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Test: Belt Construction II & V Belts - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Belt Construction II & V Belts

Test: Belt Construction II & V Belts for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Belt Construction II & V Belts questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Belt Construction II & V Belts MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Belt Construction II & V Belts below.
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Test: Belt Construction II & V Belts - Question 1

 Calculate the angle of wrap if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.

Detailed Solution for Test: Belt Construction II & V Belts - Question 1

Explanation: ὰ=180 – 2sin¯¹(D-d/2C).

Test: Belt Construction II & V Belts - Question 2

Calculate the arc of contact if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.

Detailed Solution for Test: Belt Construction II & V Belts - Question 2

Explanation: ὰ=180 – 2sin¯¹(D-d/2C). Factor=1+ (1.04-1)(180-174.8)/(180-170).

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Test: Belt Construction II & V Belts - Question 3

Calculate the belt length if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.

Detailed Solution for Test: Belt Construction II & V Belts - Question 3

Explanation: L=2C + π(D+d)/2 + (D-d)²/4C.

Test: Belt Construction II & V Belts - Question 4

 Crowns are never mounted on the pulley.

Detailed Solution for Test: Belt Construction II & V Belts - Question 4

Explanation: Crowns are used to avoid slip in case of misalignment or non-parallelism.

Test: Belt Construction II & V Belts - Question 5

In a cast iron pulley minor axis is generally kept in the plane of rotation.

Detailed Solution for Test: Belt Construction II & V Belts - Question 5

Explanation: Keeping minor axis in plane of rotation increases the cross section.

Test: Belt Construction II & V Belts - Question 6

The number of V belts required for a given application are given by (ignoring correction factor for arc of contact and belt length) Transmitted power/kW rating of single belt x Industrial Service Factor.

Detailed Solution for Test: Belt Construction II & V Belts - Question 6

Explanation: It is given by Transmitted power x Industrial Service Factor /kW rating of single belt.

Test: Belt Construction II & V Belts - Question 7

The pitch diameter of bigger pulley D in terms of small diameter d is given by

Detailed Solution for Test: Belt Construction II & V Belts - Question 7

Explanation: Product of diameter and speed of pulley is constant.

Test: Belt Construction II & V Belts - Question 8

 If maximum tension in the belt is 900N and allowable belt load is 500N. Calculate the number of belts required to transmit power.

Detailed Solution for Test: Belt Construction II & V Belts - Question 8

Explanation: No of belts=900/500.

Test: Belt Construction II & V Belts - Question 9

 The belt tension is maximum when velocity of belt is 0.

Detailed Solution for Test: Belt Construction II & V Belts - Question 9

Explanation: P₁-mv²/P₂-mv²=e^(fa/sinθ/2). Hence belt tension is maximum when v=0.

Test: Belt Construction II & V Belts - Question 10

If belt tension in the two sides is 730N and 140N and belt is moving with a velocity of 10m/s, calculate the power transmitted.

Detailed Solution for Test: Belt Construction II & V Belts - Question 10

Explanation: Power=(P₁-P₂)xv.

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