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NEET Exam  >  NEET Tests  >  31 Year NEET Previous Year Questions: Waves - 1 - NEET MCQ

31 Year NEET Previous Year Questions: Waves - 1 - NEET MCQ


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11 Questions MCQ Test - 31 Year NEET Previous Year Questions: Waves - 1

31 Year NEET Previous Year Questions: Waves - 1 for NEET 2024 is part of NEET preparation. The 31 Year NEET Previous Year Questions: Waves - 1 questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Waves - 1 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Waves - 1 below.
Solutions of 31 Year NEET Previous Year Questions: Waves - 1 questions in English are available as part of our course for NEET & 31 Year NEET Previous Year Questions: Waves - 1 solutions in Hindi for NEET course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt 31 Year NEET Previous Year Questions: Waves - 1 | 11 questions in 20 minutes | Mock test for NEET preparation | Free important questions MCQ to study for NEET Exam | Download free PDF with solutions
31 Year NEET Previous Year Questions: Waves - 1 - Question 1
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Two waves are represented by the equations y1 = a sin (ωt + kx + 0.57) m and y2 = a cos (ωt + kx) m, where x is in meter and t in sec. The phase difference between them is [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 1

Here, y1 = a sin (ωt + kx + 0.57)

and    y2 = a cos (ωt + kx)

Phase difference,  

= 1.57 – 0.57
= 1 radian

31 Year NEET Previous Year Questions: Waves - 1 - Question 2
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Sound waves travel at 350 m/s through a warm air and at 3500 m/s through brass. The wavelength of a 700 Hz acoustic wave as it enters brass from warm air [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 2

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31 Year NEET Previous Year Questions: Waves - 1 - Question 3
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Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be [2011M]

Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 3

For fundamental mode,

Taking logarithm on both sides, we get

Differentiating both sides, we get

(as  and μ are constants)

Here df = 6            

f = 600 Hz

31 Year NEET Previous Year Questions: Waves - 1 - Question 4
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When a string is divided into three segments of length l1, l2, and l3  the fundamental frequencies of these three segments are v1, v2 and v3 respectively. The original fundamental frequency (v) of the string is [2012]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 4

Answer :- c

Solution :- Let l be the length of the string

Frequency fundamental is given by (v) = 1/2l(T/u)^½

V is inversely proportional to the l

Here, l1 = k/v1 ; l2 = k/v2; l3 = k/v3; l =k/v

But l = l1 + l2 + l3 

1/v = 1/v1 + 1/v2 + 1/v3 

31 Year NEET Previous Year Questions: Waves - 1 - Question 5
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Two sources of sound placed close to each other are emitting progressive waves given by y1 = 4 sin 600πt and y2 = 5 sin 608πt. An observer located near these two sources of sound will hear :[2012]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 5

2πf1 = 600π
f1 = 300 ... (1)
2πf2 = 608π
f2 = 304 ...(2)
|f1 – f2| = 4 beats

where A1, A2 are amplitudes of given two sound wave.

31 Year NEET Previous Year Questions: Waves - 1 - Question 6
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A train moving at a speed of 220 ms–1 towards a stationary object, emits a sound of frequency 1000 Hz. Some of the sound reaching the object gets reflected back to the train as echo. The frequency of the echo as detected by the driver of the train is : [2012M] (speed of sound in air is 330 ms–1)
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 6

Frequency of the echo detected by the driver of the train is (According to Doppler effect in sound)

where f = original frequency of source of sound f' = Apparent frequency of source because of the relative motion between source and observer.

31 Year NEET Previous Year Questions: Waves - 1 - Question 7
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If we study the vibration of a pipe open at both ends, then which of the following statements is not true ? [NEET 2013]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 7

Pressure change will be minimum at both ends. In fact, pressure variation is maximum at /2 because the displacement node is pressure antinode.

31 Year NEET Previous Year Questions: Waves - 1 - Question 8
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A source of unknown frequency gives 4 beats/s, when sounded with a source of known frequency 250 Hz. The second harmonic of the source of unknown frequency gives five beats per second, when sounded with a source of frequency 513 Hz. The unknown frequency is [NEET 2013]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 8

When sounded with a source of known frequency fundamental frequency = 250 ± 4 Hz = 254 Hz or 246 Hz
2nd harmonic if unknown frequency (suppose) 254 Hz = 2 × 254 = 508 Hz
As it gives 5 beats
∴  508 + 5 = 513 Hz
Hence, unknown frequency is 254 Hz

31 Year NEET Previous Year Questions: Waves - 1 - Question 9
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A wave travelling in the +ve x-direction having displacement along y-direction as 1m, wavelen gth 2πm and frequency  Hz isrepresented by [NEET 2013]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 9

As Y = A sin (ωt – kx + φ)


31 Year NEET Previous Year Questions: Waves - 1 - Question 10
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The length of the wire between two ends of a sonometer is 100 cm. What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio of 1 : 3 : 5?              [NEET Kar. 2013]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 10

Answer :- a

Solution :- Fundamental frequency (v) = 1/L

As the fundamental frequencies are in the ratio of 1:3:5,

L1 : L2 : L3 = 1/1 : 1/3 : 1/5  => 15 : 5 : 3

Let x be the common factor , then

15x + 5x + 3x = L = 100

23x = 100 

=> x = 100/23

L1 = 15*100/23 = 1500/23

L2 = 5*100/23 = 500/23

L3 = 3*100/23 = 300/23

The bridge should be placed from A at (1500/23 , 2000/23)

31 Year NEET Previous Year Questions: Waves - 1 - Question 11
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Two sources P and Q produce notes of frequency 660 Hz each. A listener moves from P to Q with a speed of 1 ms–1. If the speed of sound is 330 m/s, then the number of beats heard by the listener per second will be [NEET Kar. 2013]
Detailed Solution for 31 Year NEET Previous Year Questions: Waves - 1 - Question 11

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