Moisture content of sludge is the percentage of water present in the wet sludge. In this chapter moisture content is expressed on a wet basis, i.e., as the percentage of the total (wet) mass that is water.
For simplicity in many engineering problems the mass (or volume) of solids is taken as a unit quantity. Let the mass of dry solids be 1 (unit mass). Let the initial moisture content be p1 (%) and the final moisture content after dewatering be p2 (%). Let the mass of water initially be x and finally be y.
The percent moisture on wet basis is
p1 = (mass of water / total mass) × 100 = (x / (1 + x)) × 100
Therefore, multiplying both sides by (1 + x):
100 x = p1 + p1 x
Rearranging gives
x (100 - p1) = p1
Hence
x = p1 / (100 - p1)
Similarly, for the final condition
y = p2 / (100 - p2)
These relations let you convert between moisture content (wet basis) and the mass of water per unit mass of dry solids. If the mass of solids is not unity but a known value Ms, multiply x and y by Ms to get actual masses of water.
Example application: If initial moisture p1 = 98% and final moisture p2 = 80%, the corresponding water masses per unit dry solids are
x = 98 / (100 - 98) = 98 / 2 = 49
y = 80 / (100 - 80) = 80 / 20 = 4
So water removed per unit dry solids = x - y = 45 units of mass.
When sewage of concentration Cs (mass per unit volume) and discharge Qs (volume per unit time) mixes with river water of concentration CR and discharge QR, the combined concentration C immediately downstream (assuming complete instantaneous mixing across the cross section) is found by mass balance:
C = (Cs Qs + CR QR) / (Qs + QR)
Here the numerator represents the total pollutant mass per unit time entering the mixing zone and the denominator is the total flow. This simple dilution formula is widely used to estimate initial pollutant concentrations after discharge.
Oxygen deficit at any time is the difference between saturation DO at the water temperature and the actual DO:
D = DOsat - DOactual
A plot of DO (or of deficit) with downstream distance (or time) typically shows a fall to a minimum (maximum deficit) followed by recovery, as illustrated conceptually below.
The Streeter-Phelps model describes the change in biochemical oxygen demand (BOD) and oxygen deficit with time downstream after a pollutant discharge. Two processes are modelled:
Let L(t) be the biodegradable BOD remaining at time t and L0 the initial biodegradable BOD at t = 0. First-order decay is assumed:
dL/dt = -kd L
Solving (separation of variables and integration):
L(t) = L0 e-kd t
The rate of change of oxygen deficit D(t) equals oxygen demand generated by deoxygenation minus oxygen supplied by reaeration:
dD/dt = kd L(t) - kr D(t)
To solve dD/dt + kr D = kd L0 e-kd t, use an integrating factor μ(t) = ekr t.
Multiply both sides by μ(t):
ekr t dD/dt + kr ekr t D = kd L0 e(kr - kd) t
Left-hand side is derivative:
d/dt [ekr t D] = kd L0 e(kr - kd) t
Integrate both sides from 0 to t:
ekr t D(t) - D(0) = kd L0 ∫0t e(kr - kd) τ dτ
Performing the integral (consider kr ≠ kd):
ekr t D(t) - D(0) = kd L0 [e(kr - kd) t - 1] / (kr - kd)
Therefore
D(t) = D(0) e-kr t + (kd L0 / (kr - kd)) [e-kd t - e-kr t]
In this expression:
The oxygen deficit reaches a maximum at time tc where dD/dt = 0. Using the differential equation dD/dt = kd L(t) - kr D(t), set the derivative to zero to get the condition for the critical time.
For the common case where the initial oxygen deficit is zero (D(0) = 0), the critical time simplifies to
tc = (1 / (kr - kd)) ln (kr / kd)
Substituting t = tc into the D(t) expression yields the maximum deficit Dmax. For D(0) ≠ 0 the formula for tc and Dmax becomes more complex but follows from the same procedure of setting dD/dt = 0 and solving for t.
Where the symbols appearing in the expression are as defined above.
| 1. What are the effluent discharge standards for sludge disposal in civil engineering? | ![]() |
| 2. What factors are considered in determining the effluent discharge standards for sludge disposal? | ![]() |
| 3. How are the effluent discharge standards monitored and enforced in civil engineering projects? | ![]() |
| 4. Are there any international guidelines or standards for sludge disposal effluent discharge in civil engineering? | ![]() |
| 5. What are the potential environmental impacts of inadequate sludge disposal effluent discharge in civil engineering? | ![]() |