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Cheatsheet: Proportional Relationships

1. Understanding Proportional Relationships

1.1 Key Definitions

TermDefinition
Proportional RelationshipA relationship between two quantities where the ratio remains constant; y = kx where k ≠ 0
Constant of Proportionality (k)The constant ratio in a proportional relationship; k = y/x
RatioA comparison of two quantities; can be written as a:b, a/b, or a to b
Unit RateA ratio comparing a quantity to 1 unit of another quantity
OriginThe point (0,0) on a coordinate plane; all proportional relationships pass through the origin

1.2 Characteristics of Proportional Relationships

  • The graph is a straight line through the origin (0,0)
  • The ratio y/x is constant for all points
  • When one quantity is 0, the other is also 0
  • The equation is in the form y = kx (no y-intercept other than 0)
  • Doubling one quantity doubles the other quantity

2. Identifying Proportional Relationships

2.1 From Tables

MethodProcess
Calculate ratiosFind y/x for each row; if all ratios are equal, relationship is proportional
Check for (0,0)If the table includes x = 0, then y must equal 0 for proportional relationship

2.2 From Graphs

  • Graph must be a straight line
  • Line must pass through the origin (0,0)
  • If either condition is false, relationship is not proportional

2.3 From Equations

ProportionalNot Proportional
y = kx (k is a constant)y = kx + b where b ≠ 0
y = 5xy = 5x + 3
y = (2/3)xy = x²

2.4 From Verbal Descriptions

  • Look for phrases: "per", "each", "for every", "constant rate"
  • Check if relationship starts at zero
  • Example (proportional): "A car travels 60 miles per hour"
  • Example (not proportional): "A phone costs $50 plus $20 per month"

3. Finding the Constant of Proportionality

3.1 Formula

  • k = y/x (for any point except the origin)
  • k represents the unit rate
  • k is the slope of the line

3.2 From Different Representations

RepresentationHow to Find k
TablePick any row, divide y by x: k = y/x
GraphPick any point (x,y) on the line, calculate k = y/x or count rise/run from origin
Equation y = kxk is the coefficient of x
VerbalFind the unit rate (amount per 1 unit)

3.3 Example Calculations

  • If 3 pounds of apples cost $6, then k = 6/3 = 2 (dollars per pound)
  • If point (4, 12) is on the line, then k = 12/4 = 3
  • In equation y = 7x, k = 7

4. Writing Equations

4.1 Standard Form

  • All proportional relationships: y = kx
  • Where y is the dependent variable, x is the independent variable, k is the constant of proportionality

4.2 Steps to Write Equation

  1. Find the constant of proportionality k using k = y/x
  2. Substitute k into y = kx
  3. Simplify if needed

4.3 Example Problems

Given InformationEquation
Point (5, 20)k = 20/5 = 4; equation: y = 4x
6 gallons cost $18k = 18/6 = 3; equation: y = 3x (cost = 3 × gallons)
Unit rate of 2.5Equation: y = 2.5x

5. Graphing Proportional Relationships

5.1 Key Steps

  1. Plot the origin (0,0) first
  2. Find another point using k (if k = 3, use point (1,3) or any point satisfying y = kx)
  3. Draw a straight line through both points
  4. Extend the line in both directions

5.2 Using the Constant of Proportionality

  • k represents the slope (rise/run)
  • From origin, move right 1 unit, up k units to find point (1, k)
  • Example: If k = 2, plot (0,0) and (1,2)
  • Example: If k = 1/2, plot (0,0) and (2,1) for easier graphing

5.3 Reading Graphs

  • Identify any point (x,y) on the line
  • Calculate k = y/x
  • Write equation y = kx
  • Verify line passes through origin

6. Unit Rates and Comparisons

6.1 Unit Rate Definition

  • A ratio with denominator of 1
  • Same as the constant of proportionality
  • Expressed as "per 1 unit"

6.2 Calculating Unit Rates

SituationCalculation
$24 for 6 pounds24 ÷ 6 = $4 per pound
180 miles in 3 hours180 ÷ 3 = 60 miles per hour
12 pencils for $33 ÷ 12 = $0.25 per pencil OR 12 ÷ 3 = 4 pencils per dollar

6.3 Comparing Proportional Relationships

  • Compare constants of proportionality (k values)
  • Higher k means steeper line on graph
  • For costs: higher k means more expensive per unit
  • For speeds: higher k means faster rate

6.4 Example Comparison

  • Store A: 5 pounds for $15 (k = 15/5 = 3)
  • Store B: 8 pounds for $20 (k = 20/8 = 2.50)
  • Store B has lower unit rate, so better deal

7. Solving Problems

7.1 Problem-Solving Steps

  1. Identify the two quantities in the relationship
  2. Determine if relationship is proportional
  3. Find the constant of proportionality k
  4. Write equation y = kx
  5. Substitute known value to find unknown

7.2 Common Problem Types

Problem TypeApproach
Find missing value in tableCalculate k from known row, then use k to find missing value
Determine if proportionalCheck if all ratios y/x are equal and relationship includes (0,0)
Compare unit ratesCalculate k for each option and compare values
Write equation from descriptionIdentify unit rate from words, write as y = kx

7.3 Example Problem

  • Problem: If 4 tickets cost $50, how much do 7 tickets cost?
  • Find k: k = 50/4 = 12.5
  • Equation: y = 12.5x
  • Substitute: y = 12.5(7) = 87.5
  • Answer: 7 tickets cost $87.50

8. Common Mistakes to Avoid

8.1 Identifying Proportional Relationships

  • Mistake: Assuming all linear relationships are proportional
  • Remember: Line must pass through origin (0,0)
  • y = 2x + 5 is linear but NOT proportional (has y-intercept of 5)

8.2 Finding k

  • Mistake: Calculating x/y instead of y/x
  • Correct: k = y/x = dependent/independent
  • Be consistent with which variable is which

8.3 Graphing

  • Mistake: Forgetting to include (0,0)
  • Every proportional relationship must pass through origin
  • Use at least two points to draw the line

8.4 Writing Equations

  • Mistake: Adding extra terms (y = 3x + 2 instead of y = 3x)
  • Proportional equations only have form y = kx
  • No y-intercept other than 0

9. Key Formulas and Relationships

Formula/ConceptDescription
y = kxStandard form of proportional relationship
k = y/xFormula to find constant of proportionality
Unit Rate = kConstant of proportionality equals unit rate
Slope = kOn graph, slope of line equals constant of proportionality
(0,0) requiredAll proportional relationships include the origin

10. Quick Reference

10.1 Checklist for Proportional Relationships

  • ✓ Ratio y/x is constant
  • ✓ Graph is straight line through origin
  • ✓ Equation has form y = kx
  • ✓ No y-intercept (or y-intercept = 0)
  • ✓ When x = 0, y = 0

10.2 Converting Between Representations

FromTo
Table → EquationCalculate k = y/x, write y = kx
Equation → GraphPlot (0,0) and (1,k), draw line
Graph → EquationFind k from any point, write y = kx
Words → EquationFind unit rate = k, write y = kx
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