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NCERT Solutions Exercise 5.6: Continuity & Differentiability - Mathematics (Maths) for JEE Main & Advanced

Continuity & Differentiability

 Question 1:
 If x and y are connected parametrically by the equation, without eliminating the

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 2: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.
 x = a cos θ, y = b cos θ


Answer
The given equations are x = a cos θ and y = b cos θ
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 3: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.
 x = sin t, y = cos 2t


Answer
The given equations are x = sin t and y = cos 2t

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 

Question 4:
 If x and y are connected parametrically by the equation, without eliminating the
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 5: If x and y are connected parametrically by the equation, without eliminating the 
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 Answer
The given equations are

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 6: If x and y are connected parametrically by the equation, without eliminating the

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer

The given equations are

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Question 7: If x and y are connected parametrically by the equation, without eliminating the

parameter,  find  NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer

The given equations are

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 

Question 8: If x and y are connected parametrically by the equation, without eliminating the

parameter, find NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer
The given equations are NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


 Question 9: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.



Answer

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

 


Question 10: If x and y are connected parametrically by the equation, without eliminating the

parameter, find  NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced.


Answer
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

Question 11:
 If 
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced


Answer
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced

NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced
Hence, proved.

The document NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics (Maths) for JEE Main & Advanced is a part of the JEE Course Mathematics (Maths) for JEE Main & Advanced.
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FAQs on NCERT Solutions Exercise 5.6: Continuity & Differentiability - Mathematics (Maths) for JEE Main & Advanced

1. What is continuity in calculus?
Ans. Continuity is a fundamental concept in calculus that describes the behavior of a function. A function is said to be continuous at a point if it is defined at that point and the limit of the function as it approaches that point exists and is equal to the value of the function at that point. In simpler terms, a function is continuous if there are no breaks, jumps, or holes in its graph.
2. How do you determine if a function is continuous or not?
Ans. To determine if a function is continuous or not, you need to check three conditions: 1) The function must be defined at the point in question. 2) The limit of the function as it approaches that point must exist. 3) The value of the function at that point must be equal to the limit. If all three conditions are satisfied, the function is continuous at that point. If any of the conditions are not satisfied, the function is not continuous at that point.
3. What is differentiability in calculus?
Ans. Differentiability is another important concept in calculus. A function is said to be differentiable at a point if it is continuous at that point and has a derivative at that point. The derivative of a function represents its rate of change or slope at any given point.
4. How do you determine if a function is differentiable or not?
Ans. To determine if a function is differentiable or not, you need to check two conditions: 1) The function must be continuous at the point in question. 2) The derivative of the function must exist at that point. If both conditions are satisfied, the function is differentiable at that point. If any of the conditions are not satisfied, the function is not differentiable at that point.
5. Can a function be continuous but not differentiable?
Ans. Yes, it is possible for a function to be continuous but not differentiable. This can occur at points where the function has sharp corners, cusps, or vertical tangents. These are points where the derivative does not exist, even though the function itself is continuous. An example of such a function is the absolute value function, |x|. It is continuous but not differentiable at x = 0.
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