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MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced


MCQ Practice Test & Solutions: Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced (8 Questions)

You can prepare effectively for JEE Crack JEE with 35 Years of Previous Year Solved Papers with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced". These 8 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 8

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*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 1

There exists a triangle ABC satisfying the conditions

Detailed Solution: Question 1

We have

(a) b sin A = a ⇒ a sin B = a
⇒ sin B = 1  ⇒ B = π/2
Since A < π/2, the ΔABC is possible.
(b) b sin A > a ⇒ a sin B > a ⇒ sin B > 1
Which is impossible. Hence the πossibility (b) is ruled out.
Similarly (c) can be shown to be impossible.
(d) b sin A < a ⇒ a sin B < a ⇒ sin B < 1 so value of ∠B exists.
Now, b > a ⇒ B > A.  Since A < π/2
The ΔABC is possible when B > or < π/2.
(e) Since b = a, we have B = A. But A > π/2
∴ B > π/2. But this is not possible for any triangle

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 2

In a triangle, the lengths of the two larger sides are 10 and 9, respectively. If the angles are in A P. Then the length of the third side can be

Detailed Solution: Question 2

Since the angles of triangle are in A.P., Let ∠A = x – d,  ∠B = x,  ∠C = x + d
Then by ∠ sum property of triangle, we have ∠A +∠ B + ∠C = 180°
⇒ x  – d + x + x + d = 180°
⇒ 3x = 180° ⇒ x = 60°
∴ ∠B = 60°



Given that a = 10,  b = 9 are the longer sides
 (both the values are less than 9 and 10),
 both are possible.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 3

If in a triangle PQR, sin P, sin Q, sin R are in A.P., then

Detailed Solution: Question 3

In ΔPQR let d1, d2, d3 be the altitudes on QR, RP and PQ respectively.



⇒ 

⇒ d1, d2, d3  are  in H.P. (As given that sin P,  sin Q,  sin R  are in A.P.)

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 4

Let A0A1A2A3A4A5 be a regular hexagon inscribed in a circle of unit radius. Then the product of the lengths of the line segments A0A1,A0A2 and A0A4 is

Detailed Solution: Question 4

Given that A0A1A2A3A4A5 is a regular hexagon inscribed in a circle of radius 1.


∴ A0A1 = 1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A0 
∠A0A1A2 = 60°  +  60° = 120°
In ΔA0A1A2, using cosine law we get


∴ (c) is the correct option.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 5

In ΔABC, internal angle bisector of ∠A meets side BC in D. DE ⊥ AD meets AC in E and AB in F. Then

Detailed Solution: Question 5

By simple geometry in ΔAFE, AF = AE
∴ ΔAFE is  an isosceles Δ.
Now Ar (ΔABC) = Ar (ΔABD) + Ar (ΔADC)




*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 6

Let ABC be a triangle such that  and let a, b and c denote the lengths of the sides opposite to A, B and C respectively. The value(s) of x for which a = x2 + x + 1, b = x2 – 1 and c = 2x + 1 is (are)

Detailed Solution: Question 6

Given that a = x2 + x + 1, b = x2 – 1, c = 2x+ 1 and ∠C = π/6





Now for x = –1and 1, b = 0 which is not possible
Also fo which is not possible

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 7

In a triangle PQR, P is the largest angle and cos p = 1/3. Further the incircle of the triangle touches the sides PQ, QR and RP at N, L and M respectively, such that the lengths of PN, QL and RM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is (are)

Detailed Solution: Question 7

Let PN = x, QL = x + 2, RM = x + 4 where x is an even integer.


Then PM = PN = x, QN = QL = x + 2 and RL = RM = x + 4
So that PQ = 2x + 2, QR = 2x + 6, PR = 2x + 4

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Properties of Triangle | JEE Advanced - Question 8

In a triangle XYZ, let x, y, z be the lengths of sides opposite to the angles X,Y, Z, respectively, and 2s = x + y + z.

 and area of incircle of the triangle 

Detailed Solution: Question 8






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