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JEE Exam  >  JEE Tests  >  Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - JEE MCQ

Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - JEE MCQ


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15 Questions MCQ Test - Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 1
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Potassium manganate (K2MnO4) is formed when

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 2
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The aqueous solutions of the following salts will be coloured in the case of

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Aqueous solution of Co(NO3)2 and CrCl3 in which Co2+ (d7) and Cr3+ (d3) contains incompletely filled d-orbitals are coloured.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 3
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Among the following ions which one has the highest paramagnetism?

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Highest parmagnetic character will be shown by the ion having maximum number of unpaired electrons in their d-subshells.
25Cr3+ has 3 unpaired electrons ; 26Fe2+ has 4 unpaired electrons
29Cu2+ has 1 unpaired electrons ; 30Zn2+ has no unpaired electrons
So (a), (b) & (c) show paramagnetism. Out of which (b) has the highest paramagnetism.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 4
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Which of the following alloys contains(s) Cu and Zn?
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Brass : Cu (60-80%), Zn (40-20%); Gun Metal : Cu (87%), Sn (10%), Zn (3%).

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 5
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In nitroprusside ion the iron and NO exist as FeII and NO+ rather than FeIII and NO. These forms can be differentiated by
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The magnetic moment (μ) of a species is related to its number of unpaired electrons (n) in form of following expressions.

The number of unpaired electrons in the given pairs are as follows:


The given combinations differ in the number of unpaired electrons. Hence these can be differentiated by the measurement on the solid state magnetic moment of nitroprusside ion.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 6
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Addition of high proportions of manganese makes steel useful in making rails of railroads, because manganese
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Mn makes steel harder and increases its elasticity and tensile strength. Further Mn acts as deoxidiser.
MnO reacts with S present in cast iron, gets oxidised and then combine to form slag.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 7
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If the bond length of CO bond in carbon monoxide is 1.128Å, then what is the value of CO bond length in Fe(CO)5?
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In Fe(CO)5​ there exists a synergic bond between Fe and CO. Due to synergic bond formation between metal and CO, the bond order of CO decreases.

As bond order decreases the Bond length increases.Here the only option having greater bond length than 1.128A0 is option A 1.158A0.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 8
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The compound(s) that exhibit(s) geometrical isomerism is (are)
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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 9
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Reduction of the metal centre in aqueous permanganate ion involves
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In acidic medium

Change in oxidation state of Mn = 7 – 2 = 5

Thus electrons lost = 5
In neutral medium

Change in oxidation state of Mn = 7 – 4 = 3
∴ Electrons lost = 3

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 10
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The equilibrium
Detailed Solution for Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 10

Cu2+ ions will react with CN– and SCN– forming [Cu(CN)4]3– and [Cu(SCN)4]3– leading the reaction in the backward direction.

Cu2+ also combines with CuCl2 which reacts with Cu to produce CuCl pushing the reaction in the backward direction.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 11
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For the given aqueous reactions, which of the statement (s) is (are) true?
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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 12
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The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is(are)
Detailed Solution for Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 12

Th e pair of complex ion s [Co(NH3)4Cl2]+ and [Pt(NH3)2(H2O)Cl]+ show geometrical isomerism.
The pair of complexes [Pt(NH3)3(NO3)]Cl and [Pt(NH3)3Cl]Br show ionisation isomerism. The other pairs given do not have same type of isomerism.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 13
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The pair (s) of reagents that yield paramagnetic species is/are
Detailed Solution for Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 13

Na + NH3 (excess) → Dilute solution of Na in liq.
NH3 → Paramagnetic
K + O2 (excess) → KO2 (O2– is paramagnetic)
Cu + HNO3 (dil.) → Cu(NO3)2 + NO (NO is paramagnetic) 2-Ethylanthraquinol + O2 →
2-Ethylanthraquinone + H2O2
(H2O2 is diamagnetic)

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 14
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The correct statement(s) about Cr2+ and Mn3+ is(are) [Atomic numbers of Cr = 24 and Mn = 25] 
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Cr2+ is a reducing agent and Mn3+ is an oxidizing agent and both have electronic configuration d4.

Above E° values explains reducing nature of Cr2+ and oxidizing behaviour of Mn3+.

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Test: MCQs (One or More Correct Option): The d- and f-Block Elements & Coordination Compounds | JEE Advanced - Question 15
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Fe3+ is reduced to Fe2+ by using
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