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NCERT Solutions Exercise 5.5: Continuity & Differentiability - Mathematics (Maths) for JEE Main & Advanced

Continuity & Differentiability 

Question 1: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 2: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Differentiating both sides with respect to x, we obtain 

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 3: Differentiate the function with respect to x. NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 4: Differentiate the function with respect to x. xx - 2sinx


Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
u = xx
Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 

Question 5: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 


Question 6: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Therefore, from (1), (2), and (3), we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced



Question 7: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 8: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Therefore, from (1), (2), and (3), we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 9: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer
Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 10: Differentiate the function with respect to x.

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 11: Differentiate the function with respect to x.
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Answer

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
 

Question 12:
 Find 
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced of function NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 13:

Find NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced



Question 14:
 Find NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced of function NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced .


Answer
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced



Question 15:
 Find 
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced  of function NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 16:
 Find the derivative of the function given by  
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced  and
 hence find 
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer
The given relationship is NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Question 17:
 Differentiate 
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced  in three ways mentioned below
 (i) By using product rule.
 (ii) By expanding the product to obtain a single polynomial.
 (iii By logarithmic differentiation.
 Do they all give the same answer?


Answer

Let y = NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
(i)

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


(ii)

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
 


( iii) NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Taking logarithm on both the sides, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Differentiating both sides with respect to x, we obtain

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

From the above three observations, it can be concluded that all the results of NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced  are same.

 Question 18: If u, v and w are functions of x, then show that

NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
in two ways-first by repeated application of product rule, second by logarithmic
 differentiation.


Answer
Let NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
By applying product rule, we obtain
NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

The document NCERT Solutions Exercise 5.5: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced is a part of the JEE Course Mathematics (Maths) for JEE Main & Advanced.
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FAQs on NCERT Solutions Exercise 5.5: Continuity & Differentiability - Mathematics (Maths) for JEE Main & Advanced

1. What is continuity in calculus?
Ans. Continuity refers to the property of a function where there are no abrupt jumps, breaks, or holes in the graph. It means that the function is smooth and can be drawn without lifting the pen from the paper. In simpler terms, a function is continuous if its graph can be traced without any interruptions.
2. What does differentiability mean in calculus?
Ans. Differentiability is a property of a function where it has a derivative at every point in its domain. It implies that the function is smooth and its graph doesn't have sharp turns or corners. A differentiable function can be approximated well by a straight line at any point on its graph.
3. How are continuity and differentiability related?
Ans. Continuity is a necessary condition for differentiability. If a function is differentiable at a point, then it must also be continuous at that point. However, continuity alone doesn't guarantee differentiability. A function can be continuous but not differentiable if there is a sharp corner or vertical tangent at a particular point.
4. How can we determine if a function is continuous?
Ans. To determine if a function is continuous, we need to check three conditions: 1. The function should be defined at the given point. 2. The limit of the function as it approaches the given point should exist. 3. The value of the function at the given point should be equal to the limit. If all three conditions are satisfied, then the function is continuous at that point.
5. How do we test for differentiability of a function?
Ans. To test for differentiability of a function, we need to check if the derivative exists at each point in its domain. The derivative can be calculated using differentiation rules or formulas. If the derivative exists for all points in the domain, then the function is differentiable. However, if there are any points where the derivative doesn't exist, then the function is not differentiable at those points.
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