Q1: Define vital capacity. What is its significance?
Ans: Vital capacity is the maximum volume of air that can be expelled from the lungs after taking the deepest possible inspiration. In an average adult human, it is about 3.5-4.5 litres, though the exact value varies with age, sex, body size and physical conditioning.
Significance:
Vital Capacity Curve
Q2: State the volume of air remaining in the lungs after a normal breathing.
Ans: The volume of air remaining in the lungs after a normal expiration is called the functional residual capacity (FRC). It is the sum of:
Therefore, FRC = ERV + RV ≈ (1000-1500) + (1100-1500) mL ≈ 2500-3000 mL. This residual air prevents lung collapse and maintains continuous gas exchange between breaths.
Q3: Diffusion of gases occurs in the alveolar region only and not in the other parts of respiratory system. Why?
Ans:
Q4: What are the major transport mechanisms for CO2? Explain.
Ans: Carbon dioxide is transported from tissues to lungs by three main mechanisms. Plasma and red blood cells both participate.

(1) Dissolved in plasma: About ~7% of CO2 is carried dissolved directly in the plasma because CO2 is moderately soluble in water. Some CO2 also reacts with water to form carbonic acid (H2CO3), but this conversion is relatively slow without enzymatic help.
Since the uncatalysed formation of carbonic acid is slow, only a small fraction is present as dissolved gas.
(2) As carbaminohaemoglobin in RBCs: About 20-25% of CO2 is transported bound to haemoglobin, but not at the iron site. CO2 binds to the amino groups of the globin chains to form carbaminohaemoglobin. This form is reversible and releases CO2 at the lungs.
Transportation of CO2 through RBCs(3) As bicarbonate (HCO3-) - the major route: About ~70% of CO2 is transported as bicarbonate in plasma. In red blood cells, the enzyme carbonic anhydrase (a zinc-containing enzyme) rapidly catalyses:
CO2 + H2O ⇌ H2CO3 ⇌ H+ + HCO3-
Bicarbonate ions diffuse out of RBCs into plasma and are carried to lungs. To maintain electrical neutrality, chloride ions move into RBCs in exchange for bicarbonate (the chloride shift). At the lungs the reactions reverse and CO2 is released and exhaled.
Q5: What will be the pO2 and pCO2 in the atmospheric air compared to those in the alveolar air?
(i) pO2 lesser, pCO2 higher
(ii) pO2 higher, pCO2 lesser
(iii) pO2 higher, pCO2 higher
(iv) pO2 lesser, pCO2 lesser
Ans: (ii)
Explanation: Atmospheric air contains dry air with a high partial pressure of oxygen, about 159 mm Hg at sea level. By the time air reaches the alveoli, it is mixed with residual air, humidified and partly replaced by CO2 coming from blood; therefore alveolar pO2 is lower, approximately 104 mm Hg. Conversely, atmospheric pCO2 is very low (~0.3 mm Hg), while alveolar pCO2 is much higher (~40 mm Hg) because CO2 diffuses from blood into alveoli. These differences drive diffusion of O2 into blood and CO2 out of blood.
Q6: Explain the process of inspiration under normal conditions.
Ans:
Q7: How is respiration regulated?
Ans:
Q8: What is the effect of pCO2 on oxygen transport?
Ans: Partial pressure of carbon dioxide (pCO2) strongly influences how readily haemoglobin picks up or releases oxygen - a phenomenon closely related to the Bohr effect. Key points:
Q9: What happens to the respiratory process in a man going up a hill?
Ans: As altitude increases, the atmospheric partial pressure of oxygen (pO2) falls. Consequences include:
Q10: What is the site of gaseous exchange in an insect?
Ans: In insects gaseous exchange occurs through the tracheal system. Air enters the body through small external openings called spiracles, passes into larger tubes called tracheae and then into finer branches called tracheoles. The tracheoles reach very close to or into body cells and have thin walls, allowing direct diffusion of oxygen into cells and of carbon dioxide out. The spiracles can open and close to regulate airflow and reduce water loss.

The movement of carbon dioxide follows the reverse path. The CO2 from the cells of the body first enters the tracheae and then leaves the body through the spiracles.
Q11: Define oxygen dissociation curve. Can you suggest any reason for its sigmoidal pattern?
Ans:
The oxygen dissociation curve is a graph that shows the percentage saturation of haemoglobin with oxygen (oxyhaemoglobin) at different partial pressures of oxygen (pO2).

Q12: Have you heard about hypoxia? Try to gather information about it, and discuss with your friends.
Ans: Hypoxia is a condition in which tissues are not receiving adequate oxygen. It may arise from different causes and is classified into several types:

Hypoxemic hypoxia: Caused by low arterial pO2, for example at high altitudes or in lung diseases where gas exchange is impaired.
Anaemic hypoxia: Occurs when the oxygen-carrying capacity of blood is reduced due to low haemoglobin concentration or dysfunctional haemoglobin (for example, anaemia or CO poisoning).
Stagnant (ischaemic) hypoxia: Due to poor blood flow (reduced perfusion) so oxygen cannot reach tissues adequately - for example in heart failure or local ischaemia. Prolonged exposure to cold can also reduce circulation.
Histotoxic hypoxia: Tissues are unable to use available oxygen, often due to metabolic poisons such as cyanide or because of certain enzyme defects.
Q13: Distinguish between
(a) IRV and ERV
(b) Inspiratory capacity and Expiratory capacity
(c) Vital capacity and Total lung capacity
Ans: (a) IRV and ERV

(b) Inspiratory capacity and Expiratory capacity

(c) Vital capacity and Total lung capacity

Q14: What is Tidal volume? Find out the Tidal volume (approximate value) for a healthy human in an hour.
Ans: Tidal volume (TV) is the volume of air inspired or expired during a normal quiet breath. For an average healthy adult the tidal volume is about ~500 mL per breath.
To estimate the total tidal air moved in an hour, use a typical resting respiratory rate of 12-16 breaths per minute:
Minute ventilation = TV × respiratory rate ≈ 500 mL × (12-16) ≈ 6000-8000 mL/min (i.e. 6-8 L/min).
Tidal volume in an hour = 6-8 L/min × 60 min = 360-480 L = 3.6 × 105 to 4.8 × 105 mL.
Therefore, a healthy person at rest moves approximately 3.6 × 105 to 4.8 × 105 mL of tidal air in one hour, depending on breathing rate.
| 1. What is the process of breathing? | ![]() |
| 2. How does the exchange of gases occur in the lungs? | ![]() |
| 3. What are the main respiratory organs involved in breathing? | ![]() |
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| 5. What are some common respiratory disorders that affect breathing? | ![]() |