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Test: Compound Cylinder & Gaskets - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Compound Cylinder & Gaskets

Test: Compound Cylinder & Gaskets for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Compound Cylinder & Gaskets questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Compound Cylinder & Gaskets MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Compound Cylinder & Gaskets below.
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Test: Compound Cylinder & Gaskets - Question 1

 Autofrettage is beneficial for the high pressure cylinder.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 1

Explanation: It increases pressure capacity of the cylinder and reduces compressive stresses.

Test: Compound Cylinder & Gaskets - Question 2

 Autogreggate is a process of ___ stressing the cylinder.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 2

Explanation: It is a pre stressing phenomenon to improve pressure capacity.

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Test: Compound Cylinder & Gaskets - Question 3

Can we pre-stress the cylinder by subjecting cylindrical portion near inner diameter in plastic range and outer diameter is still in the elastic range.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 3

Explanation: On releasing the pressure, outer portion contracts exerting pressure on the inner portion which has undergone permanent deformation. This induces residual compressive stresses at the inner surface.

Test: Compound Cylinder & Gaskets - Question 4

A compound cylinder consists of

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 4

Explanation: Inner diameter of jacket increase and outer diameter of cylinder decreases when the jacket is heated.

Test: Compound Cylinder & Gaskets - Question 5

A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 5

Explanation: σ=P[D₃²+D₂²]/[D₃²-D₂²] where D₂=40mm and D₃=60mm.

Test: Compound Cylinder & Gaskets - Question 6

 A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the interference [E=210kN/mm²].

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 6

Explanation: Δ=PD₂[2D₂²(D₃²-D₁²)] / Ex[(D₃²-D₂²)(D₂²-D₁²)].

Test: Compound Cylinder & Gaskets - Question 7

A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the radial stresses due to shrink shift in jacket.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 7

Explanation: σ(r)=-PD₂²[D₃²/4r² – 1]/ [D₃²-D₂²].

Test: Compound Cylinder & Gaskets - Question 8

A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the tangential stresses due to shrink shift in jacket.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 8

Explanation: σ(t)=+PD₂²[D₃²/4r² – 1]/ [D₃²-D₂²].

Test: Compound Cylinder & Gaskets - Question 9

 A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the radial stress due to shrink shift in inner tube.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 9

Explanation: σ(r)= σ(r)=-PD₂²[1-D₁²/4r² ]/ [D₂²-D₁²].

Test: Compound Cylinder & Gaskets - Question 10

A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the tangential stress due to shrink shift in inner tube.

Detailed Solution for Test: Compound Cylinder & Gaskets - Question 10

Explanation: σ(r)= σ(r)=-PD₂²[1+D₁²/4r² ]/ [D₂²-D₁²].

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