Impulse of Jets | Mechanical Engineering SSC JE (Technical) PDF Download

IMPULSE OF JETS

  • Jet Strikes normal to the flat stationary plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

Force exerted by the jet normal to the plate
P= ρaV2
a = area of jet
V = velocity of jet 

  • Jet strikes on a inclined stationary plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

  • Force exerted by the jet normal to the plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

  •  Force exerted by jet on moving flat plate normal to jet.

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

u = plate velocity
Pn  = ρa(V – u)2
Work done per second (W) = Pn × u = ra[V – u]2 × u 

  • Jet strikes on series of flat plat mounted on the periphery of wheel

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

P= ρaV(V – u)
Work done by the jet = Pn × U
W = ρaV(V – u)u

Efficiency of the work done of wheel h =Impulse of Jets | Mechanical Engineering SSC JE (Technical)
at ,Impulse of Jets | Mechanical Engineering SSC JE (Technical)

  •  Jet striking on a symmetrical stationary curved plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

Pn = ρaV2 (1 + cos q)
Force exerted by a jet in its direction of flow on a curved vane is always greater than that exerted on a flat plate.
Force Exerted By a jet on a Hinged Plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

  •  Force due to jet of water, normal to the plate
    Pn = ρaV2 sin (90º –θ) 
  • For equilibrium of plate

Impulse of Jets | Mechanical Engineering SSC JE (Technical)

The document Impulse of Jets | Mechanical Engineering SSC JE (Technical) is a part of the Mechanical Engineering Course Mechanical Engineering SSC JE (Technical).
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FAQs on Impulse of Jets - Mechanical Engineering SSC JE (Technical)

1. What is the impulse of a jet?
Ans. The impulse of a jet refers to the change in momentum of a fluid jet per unit time. It is the force exerted by the jet on a target or a surface, resulting in a change in momentum.
2. How is the impulse of a jet calculated?
Ans. The impulse of a jet can be calculated by multiplying the rate of flow of the fluid (mass per unit time) by the change in velocity of the fluid jet. Mathematically, it can be expressed as Impulse = Rate of Flow x Change in Velocity.
3. What factors affect the impulse of a jet?
Ans. Several factors can affect the impulse of a jet, including the velocity of the fluid jet, the density of the fluid, the area of the target surface, and the angle at which the jet strikes the surface. These factors play a significant role in determining the magnitude and direction of the impulse.
4. How does the impulse of a jet impact the target surface?
Ans. The impulse of a jet can cause a change in momentum of the target surface, leading to a force exerted on the surface. This force can result in various effects, such as the movement or displacement of the surface, deformation, or damage. The impact of the impulse depends on the magnitude and direction of the force exerted by the jet.
5. What are the applications of understanding the impulse of jets in mechanical engineering?
Ans. Understanding the impulse of jets is crucial in various mechanical engineering applications. It is used in designing and analyzing hydraulic systems, water jets, and propulsion systems. It is also important in the design of nozzles, pumps, and turbines. Additionally, it finds applications in industries such as aerospace, automotive, and manufacturing, where the control and impact of fluid jets are significant.
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