CBSE Class 6  >  Class 6 Notes  >  Mathematics  >  RS Aggarwal Solutions: Decimals (Exercise 8D)

RS Aggarwal Solutions: Decimals (Exercise 8D)

Solution 1: 0.09 + 9.8 + 6.085
= 0.090 + 9.800 + 6.085 [Converting the given decimals to like decimals]
= 15.975

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 2: 0.85 + 9.548 + 2.6 + 3.47
= 0.850 + 9.548 + 2.600 + 3.470 [Converting the given decimals to like decimals]
= 16.468

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 3: 2.86 + 5.7 + 16.587 + 6.5
= 2.860 + 5.700 + 16.587 + 6.500 [Converting the given decimals to like decimals]
= 31.647

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 4: 4.069 + 3.96 + 6.8 + 2.071
= 4.069 + 3.960 + 6.800 + 2.071 [Converting the given decimals to like decimals]
= 16.900
= 16.9
Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 5: 6.62 + 8.069 + 5.8 + 7
= 6.620 + 8.069 + 5.800 + 7.000 [Converting the given decimals to like decimals]
= 27.489
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 6: 12.5 + 0.048 + 6.85 + 9
= 12.500 + 0.048 + 6.850 + 9.000 [Converting the given decimals to like decimals]
= 28.398
Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 7: 18.7 + 63.85 + 9.678 + 3.08
= 18.700 + 63.850 + 9.678 + 3.080 [Converting the given decimals to like decimals]
= 95.308
Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 8: 8.639 + 16.8 + 5 + 28.75
= 8.639 + 16.800 + 5.000 + 28.750 [Converting the given decimals to like decimals]
= 59.189

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 9: Earning for the first day = ₹462.50
Earning for the second day = ₹385.80
Earning for the third day = ₹507.70
∴ Total earning = ₹462.50 + ₹385.80 + ₹507.70
= ₹ 1356.00
Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 10: Cost of almirah = ₹ 11025
Cartage = ₹ 172.50
Cost of fitments = ₹ 64.80
∴ Total cost = ₹ 27085 + ₹ 292.70 + ₹ 164.80
= ₹ 27542.50
Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 11: Weight of sugar in a bag = 45 kg 80 g
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 45 kg + 0.080 kg
= 45.080 kg
Mass (weight) of empty bag = 950 g
= 950/1000 kg [∵ 1 kg = 1000g]
= 0.950 kg
∴ Total weight of the bag with sugar = 45 kg 80 g + 950 g
= 45.080 kg + 0.950 kg
= 46.030 kg

Working:

RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 12: Distance covered by taxi = 36 km 235 m
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 36 km + 0.235 km
= 36.235 km
Distance covered by Rickshaw = 4 km 85 m
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 4 km + 0.085 km

= 4.085 km

and distance covered on foot = 1 km 80 m

RS Aggarwal Solutions: Decimals (Exercise 8D)

= 1 km + 0.080 km
= 1.080 km

Total distance covered = 36.235 km + 4.085 km + 1.080 km

= 41.400 km

Working:

RS Aggarwal Solutions: Decimals (Exercise 8D)

Solution 13: Length of cloth for shirt = 2 m 70 cm
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 2 m + 0.70 m
= 2.70 m
Length of cloth for trouser = 3 m 5 cm
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 3 m + 0.05 m

= 3.05 m

∴ Total length of cloth by him = 2.70 m + 3.05 m

= 5.75 m

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 14: Walked in the morning = 2 km 35 m
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 2 km + 0.035 km

= 2.035 km

Walked in the evening = 1 km 7 m

RS Aggarwal Solutions: Decimals (Exercise 8D)

= 1 km + 0.007 km
= 1.007 km
∴ Total distance walked = 2.035 km + 1.007 km
= 3.042 km

Working:
RS Aggarwal Solutions: Decimals (Exercise 8D)


Solution 15: Rice purchased = 5 kg 650 g
RS Aggarwal Solutions: Decimals (Exercise 8D)

= 5 kg + 0.650 kg
= 5.650 kg
Sugar purchased = 2 kg 50 g

RS Aggarwal Solutions: Decimals (Exercise 8D)

= 2 kg + 0.050 kg
= 2.050 kg

Flour purchased = 10 kg 80 g

RS Aggarwal Solutions: Decimals (Exercise 8D)

= 10 kg + 0.080 kg

= 10.080 kg

∴ Total weight of her purchases = 5.650 kg + 2.050 kg + 10.080 kg

= 17.780 kg

Working:

RS Aggarwal Solutions: Decimals (Exercise 8D)

The document RS Aggarwal Solutions: Decimals (Exercise 8D) is a part of the Class 6 Course Mathematics for Class 6.
All you need of Class 6 at this link: Class 6

FAQs on RS Aggarwal Solutions: Decimals (Exercise 8D)

1. What are decimals and how are they used in everyday life?
Ans. Decimals are numbers that represent a part of a whole and are expressed using a decimal point. They are used in everyday life to handle money, measure distances, and express grades, among other applications. For example, when shopping, prices are often given in decimals, such as ₹99.99, indicating a fraction of a rupee.
2. How do you convert a fraction into a decimal?
Ans. To convert a fraction into a decimal, you divide the numerator (the top part of the fraction) by the denominator (the bottom part). For instance, to convert ¾ into a decimal, you would divide 3 by 4, which equals 0.75.
3. What is the significance of the place value in decimals?
Ans. Place value in decimals is significant because it determines the value of each digit in the number based on its position relative to the decimal point. For example, in the number 2.45, the digit 4 is in the tenths place and represents 0.4, while 5 is in the hundredths place and represents 0.05. This helps in understanding the size of numbers accurately.
4. How do you add and subtract decimals?
Ans. To add or subtract decimals, align the decimal points vertically and then perform the addition or subtraction as with whole numbers. It is important to fill in any empty places with zeros to keep the columns aligned. For example, to add 1.2 and 3.45, you would write them as: 1.20 + 3.45 This equals 4.65.
5. What are the rules for rounding decimals?
Ans. The rules for rounding decimals involve looking at the digit immediately to the right of the place value you want to round to. If this digit is 5 or greater, you round up; if it is less than 5, you round down. For example, rounding 2.67 to one decimal place would result in 2.7 because 7 is greater than 5.
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