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Algebraic Expressions And Identities- 2 - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Algebraic Expressions And Identities- 2 (15 Questions)

You can prepare effectively for Class 8 Mathematics (Maths) Class 8 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Algebraic Expressions And Identities- 2". These 15 questions have been designed by the experts with the latest curriculum of Class 8 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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Test: Algebraic Expressions And Identities- 2 - Question 1

An algebraic expression that contains only one term is called:

Detailed Solution: Question 1

An algebraic expression that contains only one term is called a:

A monomial is a single term expression in algebra.

  • For example, 2x is a monomial.

Test: Algebraic Expressions And Identities- 2 - Question 2

5x+6y is a:

Detailed Solution: Question 2

The expression containing two terms is called a binomial. In this case:

  • 5x is the first term.
  • 6y is the second term.

This makes the entire expression a binomial.

Test: Algebraic Expressions And Identities- 2 - Question 3

If we add, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and –3xz + 5x – 2xy, then the answer is:

Detailed Solution: Question 3

Given, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and –3xz + 5x – 2xy.
If we add the three expressions, then we need to combine the like terms together.
(7xy – 2xy) + (5yz + 4yz) – 3zx + 9zx – 3xz – 4y + 5x
= 5xy + 9yz + 3zx + 5x – 4y

Test: Algebraic Expressions And Identities- 2 - Question 4

If we subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3, then the answer is:

  • 8a + 2ab + 2b + 15
  • 8a + 2ab + 2b – 15
  • 8a – 2ab + 2b – 15
  • 8a – 2ab – 2b – 15

Detailed Solution: Question 4

(12a – 9ab + 5b – 3) minus (4a – 7ab + 3b + 12)
= 12a – 9ab + 5b – 3 – 4a + 7ab – 3b – 12
= (12 – 4)a – (9 – 7)ab + (5 – 3)b – 3 – 12
= 8a – 2ab + 2b – 15

Test: Algebraic Expressions And Identities- 2 - Question 5

If we multiply 5x and (– 4xyz), then we get:

Detailed Solution: Question 5

(5x)* (-4xyz)

= 5 * x * (-4) * x * y * z

= -20x1+1yz

= -20x2yz

Test: Algebraic Expressions And Identities- 2 - Question 6

The product of 3xy2z and 4x is:

Detailed Solution: Question 6

The product of 3xy2z and 4x is:
⇒ (3xy2z) (4x)
⇒ 3.x.y2.z.4.x
⇒ 12x2y2z

Test: Algebraic Expressions And Identities- 2 - Question 7

Multiplication of pq+qr+rp and ‘zero’ is

Detailed Solution: Question 7

- When multiplying any expression by zero, the result is always zero.
- Thus, the product of pq+qr+rp and ‘zero’ is 0.

Answer: D: 0

Test: Algebraic Expressions And Identities- 2 - Question 8

Multiplication of ‘ab’ and ‘a-b’ is

Detailed Solution: Question 8

To find the multiplication of 'ab' and 'a - b', use the distributive property.
(ab)(a−b)
This means you multiply 'ab' by both 'a' and '-b'
So, you compute:

  • ab * a = a2b
  • ab * -b = -ab2

Combine these results: a2b - ab2
Hence, the correct answer is option D: a2b - ab2

Test: Algebraic Expressions And Identities- 2 - Question 9

What is the type of expression for 564xy?

Detailed Solution: Question 9

The expression 564xy is a monomial because it consists of a single term, which includes variables and coefficients combined through multiplication.

  • Each variable (x and y) contributes to the same term.
  • There are no addition or subtraction operations involved.
  • This fits the definition of a monomial.

Test: Algebraic Expressions And Identities- 2 - Question 10

Find the area of a square with side 5x²y.

Detailed Solution: Question 10

The area of a square is calculated by squaring the length of its side. Given the side length is 5x2y, the area is:

  • (5x2y)2 = 25x4y2.

Thus, the correct answer is option B.

Test: Algebraic Expressions And Identities- 2 - Question 11

Calculate the area of a rectangle whose length and breadths are given as 3x²y m and 5xy² m respectively.

Detailed Solution: Question 11

The area of a rectangle can be calculated using the formula:

  • Area of rectangle = Length × Breadth

For this specific rectangle, the lengths are:

  • Length = 3x2y
  • Breadth = 5xy2

Substituting these values into the formula gives:

  • Area = (3x2y) × (5xy2)

Now, let's perform the multiplication:

  • Area = 15x3y3

Thus, the area of the rectangle is 15x3y3.

Test: Algebraic Expressions And Identities- 2 - Question 12

Simplify the expression (x + y + z)(x + y – z).

Detailed Solution: Question 12

To simplify (x + y + z)(x + y - z), notice that the expression is of the form (A + z)(A - z) where A = (x + y). This product equals A² - z².

Now, compute A²

A² = (x + y)² = x² + 2xy + y²

Subtract z²: x² + 2xy + y² - z²

This matches option (a).

Answer: a) x² + y² – z² + 2xy

Test: Algebraic Expressions And Identities- 2 - Question 13

Simplify the expression x²(x – 3y²) – xy(y² – 2xy) – x(y³ – 5x²).

Detailed Solution: Question 13

To simplify the expression x2(x - 3y2) - xy(y2 - 2xy) - x(y3 - 5x2), follow these steps:

  1. Expand each term separately:
    • x2(x - 3y2) = x3 - 3x2y2
    • -xy(y2 - 2xy) = -xy3 + 2x2y2
    • -x(y3 - 5x2) = -xy3 + 5x3
  2. Combine all expanded terms:

    x3 - 3x2y2 - xy3 + 2x2y2 - xy3 + 5x3

  3. Combine like terms:
    • x3 + 5x3 = 6x3
    • -3x2y2 + 2x2y2 = -x2y2
    • -xy3 - xy3 = -2xy3

The simplified expression is:

6x3 - x2y2 - 2xy3

Thus, the correct answer is option A.

Test: Algebraic Expressions And Identities- 2 - Question 14

Subtract (7x + 2) from (-6x + 8).

Detailed Solution: Question 14

To solve the problem:

We need to subtract (7x + 2) from (-6x + 8).

This can be rewritten as:

  • (-6x + 8)(7x + 2)

Now, distribute the negative sign:

  • -6x + 87x2

Next, combine like terms:

  • Combine the x terms: -6x - 7x = -13x
  • Combine the constant terms: 8 - 2 = 6

The final result is:

-13x + 6

Test: Algebraic Expressions And Identities- 2 - Question 15

Subtract 3xy + 5yz – 7xz + 1 from -4xy + 2yz – 2xz + 5xyz + 1.

Detailed Solution: Question 15

We need to subtract (3xy + 5yz – 7xz + 1) from (-4xy + 2yz – 2xz + 5xyz + 1).

Step 1: Write the subtraction expression:

(-4xy + 2yz – 2xz + 5xyz + 1) - (3xy + 5yz – 7xz + 1)

Step 2: Distribute the minus sign across the second set of terms:

= -4xy + 2yz – 2xz + 5xyz + 1 - 3xy - 5yz + 7xz - 1

Step 3: Combine like terms:

  • For xy terms: -4xy - 3xy = -7xy
  • For yz terms: 2yz - 5yz = -3yz
  • For xz terms: -2xz + 7xz = 5xz
  • For xyz term: 5xyz (no like term)
  • For constants: 1 - 1 = 0

Step 4: Write the final expression:

5xz + 5xyz - 7xy - 3yz

Thus, the correct answer is:

a) 5xz + 5xyz - 7xy - 3yz

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