Standard Form:
\[a_n(x)\frac{d^ny}{dx^n} + a_{n-1}(x)\frac{d^{n-1}y}{dx^{n-1}} + \cdots + a_1(x)\frac{dy}{dx} + a_0(x)y = g(x)\]Variables and Terms:
Form:
\[\frac{dy}{dx} = f(x)g(y)\]Solution Method:
\[\frac{dy}{g(y)} = f(x)dx\] \[\int \frac{dy}{g(y)} = \int f(x)dx + C\]Variables:
Standard Form:
\[\frac{dy}{dx} + P(x)y = Q(x)\]Integrating Factor Method:
\[\mu(x) = e^{\int P(x)dx}\]General Solution:
\[y = \frac{1}{\mu(x)}\left[\int \mu(x)Q(x)dx + C\right]\]Alternative Form:
\[y \cdot e^{\int P(x)dx} = \int Q(x)e^{\int P(x)dx}dx + C\]Variables:
Form:
\[M(x,y)dx + N(x,y)dy = 0\]Exactness Condition:
\[\frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}\]Solution Method: The solution F(x,y) = C is found where:
\[\frac{\partial F}{\partial x} = M(x,y)\] \[\frac{\partial F}{\partial y} = N(x,y)\]General Solution:
\[F(x,y) = \int M(x,y)dx + g(y) = C\]where g(y) is determined by ensuring ∂F/∂y = N(x,y)
Integrating Factor for Non-Exact Equations:
If \(\frac{1}{N}\left(\frac{\partial M}{\partial y} - \frac{\partial N}{\partial x}\right)\) is a function of x only:
\[\mu(x) = e^{\int \frac{1}{N}\left(\frac{\partial M}{\partial y} - \frac{\partial N}{\partial x}\right)dx}\]If \(\frac{1}{M}\left(\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}\right)\) is a function of y only:
\[\mu(y) = e^{\int \frac{1}{M}\left(\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}\right)dy}\]Form:
\[\frac{dy}{dx} + P(x)y = Q(x)y^n\]Substitution:
\[v = y^{1-n}\]Transformed Linear Equation:
\[\frac{dv}{dx} + (1-n)P(x)v = (1-n)Q(x)\]Variables:
Standard Form:
\[a\frac{d^2y}{dx^2} + b\frac{dy}{dx} + cy = f(x)\]Variables:
Characteristic Equation:
\[ar^2 + br + c = 0\]Characteristic Roots:
\[r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Discriminant:
\[\Delta = b^2 - 4ac\]Roots: \(r_1\) and \(r_2\) (both real and distinct)
\[y = C_1e^{r_1x} + C_2e^{r_2x}\]Root: \(r_1 = r_2 = r\)
\[y = (C_1 + C_2x)e^{rx}\]Roots: \(r = \alpha \pm i\beta\)
\[y = e^{\alpha x}(C_1\cos(\beta x) + C_2\sin(\beta x))\]Where:
\[\alpha = -\frac{b}{2a}\] \[\beta = \frac{\sqrt{4ac - b^2}}{2a}\]Variables:
General Solution Structure:
\[y = y_h + y_p\]Variables:
Applicable when: f(x) consists of polynomials, exponentials, sines, cosines, or their products
Form of Particular Solution Based on f(x):
Modification Rule: If any term in the assumed \(y_p\) duplicates a term in \(y_h\), multiply \(y_p\) by x (or \(x^2\) if necessary) until no duplication exists.
For equation:
\[y'' + p(x)y' + q(x)y = f(x)\]If homogeneous solutions are \(y_1\) and \(y_2\), particular solution:
\[y_p = u_1(x)y_1 + u_2(x)y_2\]Where:
\[u_1 = -\int \frac{y_2f(x)}{W}dx\] \[u_2 = \int \frac{y_1f(x)}{W}dx\]Wronskian:
\[W = \begin{vmatrix} y_1 & y_2 \\ y_1' & y_2' \end{vmatrix} = y_1y_2' - y_2y_1'\]Variables:
Standard Form:
\[a_n\frac{d^ny}{dx^n} + a_{n-1}\frac{d^{n-1}y}{dx^{n-1}} + \cdots + a_1\frac{dy}{dx} + a_0y = f(x)\]Characteristic Equation:
\[a_nr^n + a_{n-1}r^{n-1} + \cdots + a_1r + a_0 = 0\]Solution Rules:
Laplace Transform Definition:
\[\mathcal{L}\{f(t)\} = F(s) = \int_0^{\infty} e^{-st}f(t)dt\]Inverse Laplace Transform:
\[f(t) = \mathcal{L}^{-1}\{F(s)\}\]Variables:
Linearity:
\[\mathcal{L}\{af(t) + bg(t)\} = a\mathcal{L}\{f(t)\} + b\mathcal{L}\{g(t)\}\]First Derivative:
\[\mathcal{L}\{f'(t)\} = sF(s) - f(0)\]Second Derivative:
\[\mathcal{L}\{f''(t)\} = s^2F(s) - sf(0) - f'(0)\]n-th Derivative:
\[\mathcal{L}\{f^{(n)}(t)\} = s^nF(s) - s^{n-1}f(0) - s^{n-2}f'(0) - \cdots - f^{(n-1)}(0)\]Integration:
\[\mathcal{L}\left\{\int_0^t f(\tau)d\tau\right\} = \frac{F(s)}{s}\]First Shifting Theorem (s-shift):
\[\mathcal{L}\{e^{at}f(t)\} = F(s-a)\]Second Shifting Theorem (t-shift):
\[\mathcal{L}\{u(t-a)f(t-a)\} = e^{-as}F(s)\]where u(t-a) is the unit step function
Multiplication by t:
\[\mathcal{L}\{tf(t)\} = -\frac{dF(s)}{ds}\]Division by t:
\[\mathcal{L}\left\{\frac{f(t)}{t}\right\} = \int_s^{\infty}F(\sigma)d\sigma\]Convolution Theorem:
\[\mathcal{L}\{f(t) * g(t)\} = F(s)G(s)\]where the convolution is:
\[f(t) * g(t) = \int_0^t f(\tau)g(t-\tau)d\tau\]Definition:
\[u(t-a) = \begin{cases} 0, & t < a="" \\="" 1,="" &="" t="" \geq="" a="" \end{cases}\]="">Laplace Transform:
\[\mathcal{L}\{u(t-a)\} = \frac{e^{-as}}{s}\]Definition:
\[\delta(t-a) = \begin{cases} 0, & t \neq a \\ \infty, & t = a \end{cases}\]with the property:
\[\int_{-\infty}^{\infty}\delta(t-a)dt = 1\]Laplace Transform:
\[\mathcal{L}\{\delta(t-a)\} = e^{-as}\]General Procedure:
For equation:
\[ay'' + by' + cy = f(t)\]After taking Laplace transform:
\[a[s^2Y(s) - sy(0) - y'(0)] + b[sY(s) - y(0)] + cY(s) = F(s)\]Solve for Y(s):
\[Y(s) = \frac{F(s) + asy(0) + ay'(0) + by(0)}{as^2 + bs + c}\]General Form (2×2 system):
\[\frac{dx}{dt} = ax + by\] \[\frac{dy}{dt} = cx + dy\]Matrix Form:
\[\frac{d\mathbf{X}}{dt} = \mathbf{A}\mathbf{X}\]Where:
\[\mathbf{X} = \begin{bmatrix} x \\ y \end{bmatrix}, \quad \mathbf{A} = \begin{bmatrix} a & b \\ c & d \end{bmatrix}\]Characteristic Equation:
\[\det(\mathbf{A} - \lambda\mathbf{I}) = 0\]For 2×2 matrix:
\[(a-\lambda)(d-\lambda) - bc = 0\] \[\lambda^2 - (a+d)\lambda + (ad-bc) = 0\]Eigenvalues:
\[\lambda = \frac{(a+d) \pm \sqrt{(a+d)^2 - 4(ad-bc)}}{2}\]General Solution:
\[\mathbf{X} = C_1\mathbf{v}_1e^{\lambda_1 t} + C_2\mathbf{v}_2e^{\lambda_2 t}\]General Solution:
\[\mathbf{X} = C_1\mathbf{v}e^{\lambda t} + C_2(\mathbf{v}t + \mathbf{w})e^{\lambda t}\]General Solution:
\[\mathbf{X} = e^{\alpha t}[C_1(\mathbf{u}\cos(\beta t) - \mathbf{v}\sin(\beta t)) + C_2(\mathbf{u}\sin(\beta t) + \mathbf{v}\cos(\beta t))]\]Variables:
For system:
\[\frac{d\mathbf{X}}{dt} = \mathbf{A}\mathbf{X} + \mathbf{F}(t)\]Taking Laplace transform:
\[s\mathbf{X}(s) - \mathbf{X}(0) = \mathbf{A}\mathbf{X}(s) + \mathbf{F}(s)\]Solving for X(s):
\[\mathbf{X}(s) = (s\mathbf{I} - \mathbf{A})^{-1}[\mathbf{X}(0) + \mathbf{F}(s)]\]For initial value problem:
\[\frac{dy}{dx} = f(x,y), \quad y(x_0) = y_0\]Iterative Formula:
\[y_{n+1} = y_n + hf(x_n, y_n)\] \[x_{n+1} = x_n + h\]Variables:
Predictor:
\[y_{n+1}^* = y_n + hf(x_n, y_n)\]Corrector:
\[y_{n+1} = y_n + \frac{h}{2}[f(x_n, y_n) + f(x_{n+1}, y_{n+1}^*)]\]Variables:
Variables:
Assume solution of form:
\[y = \sum_{n=0}^{\infty}a_nx^n = a_0 + a_1x + a_2x^2 + a_3x^3 + \cdots\]Derivatives:
\[y' = \sum_{n=1}^{\infty}na_nx^{n-1}\] \[y'' = \sum_{n=2}^{\infty}n(n-1)a_nx^{n-2}\]Procedure:
For equations with regular singular point at x = 0:
\[y = x^r\sum_{n=0}^{\infty}a_nx^n = \sum_{n=0}^{\infty}a_nx^{n+r}\]Indicial Equation: Determines the exponent r by substituting the series into the differential equation and equating the coefficient of the lowest power of x to zero.
Variables:
Differential equation on interval [a, b]:
\[y'' + p(x)y' + q(x)y = f(x)\]With boundary conditions:
Sturm-Liouville Problem:
\[\frac{d}{dx}\left[p(x)\frac{dy}{dx}\right] + [q(x) + \lambda r(x)]y = 0\]With boundary conditions at x = a and x = b
Variables:
Form:
\[ax^2y'' + bxy' + cy = 0\]Substitution:
\[y = x^r\]Characteristic Equation:
\[ar(r-1) + br + c = 0\] \[ar^2 + (b-a)r + c = 0\]Standard Form:
\[x^2y'' + xy' + (x^2 - n^2)y = 0\]General Solution:
\[y = C_1J_n(x) + C_2Y_n(x)\]Variables:
Standard Form:
\[(1-x^2)y'' - 2xy' + n(n+1)y = 0\]General Solution:
\[y = C_1P_n(x) + C_2Q_n(x)\]Variables:
Spring-Mass-Damper System:
\[m\frac{d^2x}{dt^2} + c\frac{dx}{dt} + kx = F(t)\]Variables:
Natural Frequency:
\[\omega_n = \sqrt{\frac{k}{m}}\]Damping Ratio:
\[\zeta = \frac{c}{2\sqrt{km}} = \frac{c}{2m\omega_n}\]Damped Natural Frequency:
\[\omega_d = \omega_n\sqrt{1-\zeta^2}\]System Behavior:
Series RLC Circuit:
\[L\frac{d^2q}{dt^2} + R\frac{dq}{dt} + \frac{1}{C}q = E(t)\]Or in terms of current (i = dq/dt):
\[L\frac{di}{dt} + Ri + \frac{1}{C}\int i\,dt = E(t)\]Differentiated form:
\[L\frac{d^2i}{dt^2} + R\frac{di}{dt} + \frac{1}{C}i = \frac{dE(t)}{dt}\]Variables:
Natural Frequency:
\[\omega_n = \frac{1}{\sqrt{LC}}\]Damping Coefficient:
\[\alpha = \frac{R}{2L}\]Exponential Growth:
\[\frac{dP}{dt} = kP\] \[P(t) = P_0e^{kt}\]Logistic Growth:
\[\frac{dP}{dt} = kP\left(1 - \frac{P}{M}\right)\] \[P(t) = \frac{M}{1 + Ae^{-kt}}\]Where:
\[A = \frac{M - P_0}{P_0}\]Variables:
Newton's Law of Cooling:
\[\frac{dT}{dt} = -k(T - T_s)\]Solution:
\[T(t) = T_s + (T_0 - T_s)e^{-kt}\]Variables:
Tank with inflow and outflow:
\[\frac{dA}{dt} = \text{(rate in)} - \text{(rate out)}\] \[\frac{dA}{dt} = r_{in}c_{in} - r_{out}\frac{A(t)}{V(t)}\]Variables:
If rin = rout, then V(t) is constant