SNAP Past Year Papers - 2013 - CAT MCQ

Dinesh can do the work in 15 days and Harish can do it in 12 days. Let Subodh can do the work in ‘x’ days. Since the work completes in 4 days, we have

Hence Subodh can do the work in 10 
days. 

Here Males in the village = 1100. Since 3% males are not literate, so the number of males who are literate = 97% of 1100 = 1067.  

Now overall literacy rate of the village = 95% of 2000 = 1900.  

So, number of literate females = 1900 – 1067 = 833. 

Hence required %age 

Since Ravi’s 18 day’s salary = Ajit’s 12 day’s salary 

⇒ Ravi’s 1 day salary = Ajit’s 2/3 day salary. Let Ajit’s 1 day salary = Rs 99, so Ravi’s 1 day salary = Rs 
66. The total amount = 99 × 12 = Rs 1188. 

The total one day salary of Ajit & Ravi = 99 + 66 = Rs 165.  

Hence the required number of days = 1188/165 = 7.2 days .

 Also 25% of 40 = 10 and 50% of 10 = 5. So the required number = 10 + 5 = 15. Hence the number to be added in 9 to make it 15 is 6. 

Total age of 25 teachers 10 years ago = 45 × 25 = 1125 years.

As one teacher was retired 4 years ago, total age of all teachers 4 years ago  = 1125 + 150 – 58 = 1217 years.

After one year, one more teacher was added with age 54 years, so the total age of all teachers 3 years ago = 1217 + 24 + 54 = 1295 years.

Now the present age of all teachers = 1295 + 75 = 1370 years. 

Hence average age of all teachers =   

Let the total work is 60 units. X can complete the work 15 days, so he can do 4 units in one day. Similarly Y can do 3 units in one day. Now in the first 5 days, X will do 5 × 4 = 20 units and in next three days x and Y will work 7 × 3 = 21 units.

The total work done till now is 20 + 21 = 41 units. The remaining work is 19 units, which will be done by Y alone and he will take 19/3 = 6.3 days .

Let x = 2.093 and y = 0.089. So we have 

We have x + y + 50 = 180⁰ ⇒ x + y = 130⁰.  

BO and CO are the external bisectors of angle B and angle C. 

From the given information we can say that the number of executives is 40 and the number of non executives is 20. But we cannot find the average salary of non executives as we do not know the average salary of executives. So answer is 4^th option.

The syrup in pot A is 3/10 and in pot B is 5/7. In the required mixture the syrup should be 2/5. Using Alligation we have 

⇒ The required ratio is 22: 7. 

The total distance covered by the truck in three days = 12 × 40 + 10 × 50 + 360  = 480 + 500 +360 = 1340. 
 The total time it travelled in three days = 12 + 10 + 8 = 30 hours. 

So the average speed  

Let the second number is x. We know that L.C.F. × H.C.F = Product of numbers. ⇒ 8 × 96 = 32 × x ⇒ x = 24.

Let the ages of A and B are 3x and 4x. Acc. to the question we have, 4x = 3x – 5 + 10 ⇒ x = 5. So the age of B = 4 × 5 = 20 years. 

The speed of the vehicle = 54 km/hr or 15 m/sec. The circumference of front wheel is 3.5 meters and that of the back wheel is 3 meters. In order to make a whole number of turns, the vehicle should move = LCM (3.5, 3) = 21m. Time taken by the vehicle to move 21 meters is 21/15 = 1.4 seconds. 

Let q is 100, then p is 81. The required %age 

The cost of fencing is Rs 2700 at the rate of Rs 30/m. So the perimeter of the plot is 2700/30 = 90m. Let breadth of plot is x, then length = x + 15.

Perimeter of plot = 90 ⇒ 2( x+ 15 +x) = 90 ⇒ 2x + 15 = 45 ⇒ x = 15. So the length = 15 + 15 = 30 m.  

Let the total number of students is 100. As 20 % opted for neither History nor Geography, so the total students who opted at least one of the subjects is 80.

We have n(H) = 70, n(G) = 45, n(H∪G) = 80

Now n(H∪G) = n(H) + n(G) - n(H∩G)

⇒ 80 = 70 + 45 - n(H∩G)

⇒ n(H∩G) = 35.

Hence 35% of the class opted for both the subjects. 

We have  

Now 19 – x + x + 11 – x = 21

⇒ x = 9

Or

We have n(C) = 19, n(S) = 11, n(S∪C) = 21

Since the no. is increased & decreased by same %age, So the net change is   decrease. 

Total no. of boys = 22 & total girls = 20 The no. of ways in which a girl and a boy will be appointed a monitor = ²²C₁× ²⁰C₁ = 22 × 20 = 440 

Let the speed of Arvind is x km/hr and speed of Mohan is y km/hr. When they travel in opposite direction  

& when they travel in same direction, we have  (x-y) × 2 = 20

⇒ x-y =10 ...................(2)

Adding 1 & 2 we get 2x = 50

⇒ x = 25 km/hr

∴ Speed of Arvind is 25 km/hr 

Here A = { 1,2,3,4,5,6}. Since A has three even & there odd numbers, the subsets of A with one element even & one add can be formed in ³C₁׳C₁ = 9 ways.

The net SP of Soap after discount = 0.85 × 30 = Rs 25.5.

Since he is giving a sachet of Shampoo fee, net price he his taking from customer = 25.5 – 1.5 = Rs 24.

Now the profit made = 20% We have 1.2 CP = SP  

This is the basic property of logarithms that  Log(m × n) = log m + log n.

Let the numbers are x & y

We have x + y =15 ...................(1) & xy = 30 ....................(2)

The total amount paid by Amar, Akbar & Anthony = 26.85 + 42.75 + 53 = Rs 122.6

Since they had decided to pay the bill in 3:4:5, their actual payments should have been 

Since Amar paid Rs., 3.8 less than what he should pay, so he will give 42.75 – 40.81 = Rs 1.95. to Akbar & 53 – 51 = Rs 2. to Anthony.

Hence 3rd option is answer. 

Let distance between Ayodhya and Chitrakoot = xkm
Let distance covered by Bajrang when Angad covered 100km = y = km
In ΔSTR Right Angled at T & Angle TSR = 30⁰

As we know that speed & Distance. Hence distance covered by Angad & Bajrang is & Speed and their speed is constant hence. 

x² – 250x – 15000 = 0
(x – 300) (x + 50) = 0

Hence Distance of chitrakoot & Ayodhya = x = 300km. 

We have 

The LCM of 12, 16, 18 is 144.

∴ the Smallest number which when divided by 12,16,18 gives remainder 7 in each case is 144 + 7 = 151