is given by \(C = 2\pi r\). If a circle has a radius of 48.7 cm, which of the following is the best estimate of its circumference in centimeters? (Use \(\pi \approx 3\))
18. If \(n = \frac{987 \times 412}{197}\), which of the following is closest to \(n\)?
19. A store marks up items by 18% above cost. If an item costs $47.90, approximately what is the selling price?
20. The expression \(\frac{5.2 \times 10^6 \times 3.8 \times 10^{-3}}{9.7 \times 10^2}\) is approximately equal to
1C 2C 3C 4C 5B 6C 7C 8C 9B 10A
11C 12B 13B 14B 15D 16C 17C 18B 19C 20A
Question 1 - Correct Answer: C
Round 487 to 500 and round 52 to 50.
Compute 500 × 50 = 25,000.
The best estimate is 25,000.
Choice B results from rounding 487 to 400 instead of 500, yielding 400 × 50 = 20,000.
Question 2 - Correct Answer: C
Round 3,987 to 4,000 and round 198 to 200.
Compute \(\frac{4,000}{200} = 20\).
The value is closest to 20.
Choice D results from estimating with 3,987 rounded to 4,400 or from computational error in the division.
Question 3 - Correct Answer: C
The digit in the tenths place is 8.
The digit in the hundredths place is 6, which is 5 or greater.
Round up: 47.862 becomes 47.9.
Choice A results from failing to round up and instead truncating the number at the tenths place.
Question 4 - Correct Answer: C
Round 398 to 400.
Round 21% to 20%.
Compute 20% of 400: \(0.20 \times 400 = 80\).
A reasonable estimate is 80.
Choice D results from rounding 21% to 25% and computing 25% of 400 = 100.
Question 5 - Correct Answer: B
Round 5.97 to 6.
Round 8.12 to 8.
Round 3.89 to 4.
The best estimate is \(\frac{6 \times 8}{4}\).
Choice A results from rounding 5.97 down to 5 and 3.89 down to 3, which yields less accurate estimates.
Question 6 - Correct Answer: C
Round 1,872 to 2,000.
Round 4,923 to 5,000.
Round 2,104 to 2,000.
Compute 2,000 + 5,000 + 2,000 = 9,000.
The sum is approximately 9,000.
Choice B results from rounding 4,923 to 4,000, yielding 2,000 + 4,000 + 2,000 = 8,000.
Question 7 - Correct Answer: C
Round 48 to 50.
Round $9.95 to $10.
Compute 50 × 10 = 500.
Approximately $500 in total revenue.
Choice B results from rounding 48 to 45 instead of 50, yielding 45 × 10 = 450.
Question 8 - Correct Answer: C
\(9^2 = 81\) and \(10^2 = 100\).
Since 83 is between 81 and 100, \(\sqrt{83}\) is between 9 and 10.
83 is closer to 81 than to 100, so \(\sqrt{83}\) is closer to 9.
A reasonable estimate is 9.
Choice D results from choosing the midpoint between 9 and 10 without considering proximity of 83 to 81.
Question 9 - Correct Answer: B
Round 19.8 to 20.
Round 4.1 to 4.
Compute \(\frac{(20)^2}{4} = \frac{400}{4} = 100\).
The expression is closest to 100.
Choice A results from incorrectly computing \(20^2\) as 200 instead of 400, yielding \(\frac{200}{4} = 50\).
Question 10 - Correct Answer: A
The student computes \(\frac{4 \times 10^5}{2 \times 10^2}\).
Simplify the coefficients: \(\frac{4}{2} = 2\).
Simplify the powers of 10: \(10^5 \div 10^2 = 10^3\).
Compute \(2 \times 10^3 = 2,000\).
Choice B results from incorrectly computing \(10^5 \div 10^2\) as \(10^4\) instead of \(10^3\), yielding 20,000.
Question 11 - Correct Answer: C
Round 897 to 900 and 1,123 to 1,100.
The numerator is approximately 900 + 1,100 = 2,000.
Round 52 to 50 and 11 to 10.
The denominator is approximately 50 - 10 = 40.
Compute \(\frac{2,000}{40} = 50\).
Choice D results from rounding the denominator to 52 - 10 = 42, then estimating \(\frac{2,000}{42}\) as approximately 48, and selecting the nearest value of 75 due to computational error.
Question 12 - Correct Answer: B
Round 4.93 to 5.
Round 2.08 to 2.
Compute \(\frac{5^2}{2} = \frac{25}{2} = 12.5\).
The value is approximately 12.
Choice A results from computing \(\frac{x \times y}{2}\) instead of \(\frac{x^2}{y}\).
Question 13 - Correct Answer: B
Round 0.487 to 0.5.
Round 0.0312 to 0.03.
Compute 0.5 × 0.03 = 0.015.
The product is closest to 0.015.
Choice C results from miscounting decimal places and computing 0.5 × 0.3 = 0.15 instead of recognizing 0.0312 as approximately 0.03.
Question 14 - Correct Answer: B
\(\sqrt{47}\) is slightly less than \(\sqrt{49} = 7\), approximately 6.9.
\(\sqrt{83}\) is slightly greater than \(\sqrt{81} = 9\), approximately 9.1.
Sum: 6.9 + 9.1 = 16.
A reasonable estimate is 16.
Choice C results from estimating \(\sqrt{47}\) as 7 and \(\sqrt{83}\) as 9.5, yielding 7 + 9.5 = 16.5, then rounding to 19.
Question 15 - Correct Answer: D
Round 287 to 300 and 193 to 200.
Perimeter = 2 × (length + width) = 2 × (300 + 200) = 2 × 500 = 1,000.
The best estimate is 1,000 meters.
Choice C results from computing 2 × 287 + 2 × 193 without proper rounding, yielding approximately 574 + 386 = 960.
Question 16 - Correct Answer: C
Round 1,892 to 2,000.
Round 21 to 20.
Compute 2,000 × 20 = 40,000.
Approximately 40,000 units are produced.
Choice B results from rounding 1,892 to 1,500 or 21 to 20, yielding 1,500 × 20 = 30,000.
Question 17 - Correct Answer: C
Round the radius 48.7 to 50.
Use \(\pi \approx 3\).
Compute \(C = 2 \times 3 \times 50 = 300\) cm.
The best estimate is 300 cm.
Choice B results from using \(\pi \approx 2.5\) or incorrectly multiplying, yielding approximately 250.
Question 18 - Correct Answer: B
Round 987 to 1,000.
Round 412 to 400.
Round 197 to 200.
Compute \(\frac{1,000 \times 400}{200} = \frac{400,000}{200} = 2,000\).
The value is closest to 2,000.
Choice A results from rounding 987 to 1,000 and 412 to 300, yielding \(\frac{1,000 \times 300}{200} = 1,500\).
Question 19 - Correct Answer: C
Round the cost $47.90 to $48.
Round 18% to 20%.
Compute 20% of 48: \(0.20 \times 48 = 9.60\), approximately $10.
Selling price = 48 + 10 = $58.
The closest estimate is $57.
Choice D results from computing 25% markup instead of 18%, yielding 48 + 12 = $60.
Question 20 - Correct Answer: A
Round 5.2 to 5, 3.8 to 4, and 9.7 to 10.
Compute \(\frac{5 \times 10^6 \times 4 \times 10^{-3}}{10 \times 10^2}\).
Multiply coefficients: \(5 \times 4 = 20\).
Combine powers of 10: \(10^6 \times 10^{-3} \div 10^2 = 10^{6-3-2} = 10^1 = 10\).
Compute \(\frac{20 \times 10}{10} = 20\).
The expression is approximately 20.
Choice B results from incorrectly computing the exponent as \(10^{6-3+2} = 10^5\), yielding \(\frac{20 \times 10^5}{10} = 200\).