Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  NCERT Solutions: Fractions & Decimals

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Exercise 2.1

Q1. Which of the drawings (a) to (d) show: 

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans:
(i) 2 × (1/5) represents the addition of 2 figures, each represents 1 shaded part out of the given 5 equal parts.
∴ 2 × (1/5) is represented by fig (d).
(ii) 2 × ½ represents the addition of 2 figures, each represents 1 shaded part out of the given 2 equal parts.
∴ 2 × ½ is represented by fig (b).
(iii) 3 × (2/3) represents the addition of 3 figures, each represents 2 shaded part out of the given 3 equal parts.
∴ 3 × (2/3) is represented by fig (a).
(iii) 3 × ¼ represents the addition of 3 figures, each represents 1 shaded part out of the given 4 equal parts.
∴ 3 × ¼ is represented by fig (c).


Q2. Some pictures (a) to (c) are given below. Tell which of them show:

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans:

(i) 3 × (1/5) represents the addition of 3 figures, each represents 1 shaded part out of the given 5 equal parts and (3/5) represents 3 shaded parts out of 5 equal parts.
∴ 3 × (1/5) = (3/5) is represented by fig (c).
(ii) 2 × (1/3) represents the addition of 2 figures, each represents 1 shaded part out of the given 3 equal parts and (2/3) represents 2 shaded parts out of 3 equal parts.
∴ 2 × (1/3) = (2/3) is represented by fig (a).
(iii) 3 × (3/4) represents the addition of 3 figures, each represents 3 shaded part out of the given 4 equal parts and 2 ¼ represents 2 fully and 1 figure having 1 part as shaded out of 4 equal parts.
∴ 3 × (3/4) = 2 ¼ is represented by fig (b)


Q3. Multiply and reduce to lowest form and convert into a mixed fraction: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (7/1) × (3/5)
= (7 × 3)/ (1 × 5)
= (21/5)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (4/1) × (1/3)
= (4 × 1)/ (1 × 3)
= (4/3)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (2/1) × (6/7)
= (2 × 6)/ (1 × 7)
= (12/7)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iv) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (5/1) × (2/9)
= (5 × 2)/ (1 × 9)
= (10/9)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (2/3) × (4/1)
= (2 × 4)/ (3 × 1)
= (8/3)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (5/2) × (6/1)
= (5 × 6)/ (2 × 1)
= (30/2)
= 15

(vii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (11/1) × (4/7)
= (11 × 4)/ (1 × 7)
= (44/7)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(viii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (20/1) × (4/5)
= (20 × 4)/ (1 × 5)
= (80/5)
= 16

(ix) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (13/1) × (1/3)
= (13 × 1)/ (1 × 3)
= (13/3)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(x) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (15/1) × (3/5)
= (15 × 3)/ (1 × 5)
= (45/5)
= 9


Q4. Shade:

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: (i) From the question,
We may observe that there are 12 circles in the given box. So, we have to shade ½ of the circles in the box.
∴ 12 × ½ = 12/2
 = 6
So we have to shade any 6 circles in the box.
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) From the question,
We may observe that there are 9 triangles in the given box. So, we have to shade 2/3 of the triangles in the box.
∴ 9 × (2/3) = 18/3
 = 6
So we have to shade any 6 triangles in the box.
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii) From the question,
We may observe that there are 15 squares in the given box. So, we have to shade 3/5 of the squares in the box.
∴ 15 × (3/5) = 45/5
 = 9
So we have to shade any 9 squares in the box.
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q5. Find: 
(a) 1/2 of (i) 24 (ii) 46

Ans: (i) 24
We have,
= ½ × 24
= 24/2
= 12

(ii) 46
We have,
= ½ × 46
= 46/2
= 23

(b) 2/3 of (i) 18 (ii) 27

Ans: (i) 18
We have,
= 2/3 × 18
= 2 × 6
= 12

(ii) 27
We have,
= 2/3 × 27
= 2 × 9
= 18

(c) 3/4 of  (i) 16 (ii) 36

Ans: (i) 16
We have,
= ¾ × 16
= 3 × 4
= 12

(ii) 36
We have
= ¾ × 36
= 3 × 9
= 27

(d) 4/5 of (i) 20 (ii) 35

Ans: (i) 20
We have,
= 4/5 × 20
= 4 × 4
= 16

(ii) 35
We have,
= 4/5 × 35
= 4 × 7
= 28


Q6. Multiply and express as a mixed fraction: 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 26/5
Now,= 3 × (26/5)
= 78/5
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= 6 ¾ = 27/4
Now,
= 5 × (27/4)
= 135/4
= 33 ¾ 

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= 2 ¼ = 9/4
Now,
= 7 × (9/4)
= 63/4
= 15 ¾ 

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 19/3
Now,
= 4 × (19/3)
= 76/3
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= 3 ¼ = 13/4
Now,
= (13/4) × 6
= (13/2) × 3
= 39/2
= 19 ½ 

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert the given mixed fraction into improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)  = 17/5
Now,
= (17/5) × 8
= 136/5
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q7. Find:
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: (i) First convert the given mixed fraction into an improper fraction.
= 2 ¾ = 11/4
Now,
= ½ × 11/4
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= ½ × (11/4)
= (1 × 11)/ (2 × 4)
= (11/8)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) First convert the given mixed fraction into improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 38/9
Now,
= ½ × (38/9)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= ½ × (38/9)
= (1 × 38)/ (2 × 9)
= (38/18)
= 19/9
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: (i) First convert the given mixed fraction into an improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) = 23/6
Now,
= (5/8) × (23/6)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (5/8) × (23/6)
= (5 × 23)/ (8 × 6)
= (115/48)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) First convert the given mixed fraction into improper fraction.
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) = 29/3
Now,
= (5/8) × (29/3)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
= (5/8) × (29/3)
= (5 × 29)/ (8 × 3)
= (145/24)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q8. Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed 2/5 of the water. Pratap consumed the remaining water. 
(i) How much water did Vidya drink? 
(ii) What fraction of the total quantity of water did Pratap drink? 

Ans: (i) From the question, it is given that,
Amount of water in the water bottle = 5 liters
Amount of water consumed by Vidya = 2/5 of 5 liters
= (2/5) × 5
= 2 liters
So, the total amount of water drank by Vidya is 2 liters

(ii) From the question, it is given that,
Amount of water in the water bottle = 5 liters
Then,
Amount of water consumed by Pratap = (1 – water consumed by Vidya)
= (1 – (2/5))
= (5-2)/5
= 3/5
∴ Total amount of water consumed by Pratap = 3/5 of 5 liters
 = (3/5) × 5
 = 3 liters
So, the total amount of water drank by Pratap is 3 liters


Deleted Exercise

Q1. Solve:
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: For subtraction of two unlike fractions, first change them to the like fractions.
LCM of 1, 5 = 5
Now, let us change each of the given fraction into an equivalent fraction having 5 as the denominator.
= [(2/1) × (5/5)] = (10/5)
= [(3/5) × (1/1)] = (3/5)
Now,
= (10/5) - (3/5)
= [(10 – 3)/5]
= (7/5)


(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: For the addition of two unlike fractions, first change them to the like fractions.
LCM of 1, 8 = 8
Now, let us change each of the given fraction into an equivalent fraction having 8 as the denominator.
= [(4/1) × (8/8)] = (32/8)
= [(7/8) × (1/1)] = (7/8)
Now,
= (32/8) + (7/8)
= [(32 + 7)/8]
= (39/8)


(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: For the addition of two unlike fractions, first change them to the like fractions.
LCM of 5, 7 = 35
Now, let us change each of the given fraction into an equivalent fraction having 35 as the denominator
= [(3/5) × (7/7)] = (21/35)
= [(2/7) × (5/5)] = (10/35)
Now,
= (21/35) + (10/35)
= [(21 + 10)/35]
= (31/35)


(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: For subtraction of two, unlike fractions, first, change them to the like fractions.
LCM of 11, 15 = 165
Now, let us change each of the given fraction into an equivalent fraction having 165 as the denominator.
= [(9/11) × (15/15)] = (135/165)
= [(4/15) × (11/11)] = (44/165)
Now,
= (135/165) - (44/165)
= [(135 – 44)/165]
= (91/165)


(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: For the addition of two unlike fractions, first change them to the like fractions.
LCM of 10, 5, 2 = 10
Now, let us change each of the given fraction into an equivalent fraction having 35 as the denominator.
= [(7/10) × (1/1)] = (7/10)
= [(2/5) × (2/2)] = (4/10)
= [(3/2) × (5/5)] = (15/10)
Now,
= (7/10) + (4/10) + (15/10)
= [(7 + 4 + 15)/10]
= (26/10)
= (13/5)


(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert mixed fraction into improper fraction,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 8/3
= 3 ½
= 7/2
For the addition of two unlike fractions, first, change them to the like fractions.
LCM of 3, 2 = 6
Now, let us change each of the given fraction into an equivalent fraction having 6 as the denominator.
= [(8/3) × (2/2)] = (16/6)
= [(7/2) × (3/3)] = (21/6)
Now,
= (16/6) + (21/6)
= [(16 + 21)/6]
= (37/6)


(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: First convert mixed fraction into improper fraction,
= 8 ½ = 17/2
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) = 29/8
For the Subtraction of two, unlike fractions, first, change them to the like fractions.
LCM of 2, 8 = 8
Now, let us change each of the given fraction into an equivalent fraction having 35 as the denominator.
= [(17/2) × (4/4)] = (68/8)
= [(29/8) × (1/1)] = (29/8)
Now,
= (68/8) - (29/8)
= [(68 - 29)/8]
= (39/8)


Q2. Arrange the following in descending order:
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: (i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
[Converting into like fractions]
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
[Arranging in descending order]
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Therefore,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
[Converting into like fractions]
⇒  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) 
[Arranging in descending order]
⇒  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)   
Therefore,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q3. In a “magic square”, the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: Sum of first row NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of second row  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of third row  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of first column  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of second column  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of third column  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of first diagonal [left to right) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Sum of second diagonal [left to right]  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Since the sum of fractions in each row, in each column and along the diagonals are same, therefore it is a magic square.


Q4. A rectangular sheet of paper is NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) cm wide. Find its perimeter. 

Ans: Given: The sheet of paper is in rectangular form.
Length of sheet =NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)  cm and Breadth of sheetNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) cm
Perimeter of rectangle = 2 (length + breadth)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, the perimeter of the rectangular sheet is NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q5. Find the perimeter of 
(i) ΔABE 
(ii) the rectangle BCDE in this figure. 
Whose perimeter is greater?

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: (i) In ΔABE NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
The perimeter of ΔABE = AB + BE + AE

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
= NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, the perimeter of ΔABE isNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)cm

(ii) In rectangle BCDE,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Perimeter of rectangle = 2 [length + breadth]

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, the perimeter of rectangle BCDE isNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Comparing the perimeter of triangle and that of rectangle,

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Therefore, the perimeter of triangle ABE is greater than that of rectangle BCDE.


Q6. Salil wants to put a picture in a frame. The picture is NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) cm wide. To fit in the frame the picture cannot be more thanNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) cm wide. How much should the picture be trimmed?

Ans: Given: The width of the pictureNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
and the width of picture frame NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Therefore, the picture should be trimmed
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, the picture should be trimmed by  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q7. Ritu ate 3/5 part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? Who had the larger share? By how much? 

Ans: The part of an apple eaten by Ritu = 3/5
The part of an apple eaten by Somu NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Comparing the parts of apple eaten by both Ritu and Somu  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
The larger share will be more b NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, Ritu's part is 1/5 more than Somu’s part.


Q8. Michael finished colouring a picture in 7/12 hour. Vaibhav finished colouring the same picture in 3/4 hour. Who worked longer? By what fraction was it longer? 

Ans: Time is taken by Michael to colour the picture = 7/2 hour
Time is taken by Vaibhav to colour the picture = 3/4 hour
Converting both fractions in like fractions,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Here, NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, Vaibhav worked longer time.
Vaibhav worked longer time by NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, Vaibhav took 1/6 hour more than Michael.

Exercise 2.2

Fractions and Decimals Fractions and Decimals 

Q1. Find: 
(i) 1/4 of 
(a) 1/4 
(b) 3/5 
(c) 4/3
(ii) 1/7 of 

(a) 2/9 
(b) 6/5 
(c) 3/10

Ans: 
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
(i)
 (a) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(b)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(c)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii)
 (a)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(b)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(c)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q2: Multiply and reduce to lowest form (if possible): 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans:
(i) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 8/3,

By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii) By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iv) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vii) By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Multiplying FractionMultiplying FractionQ3. Multiply the following fractions: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: 
(i) First convert the given mixed fraction into improper fraction.
= 5 ¼ = 21/4
Now,
= (2/5) × (21/4)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


(ii) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 32/5Now,= (32/5) × (7/9)

By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then, 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii) First, convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 16/3
Now,
= (3/2) × (16/3)
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv) First convert the given mixed fraction into an improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 17/7
Now,
= (5/6) × (17/7)
By the rule Multiplication of fractions,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 17/5
Now,
= (17/5) × (4/7)

By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 13/5
Now,
= (13/5) × (3/1)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vii) First convert the given mixed fraction into improper fraction.
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 25/7
Now,
= (25/7) × (3/5)
By the rule Multiplication of fraction,
Product of fraction = (product of numerator)/ (product of denominator)
Then,  
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q4. Which is greater: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
⇒  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
⇒   NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
⇒   NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q5. Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 3/4 m. Find the distance between the first and the last sapling.

Ans: The distance between two adjacent saplings = 3/4 m
Saili planted 4 saplings in a row, then number of gap in saplings = 3
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Therefore,
The distance between the first and the last saplings  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus the distance between the first and the last saplings is NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q6. Lipika reads a book forNCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)hours every day. She reads the entire book in 6 days. How many hours in ail were required by her to read the book?

Ans: Time is taken by Lipika to read a book = NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)hours
She reads the entire book in 6 days.
Now, the total hours are taken by her to read the entire book  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, 10 hours were required by her to read the book.  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q7. A car runs 16 km using 1 litre of petrol. How much distance will it cover using  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)of petrol?

Ans: In 1 litre of petrol, car covers the distance = 16 km
In NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)litres of petrol, car covers the distance =  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, the car will cover 44 km distance.


Q8. 
(a) 
(i) Provide the number in the box 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) The simplest form of the number obtained in NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(b)
 (i) Provide the number in the box
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) The simplest form of the number obtained in NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans:
 (a)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) The simplest form NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(b)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) The simplest form NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Exercise 2.3 

Q1.
Find: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: 
(i) We have,
= 12 × reciprocal of ¾

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii) We have,
= 14 × reciprocal of (5/6)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii) We have,
= 8× reciprocal of (7/3)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iv) We have,
= 4 × reciprocal of (8/3)

 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v) While dividing a whole number by a mixed fraction, first convert the mixed fraction into improper fraction We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 7/3
Then,
= 3 ÷ (7/3)
= 3 × reciprocal of (7/3)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi) While dividing a whole number by a mixed fraction, first convert the mixed fraction into improper fraction We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 25/7
Then,
= 5 ÷ (25/7)
= 5 × reciprocal of (25/7)   
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

(i) 3/7
Ans: Reciprocal of (3/7) is (7/3) [∵ ((3/7) × (7/3)) = 1]
So, it is an improper fraction.
Improper fraction is that fraction in which numerator is greater than its denominator.
(ii) 5/8
Ans: Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]
So, it is an improper fraction.
Improper fraction is that fraction in which numerator is greater than its denominator.
(iii) 9/7
Ans: Reciprocal of (9/7) is (7/9) [∵ ((9/7) × (7/9)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(iv) 6/5
Ans: Reciprocal of (6/5) is (5/6) [∵ ((6/5) × (5/6)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(v) 12/7
Ans: Reciprocal of (12/7) is (7/12) [∵ ((12/7) × (7/12)) = 1]
So, it is a proper fraction.
A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.
(vi) 1/8
Ans: Reciprocal of (1/8) is (8/1) or 8 [∵ ((1/8) × (8/1)) = 1]
So, it is a whole number.
Whole numbers are collection of all positive integers including 0.
(vii) 1/11
Ans: Reciprocal of (1/11) is (11/1) or 11 [∵ ((1/11) × (11/1)) = 1]
So, it is a whole number.
Whole numbers are collection of all positive integers including 0.


Q3. Find: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: 
(i) We have,
= (7/3) × reciprocal of 2
= (7/3) × (1/2)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) We have,
= (4/9) × reciprocal of 5
= (4/9) × (1/5)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii) We have,
= (6/13) × reciprocal of 7
= (6/13) × (1/7)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iv) First convert the mixed fraction into improper fraction. We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 13/3 Then,
= (13/3) × reciprocal of 3

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v) First convert the mixed fraction into improper fraction.
We have,
= 3 ½ = 7/2
Then,
= (7/2) × reciprocal of 4

 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi) First convert the mixed fraction into improper fraction.
We have,

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 31/7
Then,
= (31/7) × reciprocal of 7

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q4.  Find 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

(viii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Ans: 
(i) We have,
= (2/5) × reciprocal of ½
= (2/5) × (2/1)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) We have,
= (4/9) × reciprocal of (2/3)
= (4/9) × (3/2)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii) We have,
= (3/7) × reciprocal of (8/7)
= (3/7) × (7/8)
  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 7/3
Then,
= (7/3) × reciprocal of (3/5)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v) First convert the mixed fraction into improper fraction.
We have,
= 3 ½ = 7/2
Then,
= (7/2) × reciprocal of (8/3)
= (7/2) × (3/8)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi) First convert the mixed fraction into improper fraction.
We have,
= 1 ½ = 3/2
Then,
= (2/5) × reciprocal of (3/2)

= (2/5) × (2/3)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 16/5

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 5/3Then,= (16/5) × reciprocal of (5/3)= (16/5) × (3/5)

  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(viii) First convert the mixed fraction into improper fraction.
We have,
=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 11/5

=NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 6/5
Then,
= (11/5) × reciprocal of (6/5)
= (11/5) × (5/6)
 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Exercise 2.4 

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Q1. 
Find: 
(i) 0.2 x 6 
(ii) 8 x 4.6 
(iii) 2.71 x 5 
(iv) 20.1 x 4 
(v) 0.05 x 7 
(vi) 211.02 x 4 
(vii) 2 x 0.86 

Ans: 
(i) 0.2 x 6 = 1.2
(ii) 8 x 4.6 = 36.8
(iii) 2.71 x 5 = 13.55
(iv) 20.1 x 4 = 80.4
(v) 0.05 x 7 = 0.35
(vi) 211.02 x 4 = 844.08
(vii) 2 x 0.86 = 1.72


Q2. Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm. 

Ans: Given: Length of rectangle = 5.7 cm and
Breadth of rectangle = 3 cm
Area of rectangle = Length x Breadth = 5.7 x 3 = 17.1 cm2
Thus, the area of rectangle is 17.1 cm2.


Q3. Find: 
(i) 1.3 x 10 
(ii) 36.8 x 10 
(iii) 153.7 x 10 
(iv) 168.07 x 10 
(v) 31.1 x 100 
(vi) 156.1 x 100
(vii) 3.62 x 100 
(viii) 43.07 x 100 
(ix) 0.5 x 10
(x) 0.08 x 10 
(xi) 0.9 x 100 
(xii) 0.03 x 1000 

Ans:
(i) 1.3 x 10 = 13.0
(ii) 36.8 x 10 = 368.0
(iii) 153.7 x 10 = 1537.0
(iv) 168.07 x 10 = 1680.7
(v) 31.1 x 100 = 3110.0
(vi) 156.1 x 100 = 15610.0
(vii) 3.62 x 100 = 362.0
(viii) 43.07 x 100 = 4307.0
(ix) 0.5 x 10 = 5.0
(x) 0.08 x 10 = 0.80
(xi) 0.9 x 100 = 90.0
(xii) 0.03 x 1000 = 30.0


Q4. A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol? 

Ans: ∵ In one litre, a two-wheeler covers a distance = 55.3 km
∴ In 10 litres, a two- wheeler covers a distance = 55.3x10 = 553.0 km
Thus, 553 km distance will be covered by it in 10 litres of petrol.


Q5. Find: 
(i) 2.5 x 0.3 
(ii) 0.1 x 51.7 
(iii) 0.2 x 316.8 
(iv) 1.3 x 3.1 
(v) 0.5 x 0.05 
(vi) 11.2 x 0.15 
(vii) 1.07 x 0.02 
(viii) 10.05 x 1.05 
(ix) 101.01 x 0.01 
(x) 100.01 x 1.1 

Ans: 
(i) 2.5 x 0.3 = 0.75
(ii)  0.1 x 51.7 = 5.17
(iii) 0.2 x 316.8 = 63.36
(iv) 1.3 x 3.1=4.03
(v) 0.5 x 0.05 =0.025
(vi) 11.2 x 0.15 = 1.680
(vii) 1.07 x 0.02 = 0.0214
(viii) 10.05 x 1.05 = 10.5525
(ix) 101.01 x 0.01 = 1.0101
(x) 100.01 x1.1=110.11


Exercise 2.5 

Q1. Find: 
(i) 0.4 ÷ 2
(ii) 0.35 ÷ 5
(iii) 2.48 ÷ 4
(iv) 65.4 ÷ 6
(v)  651.2 ÷ 4
(v)  14.49 ÷ 7
(vii) 3.96 ÷ 4
(viii) 0.80 ÷ 5

Ans: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(viii)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q2. Find: 
(i) 4.8 ÷ 10
(ii) 52.5 ÷ 10
(iii) 0.7 ÷ 10
(iv) 33.1 ÷ 10
(v) 272.23 ÷ 10
(vi) 0.56 ÷ 10
(vii) 3.97 ÷ 10

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q3. Find: 
(i) 2.7 ÷ 100
(ii)  0.3 ÷ 100
(iii) 0.78 ÷ 100
(iv) 432.6 ÷ 100
(v) 23.6 ÷ 100
(vi) 98.53 ÷ 100

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q4. Find: 
(i) 7.9 ÷ 1000 
(ii)  26.3 ÷ 1000 
(iii) 38.53 ÷ 1000
(iv) 128.9 ÷ 1000 
(v)  0.5 ÷ 1000

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q5. Find: 
(i) 7÷ 3.5 
(ii)  36 ÷ 0.2 
(iii)  3.25  ÷  0.5
(iv)  30.94 ÷ 0.7 
(v)  0.5 ÷ 0.25 
(vi)  7.75  ÷  0.25
(vii) 76.5 ÷ 0.15 
(viii)  37.8 ÷1.4 
(ix)  2.73  ÷  1.3

Ans: 
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vi)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(vii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(viii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ix) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q6. A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre petrol?

Ans:
∵ In 2.4 litres of petrol, distance covered by the vehicle = 43.2 km
∴ In 1 litre of petrol, distance covered by the vehicle = 43.2 ÷2.4
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Thus, it covered 18 km distance in one litre of petrol.


Deleted Exercise 

Q1: Which is greater: 
(i) 0.5 or 0.05 
(ii) 0.7or 0.5 
(iii) 7 or 0.7
(iv) 1.37 or 1.49 
(v)  3.03 or 2.30 
(vi) 0.8 or 0.88
Ans: 
(i)  0.5 > 0.05    
(ii)  0.7 > 0.5
(iii) 7 >0.7
(iv) 1.37 <1.49
(v)  2.03 < 2.30
(vi) 0.8 <0.88

Q2: Express as rupees using decimals: 
(i) 7 paise 
(ii) 7 rupees 7 paise 
(iii) 77 rupees 77 paise 
(iv) 50 paise 
(v) 235 paise 
Ans: We know that,
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(i)NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q3:
 (i) Express 5 cm in metre and kilometre. 
(ii) Express 35 mm in cm, m and km. 
Ans: 
(i) Express 5 cm in meter and kilometer.
We know that, 100 cm = 1 meter
∴ 1 cm = 1/100 meter
⇒ 5 cm = 5/100 = 0.05 meter
Now,
∴ 1000 meters = 1 kilometers
∴ 1 meters = 1/1000 kilometer
⇒ 0.05 meter = 0.05/1000 = 0.00005 kilometer
(ii) Express 35 mm in cm, m and km.
∵ 10 mm = 1 cm
∴ 1 mm  = 1/10 cm
⇒ 35 mm = 35/100 = 3.5 cm
Now, ∵ 100 cm = 1 meter
∴ 1 cm = 1/100 meter
⇒ 3.5 cm  = 3.5/100 = 0.035 meter
Again,
∵ 1000 meters = 1 kilometers
∴ 1 meter = 1/1000 kilometers
⇒ 0.035 meter = 0.035/1000 = 0.000035 kilometer

Q4:  Express in kg. 
(i) 200 g 
(ii) 3470 g 
(iii) 4 kg 8 g 
Ans: 
Let us consider, 1000 g = 1 kg

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  4kg 8 g = NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)= 5 kg + 0.008 kg = 4.005 kg

Q5: Write the following decimal numbers in the expanded form: 
(i) 20.03 
(ii) 2.03 
(iii) 200.03 
(iv) 2.034 
Ans: 
(i) NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(ii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iii)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv)  NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)


Q6: Write the place value of 2 in the following decimal numbers: 
(i) 2.56 
(ii) 21.37 
(iii) 10.25 
(iv) 9.42
(v) 63.352
Ans: 
(i) Place value of 2 in 2.56 = 2 x 1 = 2 ones
(ii)  Place value of 2 in 21.37 = 2 x 10 = 2 tens
(iii) Place value of 2 in 10.25 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(iv) Place value of 2 in 9.42 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
(v) Place value of 2 in 63.352 NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Q7: Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much? 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)
Ans: 
NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

Distance travelled by Dinesh when he went from place A to place B = 7.5 km and from place B to C = 12.7 km.
Total distance covered by Dinesh = AB + BC
= 7.5 + 12.7
= 20.2 km
Total distance covered by Ayub = AD + DC
= 9.3 + 11.8
= 21.1 km
On comparing the total distance of Ayub and Dinesh,
21.1 km > 20.2 km
Therefore, Ayub covered more distance by 21.1 – 20.2 = 0.9 km = 900 m
∴Ayub travelled 0.9 km more than Dinesh. 

Q8: Shyam bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits? 
Ans: From the question, it is given that, Fruits bought by Shyama = 5 kg 300 g

= 5 kg + (300/1000) kg
= 5 kg + 0.3 kg
= 5.3 kg
Fruits bought by Sarala = 4 kg 800 g + 4 kg 150 g
= (4 + (800/1000)) + (4 + (150/1000))
= (4 + 0.8) kg + (4 + .150) kg
= 4.8 kg + 4.150kg
= 8.950 kg
So, Sarala bought more fruits.

Q9: How much less is 28 km than 42.6 km? 
Ans: 
We have to find the difference between 42.6 km and 28 km.
Difference = 42.6 – 28.0 = 14.6 km
Therefore,14.6 km less is 28 km than 42.6 km.

The document NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1) is a part of the Class 7 Course Mathematics (Maths) Class 7.
All you need of Class 7 at this link: Class 7
76 videos|345 docs|39 tests

Up next

FAQs on NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

1. What is the difference between fractions and decimals?
Ans. Fractions represent parts of a whole, while decimals represent parts of a whole divided into tenths, hundredths, etc. Fractions are written as a numerator over a denominator, while decimals are written using the decimal point.
2. How can fractions and decimals be converted into each other?
Ans. To convert a fraction to a decimal, divide the numerator by the denominator. To convert a decimal to a fraction, write the decimal as a fraction with the decimal as the numerator and a power of 10 as the denominator.
3. How are fractions and decimals used in everyday life?
Ans. Fractions and decimals are used in everyday life for tasks such as cooking, measuring, shopping, and calculating percentages. They are essential for understanding quantities and proportions.
4. What are some common operations involving fractions and decimals?
Ans. Common operations involving fractions and decimals include addition, subtraction, multiplication, and division. It is important to understand how to perform these operations accurately.
5. How can fractions and decimals be simplified or reduced?
Ans. To simplify a fraction, find the greatest common factor of the numerator and denominator and divide both by it. To reduce a decimal, round it to the desired decimal place or convert it back to a fraction and simplify.
76 videos|345 docs|39 tests
Download as PDF

Up next

Explore Courses for Class 7 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Important questions

,

past year papers

,

video lectures

,

mock tests for examination

,

shortcuts and tricks

,

Free

,

Sample Paper

,

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

,

Viva Questions

,

Summary

,

study material

,

Previous Year Questions with Solutions

,

MCQs

,

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

,

Extra Questions

,

Objective type Questions

,

pdf

,

Exam

,

NCERT Solutions for Class 8 Maths - Fractions and Decimals (Exercise 2.1)

,

Semester Notes

,

ppt

,

practice quizzes

;