Pure bending refers to the state of bending in a beam in which bending moment is present but shear force is negligible over the length considered. The principal observations and conclusions from the theory of pure bending are given below.
Let s be the longitudinal stress produced by bending at a distance y from the neutral axis. Then (see below for expression):
From equilibrium and Hooke's law the standard flexure formula (result of simple bending) is obtained:
σ = (M y) / I
where σ is the bending stress at distance y from the neutral axis, M is the bending moment at the cross-section, and I is the second moment of area (moment of inertia) of the section about the neutral axis. The maximum bending stress occurs at the extreme fibre where |y| is maximum (denoted c), so σ_max = M c / I. The section modulus Z = I / c, therefore M = σ_max Z.
Consider a square section placed in two different orientations: (I) with sides horizontal and vertical, and (II) with a diagonal horizontal (so the diagonal is vertical). For a given extreme fibre stress, the section modulus depends on orientation. The following figures illustrate the two positions:
Calculated values show that arrangement (I) is 41.4% stronger than arrangement (II) for bending in the vertical plane shown. That is, the section modulus in (I) is larger by approximately 41.4% compared to (II).
Given a circular log of diameter D, find the rectangle of breadth b and depth d (d measured in the bending direction) that gives the maximum section modulus (hence maximum bending strength for given material).
The section modulus for a rectangle of breadth b and depth d about its neutral axis is Z = (b d^2) / 6 (for bending about the horizontal centroidal axis). For a given circular boundary the rectangle must fit inside the circle, so relationship between b and d follows from geometry (see).For maximum Z subject to b and d constrained by the circle, differentiation leads to the optimal ratio:
Hence the strongest rectangle that can be cut from a circle satisfies
b = d / √2
Geometrical and algebraic steps that lead to this result are shown in the following diagrams and expressions:
Therefore b = d / √2 gives the largest section modulus for a rectangular section inscribed in a circle of given diameter.
Problem statement (text preserved in content): Three beams have the same length, same allowable bending stress and are subjected to the same maximum bending moment. The cross section of the beams are a circle, a square and rectangle with depth twice the width. Find the ratio of the weights of the circular and rectangular beams with respect to the square beams.
Let the circular section be of diameter d.
Let the square section be of side x.
Let the rectangular section be of width b and depth 2b.
For equal bending moment under the same allowable stress, the section modulus must be equal for all three sections (M = σ Z and M, σ same for all). Therefore Z_circle = Z_square = Z_rectangle.
Using standard expressions for section modulus:
From these relations one obtains
Numerical relationships derived give d = 1.193 x and b = 0.6299 x.
Hence for the same bending strength under the same allowable stress, the rectangular section (depth twice width) is the lightest and the circular section is the heaviest.
A square-section beam carrying a vertical bending moment can have its section modulus increased slightly by trimming off triangular corners (shaded portions in the figure) oriented parallel to the neutral axis. The geometry of the parts to be cut and the resulting increase in section modulus are shown in the diagrams:
Key points:
A flitched beam is a composite beam formed by placing steel plates (flitches) on a timber beam and fastening them together so that they act compositely. The composite action increases bending strength and stiffness. The steel and wood share bending stresses according to their stiffnesses.
The modular ratio (ratio of moduli of elasticity) is used to convert steel parts into equivalent wood width when analysing as an equivalent wooden section. The modular ratio is defined as:
Case - 1: Flitches attached symmetrically at the sides.
Consider a timber beam of breadth b and depth d with two identical steel plates each of thickness t attached symmetrically to the vertical sides. Let M_r be the total moment of resistance of the composite section. Let M_w and M_s be the moments of resistance contributed by the wood and steel respectively under the same curvature.
The steel contribution can be treated by transforming steel into an equivalent width of wood using the modular ratio m. The equivalent wooden section then has width b + m(2t) and depth d. Therefore the composite section's moment of resistance equals that of a wooden member of breadth b + m(2t) and depth d. This rectangular section is called the equivalent wooden section.
Case - 2: Flitches attached symmetrically at the top and bottom.
When flitches are attached at top and bottom, the steel plates are placed furthest from the neutral axis; this increases the section modulus more effectively than side flitches for the same steel area. Therefore top-and-bottom flitching usually gives higher moment carrying capacity than side flitching (for the same quantity of steel).
For economy of material, a beam may be designed so that the extreme fibre stress is equal to the permissible stress at every section along its length. Such a beam is called a beam of uniform strength. Because bending moment varies along the span, the cross-section must vary accordingly. There are three common design approaches:
Let permissible bending stress be σ. For any section at distance x from a reference (for example a support), bending moment is M(x). For a rectangular section of constant depth d and width b(x), the section modulus is Z = b(x) d^2 / 6. Requiring σ = M(x) / Z gives the width at x:
Therefore
and the width at mid-span (or any particular x of interest) can be obtained similarly, see and
.
For constant width b, the required depth d(x) at a section with bending moment M(x) is obtained by equating M(x) = σ Z and using Z = b d(x)^2 / 6. Thus d(x) is proportional to √M(x). The detailed expressions and illustrative diagrams are shown below.
The theory of pure bending leads to the flexure formula which relates bending stress to bending moment and section geometry. Section modulus is the primary geometric property used in bending design. Practical measures-such as choosing optimal orientation, cutting optimal rectangular sections from logs, adding flitches, or designing beams of uniform strength-allow more efficient use of material. All designs must respect the assumptions of simple bending and remain within elastic limits for the theory to be applicable.
| 1. What are bending stresses in beams? | ![]() |
| 2. How do bending stresses affect the performance of beams? | ![]() |
| 3. What factors influence the magnitude of bending stresses in beams? | ![]() |
| 4. How can bending stresses in beams be calculated or analyzed? | ![]() |
| 5. What are some common techniques to reduce bending stresses in beams? | ![]() |